The mass of block 1 will be 1.99 kg.The tension force is applied along the whole length of the wire, pulling energy equally on both ends.
What is tension force?The tension force is described as the force transferred through a rope, string, or wire as it is pulled by opposing forces.
Given that,
Mass of block 1=? kg
The coefficient of the kinetic friction,μ=0.200
Now consider the weight component in the uphill direction.The weight is found as;
[tex]\rm W=m_1gsin \theta[/tex]
The force is balanced in the vertical direction as;
[tex]\rm T=F_f-W[/tex]
When the force of friction is;
[tex]\rm F_F=\mu_k N[/tex]
[tex]\rm F_f=(m_1 gcos \theta)[/tex]
Substitute the value in the vertical balanced equation;
[tex]\rm T=m_1gsin(27.5)^0-\mu_kmgcos27.5^0[/tex]
[tex]\rm T-m_2g=0\\\\T=m_2g[/tex]
[tex]\rm (10.1) g=m_1g(0.699-0.2 \times(-0.714) ) \\\\ (10.1) g=m_1g (0.699+0.1428) \\\\\ (10.1) g= m_1 \times 0.8418 \\\\ m_1 =11.99 \ kg[/tex]
Hence the mass of block 1 will be 1.99 kg.
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The force as a function of displacement of a moving object is presented by the graph. How much work is done when the object moves from 5 m to 8 m? *
Answer:
Explanation:
Work is the area under the curve between the limits
W = ½(5)(8 - 5) = 7.5 J
The work done when an object moves from 5 m to 8 m is 7.5 J.
Work done
The work done in moving an object from one point to another is equal to the product of force and displacement of the object.
W = Fs
Area under a curveThe work done on an object is equal to area under the curve
The area between point 5 m and 8 m = ¹/₂ x (8 - 5) x 5 = 7.5 J
Thus, the work done when an object moves from 5 m to 8 m is 7.5 J.
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a
A soccer player kicks a ball horizontally and it travels 150 m. The ball was kicked off of a cliff that was 75 m
high. What speed was the ball kicked at?
The ball was kicked with a speed of 38.4 m/s.
Using s = ut + 1/2gt², we find the time it takes the ball to reach the ground. Where
s = height of cliff = 75 mu = initial vertical velocity of ball = 0 m/s(since it is kicked horizontally)g = acceleration due to gravity = 9.8 m/s²t = time taken for ball to reach the ground.Substituting the values of the variables into the equation, we have
s = ut + 1/2gt²
75 m = (0 m/s)t + 1/2 × 9.8 m/s² × t²
75 m = 0 m + (4.9 m/s²) t²
75 m = (4.9 m/s²)t²
Dividing both sides by 4.9, we have
t² = 75 m/4.9 m/s²
t² = 15.306 s²
Taking square-root of both sides, we have
t = √15.306 s²
t = 3.91 s
The horizontal distance covered by the ball d = vt where
v = horizontal speed of ball and, t = time taken for the ball to reach the ground.Since we require v, we make it subject of the formula.
So, v = d/t
Given that d = 150 m and t = 3.91 s, substituting these into v, we have
v = d/t
v = 150 m/3.91 s
v = 38.4 m/s
So, the ball was kicked with a speed of 38.4 m/s.
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E
D
С
B
A
Column
Column
1.
Electron Cloud
B
2
Nucleus
b. A
3.
Electron
CD
4.
Neutron
d.
5.
Proton
ec
Answer:
1. D electron cloud
2. A nucleus
3. E electron
4. B neutron
5. C proton
Explanation:
electrons are located outside the nucleus. The nucleus holds the protons and neutrons. Protons have a positive symbol (+). electron cloud holds the electrons.
Explanation:
Electron cloud : D
Nucleus : A
Electron : E
Neutron : B
Proton : C
hope this helps you.
