A university council wants to determine the need for a new staff room. The council conducted a survey of the staff by randomly speaking to 860 staff members out of 2,844 staff members. The council found that 70% of those surveyed were in favor of building a new staff room. Assuming a 90% confidence level, which statement holds true?



As the sample size is appropriately large, the margin of error is 0.036.


As the sample size is appropriately large, the margin of error is 0.026.


As the sample size is too small, the margin of error is 0.026.


As the sample size is too small, the margin of error cannot be trusted.

To find a margin of error for a sample proportion, these assumptions must be met, where n is the sample size and is the sample proportion.




First rewrite the proportion of positive responses as a decimal number.




Now substitute the sample proportion and the sample size, 860, into the formulas for the assumptions to determine whether they are met.




Both values are greater than 10, so the assumptions are met, and the margin of error can be calculated.


Find the margin of error using this formula, where z is the critical value.




For a 90% confidence level, . Substitute the values of z, n, and into the formula for margin of error and evaluate.

Answers

Answer 1

Answer:

As the sample size is appropriately large, the margin of error is 0.026

Step-by-step explanation:

A University Council Wants To Determine The Need For A New Staff Room. The Council Conducted A Survey
A University Council Wants To Determine The Need For A New Staff Room. The Council Conducted A Survey

Related Questions

7/12 x 4/6 simplest form​

Answers

3.8 repeating or 3 8/9 i think

Round 69781 to the nearest thousand

Answers

Answer:

70000 :) :) :)

Answer:

70,000

Step-by-step explanation:

69781 = 69700

So now you need to round 700 to 1,000 or 0

If you said 1,000 your correct, this makes the number 60,000 + 10,000 making 70,000

In 1960, the average cost of a gallon of milk was $0.49. In 1985, the average cost of a gallon of milk was $2.26. Which of the following represents how to calculate the percent increase in the average cost of a gallon of milk from 1960 to 1985.

A
2.26−0.490.49



B
2.26+0.490.49



C
2.26−0.492.26



D
2.26+0.492.26

Answers

Answer:

A

Step-by-step explanation:

$ 2.26- $0.49

=$1.77 increase from 1960 to 1985

What is 3 3/10 + 2 1/10

Answers

As a decimal- 5.4

As an exact form- 24/5

As a Mixed number- 5 2/5

Hope this helped :T

PLease HELPPPpP someone who is good at math PLS

Answers

Answer:

I think it would be A not sure tho

Step-by-step explanation:

Tickets for the school play sell for $4 each. Which graph shows the relationship between the number of tickets solo
(x) and the total income from the tickets (y)?

Answers

Answer:

I do not see all the graphs but it would be the reverse of what is shown for A. graph. The tickets sold to total income would have to be a 1:4 ratio where every 4 dollar leap in the y-axis is a one point (1 unit change in x).

Step-by-step explanation:

Fill in the blank will choose brain

Answers

Answer:

Below :)

Step-by-step explanation:

The difference of the means would be:

90 - 50 = 40

When finding difference you need to use subtraction.

The difference is 40

The MAD score is 10

"This difference is 4 times the value of the MAD of each data set."

find the product -2X²×4X²y²​

Answers

Answer:

-8X^4y^2

Step-by-step explanation:

-2X² × 4X²y²​ = -8X^4y^2

edit to add:

first: multiply the coefficients together:

-2 x 4 = -8

second: add the exponents of X together (when you multiply exponents, you just add them together):

² & ² = ^4

and you have the answer:

-8X^4y^2

Step-by-step explanation:

-2X²×4X²-y²

= -4X × 16X - y

= 64X -y

100 pts plz someone help asappp

Answers

∠1=45°

∠2=135°

∠3=45°

∠4=135°

Answer:

∠1=45°

∠2=135°

∠3=45°

∠4=135°

Step-by-step explanation:

A student needs to print pamphlets for an activities fair. If the printer takes 3 minutes to print a pamphlet, which inequality represents
the possible number of pamphlets, p, the student can expect the printer to print in more than 30 minutes?
.
O 3p 30

Answers

Answer:

3p <_30

Step-by-step explanation:

what is the answer to this (235-(-30) /5-100

Answers

Answer:

265/ -95 = -2.789

Step-by-step explanation:

235 - - 30 /5 - 100

two negatives equal a positive +

265/5 - 100

265/-95

-2.789

What is 4v7^3 in exponential form?

Answers

Answer:

7 3/4

Step-by-step explanation:

Could someone please help with this?

Answers

9514 1404 393

Answer:

  5.  88.0°

  6.  13.0°

  7.  52.4°

  8.  117.8°

Step-by-step explanation:

For angle A between sides b and c, the law of cosines formula can be solved to find the angle as ...

  A = arccos((b² +c² -a²)/(2bc))

When calculations are repetitive, I find a spreadsheet useful. It doesn't mind doing the same thing over and over, and it usually makes fewer mistakes.

Here, the side opposite x° is put in column 'a', so angle A is the value of x. The order of the other two sides is irrelevant.

