Calculate the average net force.

Answer:

I once yelled out in zoom "I WANNA KISS A ANIME BOY" Cause of a silly dare

Explanation:

Everyone laughed and I was kicked

Answer:

my brother was pushing the cart at target and the front like got my ankles and I fell in front of everyone and he was just laughing.

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 4.6 × 9.2

We have the final answer as

Hope this helps you

Answer:

Explanation:

Answer: yes it is

Explanation: A biotic factor is something that is living. this also apply to plants animals and people. A dinosaur was once a living being so it would be classified as a biotic factors. An abiotic factor is something that is not living .so that would be tables chairs and clothes.

Answer: 2 m/s

Explanation:

Divide 10 meters by 5 seconds

Explanation:

think4

pleas! mark me s brainliest please please

Answer & Explanation:

Crashing into the asteroid would cause the satellite to slow down, stop, or reverse direction, because it is a force in the opposite direction to the satellite's motion. Whichever crash was a stronger force would cause it to change motion more. It takes a stronger force to change the velocity of a more massive object.

Answer:

57,6N

Explanation:

To find the component  of a force on the x-axis we can simply do:

F * cos(36) = 72N * 0.8 = 57,6N

Answer:

i. Cyclist A travelled 15 km 1 h cyclist A had started his journey from point X

  Cyclist B travelled 18 km 1 h cyclist A had started his journey from point X

ii. cyclist B overtake cyclist A 6 km from the same starting point X.

Explanation:

From the question,

- Cyclist A and B cycled at an average speed of 15 km/h and 20 km/h respectively.

- Cyclist B started his journey 6 mins after cyclist A had started.

Let the cyclist A time be t.

Then, we can write that

For Cyclist A

Speed = 15 km/h

Time = t mins

For Cyclist B

Speed = 20 km/h

Time = (t - 6) mins

i) To determine the distances travelled by cyclist A and B 1h cyclist A had started his journey,

For Cyclist A

Speed = 15km/h

Time = 1h = 60 mins

From the formula

Speed = Distance / Time

Then,

Distance = Speed × Time

Putting the values into the equation,

Distance = 15km/h × 1h

Distance = 15 km

∴ Cyclist A travelled 15 km 1 h cyclist A had started his journey from point X

For cyclist B

Speed = 20km/h

Time = 1h - 6mins = 60mins - 6mins = 54mins = 54/60 hour = 0.9 h

Also, from

Distance = Speed × Time

Putting the values into the equation

Distance = 20km/h × 0.9h

Distance = 18 km

∴ Cyclist B travelled 18 km 1 h cyclist A had started his journey from point X

ii) To determine the distance cyclist B overtake cyclist A, that is, when the distance covered by cyclist A equals that covered by cyclist B.

First, we will determine the time at which the distances covered by both cyclists were equal.

From

For Cyclist A

Speed = 15 km/h

Time = t hour  

Distance = Speed × Time

Distance = 15t km

For Cyclist B

Speed = 20 km/h

Time = (60t - 6) mins = (t - 0.1) hour

Distance = 20 × (t - 0.1) = (20t - 2) km

Equate the distances

15t = 20t - 2

15t - 20t = -2

-5t = -2

5t = 2

t = 2/5

t = 0.4 hour

Hence, cyclist B overtake cyclist A 0.4 hour after cyclist A had started.

For the distance cyclist B overtake cyclist A,

From

Distance = (20t - 2) km

Distance = (20×0.4 - 2) km

Distance = (8 - 2) km

Distance = 6 km

Hence, cyclist B overtake cyclist A 6km from the same starting point X.

[tex]w = F * S[/tex]

[tex]F = 20\\S = 10\\F * S = 20 * 10 = 200[/tex] Joules <- 1st answer

[tex]w = F * S[/tex]

[tex]1234 = F * 100[/tex]

[tex]F = \frac{1234}{100}[/tex]

[tex]F = 12.34 N[/tex]  <- 2nd answer

Answer:

biosphere

Explanation:

pretty sure bc it is ground

Answer:

The faster car has more kinetic energy because kinetic energy increases with speed.

Explanation:

-

Answer:

The neutral wire is often confused with ground wire, but in reality, they serve two distinct purposes. Neutral wires carry currents back to power source to better control and regulate voltage. Its overall purpose is to serve as a path to return energy.

Answer:

C. Do bubbles form when the element is mixed with an acid?

Explanation:

all the other options are incorrect because they are

"Does a magnet attract the element?" is the question that can be used to identify a physical property of an element, because the magnetic behavior of any material is purely a physical property of that material.

Therefore, the correct answer is option A.

A magnetic field could be understood as an area around a magnet, magnetic material, or an electric charge in which magnetic force is exerted.

Since the magnetic behavior of any substance is solely a physical feature of that material, the question "Does a magnet attract the element?" can be used to determine a physical attribute of an element.

Thus, the correct answer is option A.

Learn more about the magnetic fields from here, refer to the link;

brainly.com/question/23096032

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The acceleration it's the difference of speed (final speed - initial speed)  divided by the time. So:

a = Δv/t

In this case the initial speed is equal to 0. The final speed is equal to 80 miles/hour. The time is 10s.

a = 80 miles/hour divided by 10 = 8 miles/hour

Answer:

8

Explanation:

Because as you can see 80/10= 8

Answer is 8

Answer:

Q=it

I=2.5A

T=600 seconds

Q=2.5*600

= 1,500 C

Answer:

Explanation:

Explanation is attached.

Answer: To determine the speed of an object, you need to know the distance traveled and the Time = 4.0 seconds The speed of the cheetah in miles per hour is 63 mph 5. How far can a person run in 15 minutes if he or she runs at an average .

Explanation: I hope that was helpful !