17. The shape of a river is determined by which of the following? (Choose all that
apply)
A Erosion
B. Deposition
C. Weathering
D. water speed
Answer:
Water speed Plays a key role In determining The shape of it
Assume each trial ( roll of cubes) represents 1000 years. Imagine that you found a rock sample was 25% Lokium and 75% DOL, how would the rock sample be given the half-life you figured out? Show your work
Assuming each trial represents 1000years, and rock samples were found, the rock sample will be given half-life of
The rock sample will be [tex]2000years[/tex] oldIsotopeWe know that the parent Isotope remaining is given by the expression
[tex]\frac{1}{2}^n[/tex]
where,
n = number of half lives passed
lokium IsotopeFrom the question, the parent Isotope remaining is [tex]25\%[/tex] lokium
[tex]0.25 = \frac{1}{4} = \frac{1}{2^2} = \frac{1}{2}^2[/tex]
Therefore,
[tex]\frac{1}{2}^2[/tex] means 2 half lives have passed.
If from the question,
1 half life = 1000years
Rock ageTherefore,
The rock sample's age = [tex]2*1000 = 2000years[/tex]
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A block of mass m=10 kg at rest slides down a rough incline plane of θ=30° and length l=5 m. The coefficient of kinetic friction between the block and the incline is μ_k=0.1. At the bottom of the plane the block continues to slide on a frictionless surface and hits a spring with spring constant k=100 N/m.
The speed of the block at point B = 6.36 m/s
Given data :
Mass ( m ) = 10 kg
Angle of inclination ( θ ) = 30°
Length of incline = 5 m
Determine the speed of the block at a point B on the incline
First step : Calculate the work done by frictional force
given that there is no friction on the horizontal plane. Vinclined = Vhorizontal
∴ Work done by frictional force ( Wf ) = F * L cos 180
= - ( μ_k * N ) L
= - (0.1 * 84.86 ) * 5 = - 42.4 Joule
where N = mg cos 30°
= 10 * 9.8 * 0.866 = 84.86
Next step : Calculate the speed of the block at point B
applying work energy theorem
Wf = ΔK.E + ΔP.E
= ( 1/2 mv² - 0 ) + ( 0 - mgh )
∴ - 42.48 = 1/2 mv² - mgh
1/2 mv² = mgh - 42.48
= 10 * 9.8 * 5 sin 30° - 42.4
v² = 40.52
V ( speed of the block at point B ) = 6.36 m/s
Hence we can conclude that the speed of the block at point B = 6.36 m/s
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Attached below is the complete question related to your question
In what way does Isaac represent us?
Answer:
I believe The Knowledge that we apply everyday or based on these methods and discoveries may represent us
Explanation:
A 1500 kg car has the same momentum as a 2500 kg truck moving at 25 m/s. How fast is the car moving in m/s
Answer:
41.6m/s
Explanation:
P=mv
2500kg × 25m/s = 62500kgm/s
62500kgm/s ÷ 1500 kg = 41.6m/s
imagine that you have an electric car and all of the recaptured energy is put back into the battery that powers your car what speed could your car cheat from rest by using only the recaptured energy from part B
Answer:
Moving vehicles have a lot of kinetic energy, and when brakes are applied to slow a vehicle, all of that kinetic energy has to go somewhere.
Explanation:
In a collision, a 30 kg ball moving at 3 m/s transfers all of its momentum to a 5kg ball. what is the velocity of the 3kg ball after the collision?
Answer:
Explanation:
Is it a 30 kg ball or a 3 kg ball?
Does not matter as we don't have to do actual calculations
If all of the momentum is transferred out of a mass, the velocity remaining must be ZERO
state all kinds of errors
Answer:
Instrumental error
Environmental error
Observational error
Theoritical error
For a wave, the _____ the amplitude, the _____ energy the wave carries.
Multiple choice question.
