A variable is normally distributed with mean 18 and standard deviation 8. Use your graphing calculator to find each of the following areas. Write your answers in decimal form. Round to the nearest thousandth as needed.

a) Find the area to the left of 18.
0
Incorrect
b) Find the area to the left of 14.

c) Find the area to the right of 17.

d) Find the area to the right of 19.

e) Find the area between 14 and 30.

Answers

Answer 1

Answer:

a) The area to the left of 18 is 0.5.

b) The area to the left of 14 is if 0.309.

c) The area to the right of 17 is of 0.55.

d) The area to the right of 19 is of 0.45.

e) The area between 14 and 30 is of 0.624.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X, which is the area to the left of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X, which is the area to the right of X.

A variable is normally distributed with mean 18 and standard deviation 8

This means that [tex]\mu = 18, \sigma = 8[/tex]

a) Find the area to the left of 18.

This is the pvalue of Z when X = 18.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{18 - 18}{8}[/tex]

[tex]Z = 0[/tex]

[tex]Z = 0[/tex] has a pvalue of 0.5.

So the area to the left of 18 is 0.5.

b) Find the area to the left of 14.

This is the pvalue of Z when X = 14. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{14 - 18}{8}[/tex]

[tex]Z = -0.5[/tex]

[tex]Z = -0.5[/tex] has a pvalue of 0.309

The area to the left of 14 is if 0.309.

c) Find the area to the right of 17.

This is 1 subtracted by the pvaleu of Z when X = 17. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{17 - 18}{8}[/tex]

[tex]Z = -0.125[/tex]

[tex]Z = -0.125[/tex] has a pvalue of 0.45

1 - 0.45 = 0.55

The area to the right of 17 is of 0.55.

d) Find the area to the right of 19.

This is 1 subtracted by the pvaleu of Z when X = 19. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{19 - 18}{8}[/tex]

[tex]Z = 0.125[/tex]

[tex]Z = 0.125[/tex] has a pvalue of 0.55

1 - 0.55 = 0.45

The area to the right of 19 is of 0.45.

e) Find the area between 14 and 30.

This is the pvalue of Z when X = 30 subtracted by the pvalue of Z when X = 14.

X = 30

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{30 - 18}{8}[/tex]

[tex]Z = 1.5[/tex]

[tex]Z = 1.5[/tex] has a pvalue of 0.933

From b), when X = 14, Z has a pvalue of 0.309.

0.933 - 0.309 = 0.624

The area between 14 and 30 is of 0.624.

Answer 2

The area to the left of 18 is 0.5, the area to the left of 14 is 0.309, the area to the right of 17 is 0.55, the area to the right of 19 is 0.45, and the area between 14 and 30 is 0.624.

Given :

A variable is normally distributed with a mean of 18 and a standard deviation of 8.

a) Use the z score formula in order to determine the area to the left of 18.

[tex]\rm Z = \dfrac{X-\mu}{\sigma}[/tex]

[tex]\rm Z = \dfrac{18-18}{8}=0[/tex]

For the z = 0 the p-value is 0.5.

Therefore, 0.5 is the area to the left of 18.

b) Use the z score formula in order to determine the area to the left of 14.

[tex]\rm Z = \dfrac{X-\mu}{\sigma}[/tex]

[tex]\rm Z = \dfrac{14-18}{8}=-0.5[/tex]

For the z = -0.5 the p-value is 0.309.

Therefore, 0.309 is the area to the left of 14.

c) Use the z score formula in order to determine the area to the right of 17.

[tex]\rm Z = \dfrac{X-\mu}{\sigma}[/tex]

[tex]\rm Z = \dfrac{17-18}{8}=-0.125[/tex]

For the z = -0.125 the p-value is 0.45.

Therefore, the area to the left of 17 is given by:

= 1 - 0.45 = 0.55

d) Use the z score formula in order to determine the area to the right of 19.

[tex]\rm Z = \dfrac{X-\mu}{\sigma}[/tex]

[tex]\rm Z = \dfrac{19-18}{8}=0.125[/tex]

For the z = 0.125 the p-value is 0.55.

Therefore, the area to the left of 19 is given by:

= 1 - 0.55 = 0.45

e) Use the z score formula in order to determine the area between 14 and 30.

At X = 30 the z score becomes:

[tex]\rm Z = \dfrac{X-\mu}{\sigma}[/tex]

[tex]\rm Z = \dfrac{30-18}{8}=1.5[/tex]

For the z = 1.5 the p-value is 0.933.

For the z = -0.5 the p-value is 0.309.

Therefore, the area to the left of 14 is given by:

= 0.933 - 0.309

= 0.624

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Answers

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Step-by-step explanation:

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What is an equation?

Equations are statements that affirm the equivalence of two expressions that are joined by the equals symbol "=". An equal sign ("=") links two expressions together to form an equation. The two expressions on each side of the equals sign are referred to as the "left-hand side" and "right-hand side" of the equation.

It is given that, A man is three times as old as his daughter. If the difference in their ages is 36 years,

We have to find the ages of the father and daughter.

Suppose the age of the father and daughter will be x and y respectively.

If the man is three times as old as his daughter,

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3y -y = 36

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y = 18

x = 54

Thus, if a man has a daughter who is three times his age. The father and daughter will be 54 and 18, respectively, assuming their ages are 36 years distant.

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Answers

Answer:

Step-by-step explanation:

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[tex]\rm Mean(B) = \frac{Sum \ of \ all \ data \ values}{Number \ of \ data \ in \ the\ set}[/tex]

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