__

Additional comment

The spreadsheet ACOS function returns the angle in radians. The DEGREES function must be used to convert it to degrees. The formula for the first problem is shown here:

  =degrees(ACOS((C3^2+D3^2-B3^2)/(2*C3*D3)))

As you can probably tell from the formula, side 'a' is listed in column B of the spreadsheet.

The spreadsheet rounds the results. This means the angle total is sometimes 179.9 and sometimes 180.1 when we expect the sum of angles to be 180.0.

20 Here is a list of five numbers.
98^53
98^64
98^73
98^88
98^91
Find the lowest common multiple of these five numbers.

Answers

We want to five the lowest common multiple of these 5 numbers. We will see that the lowest common multiple is:

[tex]98^{91}[/tex]

A multiple of a number N is any product between N and a positive integer. Here we want to get the smallest common multiple of the 5 numbers in the given set.

Here, the set is:

[tex]{98^{53}, 98^{64}, 98^{73}, 98^{88}, 98^{91}[/tex]

Remember the rule:

[tex]a^n*a^m = a^{n + m}[/tex]

Then we can see that:

[tex]98^{91} = 98^{91}*1 = 98^{88}*98^{3} = 98^{73}*98^{18} = 98^{64}*98^{27} = 98^{53}*98^{38}[/tex]

So:

[tex]98^{91}[/tex]

Is a common multiple of all the numbers in the set, and is the smallest common multiple because is equal to the largest number in the set.

If you want to learn more, you can read:

https://brainly.com/question/1055068

What is the value of the expression below?
64^1/3​

Answers

21.33 is the answer because you have to multiply 64 times 1/3

Answer:4

Step-by-step explanation:

Just did this question

The PTO is selling raffle tickets to raise money for classroom supplies. A raffle ticket costs $3. There is 1 winning ticket out of the 140 tickets sold. The winner gets a prize worth $84. Round your answers to the nearest cent.

What is the expected value (to you) of one raffle ticket?

Calculate the expected value (to you) if you purchase 8 raffle tickets?

What is the expected value (to the PTO) of one raffle ticket?

If the PTO sells all 140 raffle tickets, how much money can they expect to raise for the classroom supplies?

Answers

Answer:

A) 0.54

B) 4.32

C) 2.4

D)  336

Step-by-step explanation:

A)Expected value (you) = (84 × 3) × [tex]\frac{1}{140}[/tex] × (0.3)× [tex]\frac{139}{140}[/tex]

                                       = 0.54

B) Expected value (you) 8 tickets = 0.54 × 8

                                                       = 4.32

C) Expected value ( for PTO) = ( 3 - 84) × [tex]\frac{1}{140}[/tex] + ( 3 - 0 ) × [tex]\frac{139}{140}[/tex]

                                                = 2.4

D) For 140 raffle tickets = 2.4 × 140

                                       = 336

what is the place name of 2 in 25​

Answers

Answer:

no idea

Step-by-step explanation:

bro

Answer:

20

Step-by-step explanation:

Hope this helps

In a fruit cocktail, for every 30 ml of orange juice you need 45 ml of apple juice and 25 ml of coconut milk. What proportion of the cocktail is coconut milk?

Answers

25% or 1/4
30+45+25 =100;

enlarge the line by scale factor-2,with point (6,5)as the centre of enlargement.Mark the ends of your lines with crosses using the cross-drawing tool​

Answers

Dilation involves changing the size of a figure

The endpoints of the image are (-2,-1) and (6,1)

How to determine the coordinates of the image

The coordinates of the pre-image are give as:

(2,2) and (6,2)

The scale factor is given as:

k = 2

The center of dilation is given as:

(a,b) = (6,5)

The coordinates of the image are then calculated as:

[tex](x,y) \to (k(x -a) + a, k(y -b) + b)[/tex]

For (2,2), we have:

[tex](x,y) \to (2(2 -6) + 6, 2(2 - 5) + 5)[/tex]

[tex](x,y) \to (-2, -1)[/tex]

For (6,2), we have:

[tex](x,y) \to (2(6 -6) + 6, 2(2 - 5) + 5)[/tex]

[tex](x,y) \to (6, -1)[/tex]

Hence, the endpoints of the image are (-2,-1) and (6,1)

Read more about dilation at:

https://brainly.com/question/3457976

I need help ASAP. Worth 20 points
Look at picture plz

Answers

x = 13
hope this helps

The answer to that question was 43.93 not 43.98

Answers

Answer: Ok, but can you tell me what you want me to help you with you just put “ The answer to that question was 43.93 not 43.98” and I don’t understand.