A)
larger, more
B)
smaller, more
C)
larger, less
D)
smaller, same
Answer:
HIGHER & MORE OR LARGER OR MOREHENCE, THE ANSWER IS A. :)
Explanation:
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BRAINLIEST PLEASE I REALLY NEED IT
Identify the types of motion:-
the movement of the snail on the ground
the strings of the guitar
the whirling of stone tied with a thread
Answer:
the movement of snail on the ground is in random motion.
the strings of the guitar is in oscillatory motion.
the whirling of stone tied with a thread is in circular motion.
A stone of mass m = 1.05 kg is released from a height of h = 2.1 m into a pool of water. At a time of t = 1.83 s after hitting the surface of the water, the stone's velocity has decreased by 50%.
What is the magnitude of the average force the stone experiences, in newtons, during the time t?
Answer:
Explanation:
ignoring air resistance, the kinetic energy at water impact will equal the potential energy converted
½mv² = mgh
v = √(2gh)
v = √(2(9.81)2.1) = 6.4188... m/s
after impact, an impulse will result in a change of momentum.
There is a downward impulse due to gravity equal to the weight of the stone and an upward average force due to water resistance and buoyancy force.
FΔt = mΔv
(F - mg)Δt = m(vf - vi)
(F - mg) = m(vf - vi)/Δt
F = m(vf - vi)/Δt + mg
F = m((vf - vi)/Δt + g)
F = 1.05(((½(-6.4188) - -6.4188)/ 1.83) + 9.81)
F = 12.14198...
F = 12.1 N
The magnitude of the average force the stone experiences, will be 12.1 N.
What is force?Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration. Its unit is Newton.
The given data in the problem is;
m is the stone mass = 1.05 kg
The height is h, = 2.1 m i
The time is, t = 1.83 s
Velocity decreased by 50%.
From the law of conservation of energy the kinetic energy is equal to the potential energy;
[tex]\rm \frac{1}{2} mv^2 = mgh \\\\ v = \sqrt{2gh}\\\\ v = \sqrt{2 \times 9.81 \times 2.1 } \\\\ v= 64188 \ m/sec.[/tex]
From Newton's second law of motion, the impulsive force is equal to the change in momentum;
[tex]\rm F \triangle T = m \traingle v \\\\ (F - mg) = \frac{v_f-v_i}{\triangle t } \\\\ F = \frac{v_f-v_i}{\triangle t } + mg \\\\ F =m\frac{v_f-v_i}{\triangle t + g} \\\\ F= 12.14 98 \\\\ F=12.1 N[/tex]
Hence the magnitude of the average force the stone experiences, will be 12.1 N.
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Write down the condition required for the thermonuclear fusion.
Answer:
The main condition necessary for a controlled thermonuclear fusion:
The ions must be held together in close proximity at high temperature with a confinement time long enough to avoid cooling.
Suppose a bulldozer is being hauled at 50 km/h to a construction site on the back of a flatbed truck. From which reference point would the bulldozer not appear to be moving?
Answer:
from someone watching the bulldozer from the cab of the truck or from elsewhere on the flatbed.
Explanation:
The degree of coldness or hotness is different for different objects. Explain with an example
Answer:
Explanation:
The degree of hotness and coldness of air is known as temperature and is measured with a thermometer in degrees-Fahrenheit or degrees-Celsius. Mercury is the only one in the liquid state at room temperature. It is used in thermometers because it has a high coefficient of expansion. The flow of heat will be always from higher to lower temperature.
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please answer it I will mark it brainliest
Explanation:
1) If you spot something you think might be hazardous in your workplace, report it to your employer and safety rep straight away. Your employer should then decide what harm the hazard could cause and take action to eliminate, prevent or reduce that harm. Read more about risk assessments .
2) Complex hazards are understood as various combinations of sources of hazards that lead to the accident occurrences. ... The term "natural-technological" applies to both human-induced intensification of natural risks and any accidents in the technosphere triggered by natural processes or phenomena.