[tex]\sf{m_1}[/tex] = 8kg

[tex]\sf{m_2}[/tex] = 4kg

g = 10m/s²

→Acceleration of block

→Tension in strings

Let, the two equation will be ,

[tex]\leadsto[/tex] 8g - T = 8a ..... Equation no (1)

[tex]\leadsto[/tex] T - 4g = 4a ..... Equation no (2)

Putting the value of equation no (1) and (2) we get,

[tex]\implies[/tex] 4g = 12a

[tex]\implies[/tex] 4 × 10 = 12a

[tex]\implies[/tex] 40 = 12a

[tex]\implies[/tex] a = [tex]\sf\dfrac{\cancel{40}}{\cancel{12}}[/tex]

[tex]\dashrightarrow[/tex] a = [tex]\dfrac{10}{3}[/tex]

Again, we have to putting the value of a in the equation no (2) we get,

[tex]\implies[/tex] T - 4g = 4 × [tex]\dfrac{10}{3}[/tex]

[tex]\implies[/tex] T - 4 × 10 = 4 × [tex]\dfrac{10}{3}[/tex]

[tex]\implies[/tex] T - 40 = [tex]\dfrac{40}{3}[/tex]

[tex]\implies[/tex] T = [tex]\dfrac{40}{3}[/tex] + 40

[tex]\implies[/tex] T = [tex]\dfrac{40 + 120}{3}[/tex]

[tex]\dashrightarrow[/tex] T = [tex]\dfrac{160}{3}[/tex] N

[tex]\therefore[/tex] Acceleration of block = [tex]\dfrac{10}{3}[/tex] m/s².

And, Tension in strings = [tex]\dfrac{160}{3}[/tex] N

Answer:

B.

Velocity describes how fast something is going, whereas Speed describes how fast something is going and in which direction.

Explanation:

. If the above statement is true, then describe an example of such a motion. ... b. What was the displacement for the entire trip? 0 miles (You finish where you started) ... Speed is a quantity that describes how fast or how slow an object is moving.

Answer:

0

Explanation:

F1 = G•2.2•4.66/3² (pointed right)

F2 = G•2.2•4.66/3² (pointed left)

subtract the two to get zero

The gravitational force on the 2.20 Kg mass is 7.53 × 10⁻¹¹ N to the right and and the same to the left. The same forces are in opposite direction and thus balances each other.

The gravitational force is the force by which an object attracts other object into its center of mass. The gravitational force depends on the masses of the objects and distance between them by the equation written below:

g = G m1 m2/r²

where G is the universal gravitational constant equal to 6.67 × 10⁻¹¹ N

Given the mass at the  origin = 2.20 kg

mass in right side = 4.66 Kg.

distance = 3 m.

then g = 6.67 × 10⁻¹¹ N × (2.20 × 4.66 kg)/3² =  7.53 × 10⁻¹¹ N

However, the equal force acts from the equal distance by the same mass from the left side also. Therefore, both forces cancel each other in magnitude and the net gravitational force will be zero.

Find more on gravitational force:

https://brainly.com/question/24783651

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-- The distance the force moved through

-- How long the force lasted

The other thing we need to calculate the power is the "Velocity".

The relation can be shown as:

→ [tex]P= Fv[/tex]

where,

Thus the above is the right response.

Learn more about Power here:

https://brainly.com/question/11380506

Answer:

800 mL

Explanation:

D*V=M

You pick out the numbers as well as what it is they represent from the word problem/explanation, then from there plug them in to the equations. Once you do that, you get your product and have the answer.

10*80= 800

Explanation:

Given:

v₀ = 0 m/s

a = 3 m/s²

t = 4 s

Find: Δx and v

Δx = v₀ t + ½ at²

Δx = (0 m/s) (4 s) + ½ (3 m/s²) (4 s)²

Δx = 24 m

v = at + v₀

v = (3 m/s²) (4 s) + 0 m/s

v = 12 m/s

mass = 30kg

frictional force = coefficient of friction * (mass * g)

g = 9.8 m/s^2

So:

60N = x * 294 N

x = 60 N / 294 N = 0,2

Answer:

C more than 1 second

Explanation:

it will take time since its 4.9 meters and how hard you throw it down

Answer:

1. The stone will strike the ground 49.46 m from the base of the cliff

2. A) Approximately 0.542 seconds

B)  Approximately 3.69 m/s

3. A) The time the ball spends in the air is approximately 4.0775 s

B) The horizontal range is approximately  141.25 m.

Explanation:

1. The time it takes the stone to land is given by the equation, t = √(h/(1/2 × g)

∴ t = √(30/(1/2 × 9.81)) ≈ 2.473 seconds

The horizontal distance covered by the stone in that time = 20 × 2.473 ≈ 49.46 m

The stone will strike the ground 49.46 m from the base of the cliff

2. A) The time the ball spends in the air = t = √(h/(1/2 × g)

∴ t = √(1.44/(1/2 × 9.81)) ≈ 0.542 seconds

B) The initial horizontal velocity, u = Horizontal distance/(Time) = 2/0.542 ≈ 3.69 m/s

The initial horizontal velocity ≈ 3.69 m/s

3. A) The time the ball spends in the air is given by the following equation;

t = 2 × u × sin(θ)/g = 2 × 40 × sin(30)/9.81 ≈ 4.0775 s

t ≈ 4.0775 s

B) The horizontal range, R, of the  ball is given by the equation for the range of a projectile as follows;

[tex]Range, R = \dfrac{u^2 \times sin (2 \cdot \theta) }{g}[/tex]

Substituting the known values, gives;

[tex]Range, R = \dfrac{40^2 \times sin (2 \times 30^{\circ}) }{9.81} \approx 141.25 \ m[/tex]

The horizontal range ≈ 141.25 m.