Step-by-step explanation:

At many college bookstores, students can decide whether to purchase or to rent a textbook for a class. A study was conducted to investigate whether the percent of rented textbooks for all science classes in the state was greater than the percent of rented textbooks for all literature classes in the state. The following hypothesis test was done at the significance level of α=0.05α=0.05.
H0:pS=pLHa:pS>pLH0:pS=pLHa:pS>pL
In the hypotheses, pSpS represents the proportion of all science textbooks that are rented, and pLpL represents the proportion of all literature textbooks that are rented.
All conditions for inference were met, and the resulting pp-value was 0.035. Which of the following is the correct decision for the test?
The pp-value is less than αα. Since 0.035<0.050.035<0.05, the null hypothesis is rejected, and the claim is supported. There is convincing statistical evidence that the proportion of all science textbooks that are rented is greater than the proportion of all literature textbooks that are rented.
A The pp-value is less than αα, and the null hypothesis is rejected. There is not convincing evidence to support the claim that the proportion of all science textbooks that are rented is greater than the proportion of all literature textbooks that are rented.
B The pp-value is less than αα, and the null hypothesis is not rejected. There is not convincing evidence to support the claim that the proportion of all science textbooks that are rented is greater than the proportion of all literature textbooks that are rented.
C The pp-value is greater than αα, and the null hypothesis is rejected. There is convincing evidence to support the claim that the proportion of all science textbooks that are rented is greater than the proportion of all literature textbooks that are rented.
D The pp-value is greater than αα, and the null hypothesis is not rejected. There is not convincing evidence to support the claim that the proportion of all science textbooks that are rented is greater than the proportion of all literature textbooks that are rented.

Answers

Answer:

A The p-value is less than α, and the null hypothesis is rejected. There is convincing evidence to support the claim that the proportion of all science textbooks that are rented is greater than the proportion of all literature textbooks that are rented.

Step-by-step explanation:

Given :

Percentage rented science textbooks = pS

Percentage rented Literature textbooks = pL

To test if percentage Science textbooks in the state was greater than percentage Literature textbooks :

H0: pS = pL

Ha: pS > pL

Pvalue = 0.035 ; α = 0.05

Decision Region :

If Pvalue < α ; We reject H0

In the scenario above,

Pvalue < α ; 0.035 < 0.05 ; Hence, we reject the Null ;

We conclude that There is convincing evidence to support the claim that the proportion of all science textbooks that are rented is greater than the proportion of all literature textbooks that are rented.

True or False
If you know at least one
angle on the diagram
below you can find the
other three.

Answers

False
Hope this helps:)

One angle of a right triangle measures 51°. What is the measure of the other acute angle, in degrees?

Answers

Answer:

39 degree

Step-by-step explanation:

180-90-51=39

This question confuses me, and I am not understanding it.

Answers

Answer: As n increases, p increases.

The question is asking you about the equation of a line, p=2n-10

The equation of a line is y=mx+b

In this equation, m is the slope (how much you go up or down and then over)

In this equation, b is the y-intercept (where it intersects with the y line at 0)

Now with this knowledge, p=2n-10

P stands for y and N stands for x (its the same thing even if different)

2n means the m=2

Since the slope is positve it goes up 2 and then right 1

The y-int is -10

Now the options want to know what happens as n increases

Since the slope is positive when the x increases you know that the y increases so

As n increases, p increases.

(also i attached what the graph looks like)

I hope this explanation could help, please let me know if you do not understand still and if you could mark brainliest I would greatly appreciate it.

Answer: as n increases p increases

Step-by-step explanation:


Find the compound amount on an investment of $8,500 at 7.5% compounded daily for 3.5 years.

Answers

Answer:

Accrued Amount: 10955.51, Total Interest: 2455.51

Step-by-step explanation:

A = P(1+r/n)nt

CI = A-P

Where,

CI = Compounded interest

A = Final amount

P = Principal

t = Time period in years

n = Number of compounding periods per year

r = Interest rate

Four gardeners record the weight, in pounds, of 5 pumpkins they grew. Which statement about the weights of the pumpkins is true? Gardener Kylie Mark Todd Greg Pumpkin Weights (lbs) 20, 21, 33, 40, 29 14, 19, 45, 20, 22 15, 15, 15, 30, 22 33, 34, 36, 39, 33​

Answers

Answer:

Last Option: The range of weights for Greg's pumpkins is the least

Step-by-step explanation:

iReady Diagnostic

pls help

i’m so confused on this

Answers

Answer:

√(100)

Step-by-step explanation:

√(5) × √(20)

√(5 × 20)

√(100)

One year there was a total of 59 commercial and noncommercial orbital launches worldwide. In addition, the number of noncommercial orbital launches was two more
than twice the number of commercial orbital launches. Determine the number of commercial and noncommercial orbital launches.

Answers

Answer:

The number of commercial orbital launches is equal to 19 and the number of noncommercial orbital launches is equal to 40.

Step-by-step explanation:

IMPORTANT INFORMATION: The number of noncommercial orbital launches was two more than twice the number of commercial orbital launches.

Let's say that the number of commercial orbital launches is equal to x. Now, the number of noncommercial orbital launches is equal to 2x+2.

We are told that if we add the number of commercial and noncommercial orbital launches together we will get 59.

Therefore, if we add 2x+2 with x we should get 59:

2x+2+x=59

3x+2=59

3x=57

x=19

This is how we can come to the answer that the number of commercial orbital launches is equal to 19 and the number of noncommercial orbital launches is equal to 40 (2x+2=2*19+2=38+2=40).

Hope this helps!

HAPPY EARTH DAY GUYS! :)

Answers

Answer:

THANK YOU! YOU TOO! :)

Step-by-step explanation:

Have a nice dayyyyyy <3

Answer:

HAPPY EARTH DAY!!!!

:)

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