3)Risk Evaluation : To determine who may be harmed. Risk Control : Taking preventive measures to control the impact of risk.
In general, to do an assessment, you should:
Identify hazards.
Determine the likelihood of harm, such as an injury or illness occurring, and its severity. ...
Identify actions necessary to eliminate the hazard, or control the risk using the hierarchy of risk control methods.
The motor in a hairdryer is attached to a 3V battery. A current of 0.8A flows through the motor for 3 minutes. Calculate the total charge in this time.
The total charge in this time is equal to 144 Coulomb.
Given the following data:
Voltage = 3 VoltsCurrent = 0.8 AmperesTime = 3 minutes.To calculate the total charge in this time:
First of all, we would convert the value of time in minutes to seconds.
Conversion:
1 minute = 60 seconds
3 minutes = 180 seconds
Formula for quantity of charge.Mathematically, the quantity of charge is given by this formula:
[tex]Q=It[/tex]
Where:
Q is the quantity of charge.I is the current.t is the time measured in seconds.Substituting the given parameters into the formula, we have;
[tex]Q = 0.8 \times 180[/tex]
Quantity of charge, Q = 144 Coulomb.
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Answer:
960 watts
Explanation:
What is force? And tell it's unit
Answer:
force is simply a push or a pull in a particular direction. The unit is N (newton)
Explanation:
hope this helped
Answer:
In physics force is an influence which changes the motion of an object which has mass
Its unit is N or kgms/2
A 4.0 ohm resistor has a current of 3.0 A for 5.0 min. How many electrons pass through the resistor during this time interval?
a. 7.5 x 10^21
b. 3.8 x 10^21
c. 8.4 x 10^21
d. 2.1 x 10^21
e. 5.6 x 10^21
Answer:
e. 5.6 x 10^21 electrons.
Explanation:
In order to calculate the charge Q passing through the resistor for in a definite amount of time is
[tex]Q \ (\mathrm{coulombs}) \ = \ I \ (\mathrm{amperes}) \ \times \ t \ (\mathrm{seconds}) \\ \\ \-\hspace{2.22cm} = \ 3.0 \ \mathrm{A} \ \times \ 5.0 \ \mathrm{min} \ \times \ \displaystyle\frac{60 \ \mathrm{sec}}{1 \ \mathrm{min}} \\ \\ \-\hspace{2.22cm} = \ 900 \ \mathrm{C}[/tex]
Thus, using the law of quantization of electric charge, the number of electrons passing through the resistor during this time interval can be calculated.
[tex]Q \ = \ n \times e \\ \\ n \-\hspace{0.18cm} = \ \displaystyle\frac{Q}{e} \\ \\ n \-\hspace{0.18cm} = \displaystyle\frac{900 \ \mathrm{C}}{1.6 \times 10^{-19} \ \mathrm{C}} \\ \\ n \-\hspace{0.18cm} = 5.6 \times 10^{21} \ \ \mathrm{electrons}[/tex], where n denotes the number of electrons and e is the unit charge of an electron ([tex]1.6 \times 10^{-19} \ \mathrm{C}[/tex]).
You are pulling a sled with a constant velocity using a rope held horizontally in
the snow. Using a spring scale attached to the rope, you measure the tension
to be 0.96 N. The sled's mass is 0.58 kg. Write the surface force the ground
exerts on the sled in component form, and determine its magnitude.
Answer:
Explanation:
if you are pulling in the positive direction and Upward is also positive.
F = -0.96i + 0.58(9.8)j
F = -0.96i + 5.7j
F = √(-0.96² + 5.7²) = 5.8 N
You are pulling a sled with constant velocity by using a rope then the surface force the ground exerts on the sled will be 5.8 N.
What is tension?The pulling force conveyed axially by a string, cable, chain, or another analogous object, or by either end of a rod, truss member, or another such three-dimensional object, is referred to as tension in physics. Another way to think of tension is as the action-reaction pair of forces acting at each end of the previous elements. Perhaps tension is the polar opposite of compression.
