Answer:
20 per second
Explanation:
80/4
20
The hummingbird beats its wing 20 times per second!
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1. A Capacitor c =5.31 nF, is made of two Parallel square Plates seperated by distance d = 5mm. Find the Area. please ans this, i will give brainliest
We know that,
[tex]\huge ➸ C = ϵ₀ \frac{A}{d} [/tex]
C⤏Capacitanceϵ₀⤏permittivity of free space constantA⤏Area of capacitor platesd ⤏distancegiven ↷
C⤏5.31 nF = 5.31 x 10^-9ϵ₀⤏8.85 x 10^-12 F/m A⤏Area of capacitor platesd ⤏5mmto find ↷
The Areasolution ↷
[tex]\begin{gathered}➸ C = ϵ₀ \frac{A}{d} \\ \end{gathered} [/tex]
[tex]\begin{gathered}➸ A = \frac{Cd}{ϵ₀} \\ \end{gathered} \\ [/tex]
[tex]\begin{gathered}➸ A = \frac{5.31 \times {10}^{ - 9} \times 5 }{8.85 \times {10}^{ - 12} } \\ \end{gathered} \\ [/tex]
[tex]➸ A =3 \times {10}^{3} {mm}^{2} [/tex]
[tex]➸ A =3 {m}^{2} [/tex]
Hence, the area is 3m²
Answer:
Explanation:
The capacitance of two parallel square plates of area A and separated by distance d is given as:
C = ε(A/d) where ε is the permittivity of the dielectric material
For air, ε = 8.854x10^(-12) F/m
Substituting into the equation:
5.31x10^(-9) = 8.854x10^(-12) * A / 5x10^(-3)
A = 3.00 m^2
Can an object have both potential and kinetic energy at the same time ?
Answer:
yes
Explanation:
An object can be elevated and moving at the same time, example: a thrown ball
Explanation:
Ofcourse! Objects can have both kinetic energy and potential energy at the same time.
An object can be elevated above the ground (have potential energy) and be moving at the same time (and also have kinetic energy).A car bounces up and down on its springs at 1.0 Hz with only the driver in the car. Now the driver is joined by four friends. The new frequency of oscillation when the car bounces on its springs is
The new frequency of oscillation when the car bounces on its springs is 0.447 Hz
Frequency of oscillation of spring
The frequency of oscillation of the spring is given by f = (1/2π)√(k/m) where
k = spring constant and m = mass on springNow since k is constant, and f ∝ 1/√m.
So, we have f₂/f₁ = √(m₁/m₂) where
f₁ = initial frequency of spring = 1.0 Hz, m₁ = mass of driver, f₂ = final frequency of spring and m₂ = mass on spring when driver is joined by 4 friends = 5m₁So, making f₂ subject of the formula, we have
f₂ = [√(m₁/m₂)]f₁
Substituting the values of the variables into the equation, we have
f₂ = [√(m₁/m₂)]f₁
f₂ = [√(m₁/5m₁)]1.0 Hz
f₂ = [√(1/5)]1.0 Hz
f₂ = 1.0 Hz/√5
f₂ = 1.0 Hz/2.236
f₂ = 0.447 Hz
So, the new frequency of oscillation when the car bounces on its springs is 0.447 Hz
Learn more about frequency of oscillation of spring here:
https://brainly.com/question/15318845
What force causes raindrops to fall to Earth?
A.lift
B.drag
C.gravity
D.buoyancy
Answer:
Gravity
Explanation:
Because gravity try to pull everything toward the earth center. So raindrops fall towards the ground
8. A 55-kg skateboarder enters a ramp moving horizontally with a speed of 6.5 m/s, and leaves the ramp moving vertically with a speed of 4.1 m/s. (A) Find the height of the ramp, assuming no energy loss to frictional forces. (B) What is the skateboarder's maximum height above the bottom of the ramp?
(a) The energy lost to friction by the skateboarder is -699.6 J.
(b) The maximum height above the bottom of the ramp is 1.3 m.
Energy loss to frictionThe energy lost to friction by the skateboarder is calculated from the change in kinetic energy of the skateboarder.
ΔK.E = K.Ef - K.Ei
ΔK.E = ¹/₂m(vi² - vf²)
ΔK.E = 0.5 x 55 (4.1² - 6.5²)
ΔK.E = -699.6 J
Maximum height above the bottom of the rampThe maximum height above the bottom of the ramp is determined from conservation of energy.
mghi + ¹/₂mvi² = ¹/₂mvf² + mghf
55 x 9.8 x hi + (0.5 x 55 x 6.5²) = (0.5 x 55 x 4.1²) + (55 x 9.8 x 0)
539hi + 1161.88 = 462.28
539hi = -699.6
hi = -699.6/539
hi = -1.3 m
Thus, the maximum height above the bottom of the ramp is 1.3 m.
Learn more about conservation of energy here: https://brainly.com/question/166559