Calculate the average travel time for each distance, and then use the results to calculate. A 6-column table with 3 rows in the second, third, and fifth columns and 1 row in the other columns. The first column labeled Number of Washers has entry 1 washer mass = 4. 9 grams. The second column labeled Trial has entries trial number 1, trial number 2, trial number 3. The third and fourth columns labeled Time to travel 0. 25 meters t subscript 1 (seconds) have entries in the third column 2. 24, 2. 21, 2. 23 and average in the fourth column. The fifth and sixth columns labeled time to travel 0. 5 meters t subscript 2 (seconds) have entries in the fifth column 3. 16, 3. 08, 03. 15 and in the sixth column average. The average time that it takes for the car to travel the first 0. 25m is s. The average time to travel just between 0. 25 m and 0. 50 m is s. Given the time taken to travel the second 0. 25 m section, the velocity would be m/s.

Answers

Answer 1

The average travel time is simply the mean travel time between the given points

The average time that it takes for the car to travel the first 0.25m is 2.23s. The average time to travel just between 0.25m and 0.50m is 0.9s. Given the time taken to travel the second 0.25 m section, the velocity would be 0.28m/s.

(a) The average time to travel the first 0.25m

The time travel in the first 0.25m are: 2.24s, 2.21s and 2.23s.

So, the average time to travel is:

[tex]Time = \frac{2.24s + 2.21s + 2.23s}{3}[/tex]

[tex]Time = \frac{6.68s}{3}[/tex]

[tex]Time = 2.23s[/tex]

(b) The average time to travel just between 0.25m and 0.50m

The time travel in the 0.50m are: 3.16s, 3.08s and 3.15s.

So, the average time to travel this distance is:

[tex]Time = \frac{3.16s + 3.08s + 3.15s}{3}[/tex]

[tex]Time = \frac{9.39s}{3}[/tex]

[tex]Time = 3.13s[/tex]

The average time to travel between both distance is the difference between the average time of each distance.

So, we have:

[tex]Average = 3.13s - 2.23s[/tex]

[tex]Average = 0.9s[/tex]

(c) The velocity in the second 0.25m section

The distance and time are:

[tex]Distance = 0.25m[/tex]

[tex]Time = 0.9s[/tex]

So, the velocity is:

[tex]Velocity = \frac{Distance}{Time}[/tex]

This gives

[tex]Velocity = \frac{0.25m}{0.9s}[/tex]

[tex]Velocity = 0.28m/s[/tex]

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Calculate The Average Travel Time For Each Distance, And Then Use The Results To Calculate. A 6-column

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

When James is twice as old as John, the difference in their ages will be John's age: 10. That is 5 years from now, so John's age now is 10 -5 = 5.

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Answer:

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Step-by-step explanation:

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184 x 0.03

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184*1.03 = £189.52

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D
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Step-by-step explanation:

hope this helps

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Answer:

Step-by-step explanation:

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Answers

Lin should aim the ball at 7.8 feet away from point  B

From the question (see attachment), we have the following equivalent ratios:

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[tex]AB : BE = DC :CE[/tex]

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[tex]CE=20 - BE[/tex]

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[tex]320 - 16BE = 25BE[/tex]

Collect like terms

[tex]25BE + 16BE = 320[/tex]

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Step-by-step explanation:

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Answer:

360 is the answer

Step-by-step explanation:

hi

have a good day

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thank me later

carryonlearing

Answer:

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Answer:

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Rewrite the equation in slope -intercept form then graph the linear equation x+4y=8​

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Answer:

Step-by-step explanation:

x + 4y = 8

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Step-by-step explanation:

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