A restoring force may cause what is also referred to as tension when atoms or molecules are torn apart from one another at the atomic level and build up potential energy.
If you are moving upward and pushing in a positive way,
F = -0.96 i + 0.58(9.8) j
F = -0.96 i + 5.7 j
F = [tex]\sqrt{(-0.96^2 + 5.7^2)}[/tex]
F= 5.8 N
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PLEASE ASP HELP THIS WILL GIVE 50 POINT AND BRAINLIEST！！！！！!
In introductory physics, a typical cavendish balance for measuring the gravitational constant G use metal masses 2.39kg and 16g whose center are separated by 6.81cm calculate the gravitation force between these forces, treating each as a point mass located at the center of the sphere.
gravitational constant =6.67259 × 10⁻¹¹N·m²/kg²
Answer:
Explanation:
F = GMm/d²
F = 6.67259 x 10⁻¹¹(2.39)(0.016) / 0.0681²
F = 5.5019685...x 10⁻¹⁰ N
round as appropriate, probably no more than 3 significant figures.
Value of G seems low, but well within the 3 significant figures of the other numerals. I typically see G = 6.674 x 10⁻¹¹
What is the significance of Isaac's name?
Answer:
ghgivjgifigo ra together aigig disgust u hoodie
What are the symmetry operations of molecule AB4, where the molecule b lies at the center of the square and A lies at the center of the square and is not coplaner with B atoms. How to find the multiplication table
The symmetry operations of molecule AB₄ is tetrahedral and they are :
E : Identity4C₃ : axis of rotation 3C₂ : axis of rotation3S₄ : Rotation-reflection axis 6бdTo find the multiplication table we have to apply the multiplication table for Td symmetry ( attached below )
Given that molecule B lies at the corners of the square and molecule A lie at the center and is not coplanar with molecule B the symmetry operations of the molecules AB₄ will belong to a tetrahedral symmetry group which contains :
E : Identity4C₃ : axis of rotation 3C₂ : axis of rotation3S₄ : Rotation-reflection axis 6бdLearn more about tetrahedral symmetry group : https://brainly.com/question/1968705
Find the magnitude of the potential difference between two points located 1.2 m apart in a uniform 700 N/C electric field, if a line between the points is parallel to the field. Express your answer in volts.
The magnitude of the potential difference between the two points is 840 V
To solve the problem above, we need to use the formula of Potential difference as related to distance and electric field.
Potential difference: This can be defined as the work required to move a unit charge from a point to another in an electric field.
⇒ Formula:
V = E×d.................. Equation 1⇒ Where:
V = Potential differenceE = Electric Fieldd = DistanceFrom the question,
⇒ Given:
E = 700 N/Cd = 1.2 m⇒ Substitute these values into equation 1
V = 700(1.2)V = 840 VHence, The magnitude of the potential difference between the two points is 840 V
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Which of the following changes would decrease the force between two charged particles by a factor of 9? A. Decreasing the distance between the particles by a factor of 3 B. Increasing the distance between the particles by a factor of 3 C. Increasing the amount of charge on each particle by a factor of 9 D. Decreasing the amount of charge on one of the particles by a factor of 3
Option B is correct.Increasing the distance between the particles by a factor of 3 decrease the force between two charged particles by a factor of 9.
What is electric force?The electric force between the two charges is directly proportional to the product of the charge and inversely proportional to the square of the distance between them.
The electric force is found as;
[tex]\rm F = \frac{K q_1q_2}{r^2}[/tex]
The electric force between the two charges is directly proportional to the product of the charge.
The electric force is inversely proportional to the square of the distance between them.
Increasing the distance between the particles by a factor of 3 decreases the force between two charged particles by a factor of 9
Hence, option B is correct.
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American Football originated from which two sports?
A) Soccer and Rugby
B) Rugby and Basketball
C) Cricket and Soccer
D) Soccer and Volleyball
Answer:
b rugby and basketball
Explanation:
basket ball was made by a white man
American Football originated from Soccer and Rugby. Hence, option (A) is correct.
What is American Football?American football, sometimes known as gridiron, is a team sport played by two teams of eleven players on a rectangular field with goalposts at each end. It is known simply as football in the United States and Canada. The defense, the team without the ball, seeks to halt the offense's movement and seize control of the ball for themselves.
The offence, the team in possession of the oval-shaped football, attempts to advance down the field by running with the ball or throwing it. The offence is awarded a new set of four downs to resume the drive if they successfully gain at least 10 yards in four downs or plays. If they fail, they forfeit the ball to the defense.
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a rectangular block has the density of 350g/cm3 the dimensions are 3.5 6.cm 2.5
cm calculate the mass of the bock
Answer:
18375g
Explanation:
[tex]\boxed{density = \frac{mass}{volume} }[/tex]
[tex]∴ mass = density \times volume[/tex]
Let's find the volume of the rectangular block.
Volume
= length ×breadth ×height
= 3.5 ×6 ×2.5
= 52.5cm³
Mass of the block
= 350(52.5)
= 18375g
URGENTLY NEED HELP
This is a 2 part question
42) You pull downward with a force of 28 N on a rope that passes over a disk-shaped pulley of mass 1.2 kg and radius 0.075 m. The other end of the rope is attached to a 0.67-kg mass. (a) Is the tension in the rope the same on both sides of the pulley? If not, which side has the greater tension? (b) Find the tension in the rope on both sides of the pulley.
Answer:
The net force on the hanging mass is thus
2 T Mg 18 6.6 N 11.4 N
, enough to accelerate it upward at
17 m/s2
. The angular acceleration of the pulley is thus
2 2
Explanation:
The tension in the rope on both sides of the pulley 20.21N.
To solve this problem, we'll need to consider the forces acting on both sides of the pulley and apply Newton's second law of motion. Let's break it down step by step:
(a) Is the tension in the rope the same on both sides of the pulley?
No, the tension in the rope is not the same on both sides of the pulley. The side with the greater mass attached will experience a greater tension in the rope.
(b) Find the tension in the rope on both sides of the pulley:
Calculate the gravitational force on each mass:
Gravitational force on the pulley: Fpulley = mpulley * g, where mpulley is the mass of the pulley and g is the acceleration due to gravity (approximately 9.8 m/s²).
Gravitational force on the hanging mass: Fhanging = mhanging * g, where m_hanging is the mass of the hanging mass.
Calculate the net force on the pulley:
Net force on the pulley is the difference between the tension forces on either side: Fnet = TLeft - Tright.
Apply Newton's second law to the pulley:
For the pulley, Fnet = mpulley * a, where a is the acceleration of the pulley. Since the pulley is assumed to be massless, we can use the relationship a = α * r, where α is the angular acceleration and r is the radius of the pulley.
Use the relationship between linear acceleration and angular acceleration:
α = a / r.
Equate the torque due to the tension to the moment of inertia times the angular acceleration:
τ = I * α, where τ is the torque, I is the moment of inertia of the pulley, and α is the angular acceleration.
Substitute the expression for α and solve for the net tension:
Tnet = (τ / r) = (I * α) / r = (1/2 * mpulley * r² * α) / r = (1/2 * mpulley * r * a).
Now, substitute the expression for a from step 3 and solve for the net tension:
Tnet = (1/2 * mpulley * r * α) = (1/2 * mpulley * r * (a / r)) = (1/2 * mpulley * a).
Substitute the expression for a from step 2 (Fnet = mpulley * a) and solve for the net tension:
Tnet = (1/2 * Fnet).
Now, you can find the tensions on each side of the pulley:
Tleft = Tnet + Fhanging
Tright = Tnet - Fpulle
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