A train is spotted 10 miles south and 8 miles west of an observer at 2:00 pm. At 3:00 pm the train is spotted 5 miles north and 16 miles east of the observer. a. How far did the train travel in the first hour? b. If the train continues at this pace where will it be in relation to the observer at 5:00 pm? Write a function that will give the train's position at any given time c. d. At 2:00 pm a cyclist is traveling due east and is next to the observer. If the cyclist is traveling at 10 mph, do they collide with the train when the bike goes over the train tracks?

Answers

Answer 1

Answer:

a. The distance the train travelled in the first hour is approximately 28.3 miles

b. The location of the train at 5:00 p.m. is 53 miles east, and 46 miles west

c. The location of the train at any given time by the function, f(t) = (-8 + 24·t, -10 + 15·t)

d. The train does not collide with the cyclist when the bike goes over the train tracks

Step-by-step explanation:

a. The given information on the train's motion are;

The location south the train is spotted = 10 miles south and 8 miles west

The time the observer spotted the train = 2:00 pm

The location the train is spotted at 3:00 p.m. = 5 miles north and 16 miles east

Therefore, the difference between the two times the train was spotted, t = 3:00 p.m. - 2:00 p.m. = 1 hour

Making use of the coordinate plane for the two locations the train was spotted, we have;

The initial location of the train = (-10, -8)

The final location of the train = (5, 16)

Therefore the distance the train travelled in the first hour is given by the formula for finding the distance, 'd', between two points, (x₁, y₁) and (x₂, y₂) as follows;

[tex]d = \sqrt{\left (x_{2}-x_{1} \right )^{2}+\left (y_{2}-y_{1} \right )^{2}}[/tex]

Therefore;

[tex]d = \sqrt{\left (5-(-10) \right )^{2}+\left (16-(-8) \right )^{2}} = 3 \cdot\sqrt{89}[/tex]

The distance the train travelled in the first hour, d = 3·√89 ≈ 28.3 miles

b. The speed of the train, v = (Distance travelled by the train)/Time

∴ v ≈ 28.3 miles/(1 hour) = 28.3 miles per hour

The speed of the train in the first hour, v ≈ 28.3 mph

The direction of the train, θ, is given by the arctangent of the slope, 'm', of the path of the train;

[tex]\therefore The \ slope \ of \ the \ path \ of \ the \ train, \, m =tan(\theta) = \dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

∴ m = tan(θ) = (5 - (-10))/(16 - (-8)) = 0.625

c. Distance = Velocity × Time

At 5:00 p.m., we have;

The time difference, Δt = 5:00 p.m. - 3:00 p.m. = 2 hours

The distance, d₁ = (28.3 mph × 2 hours = 56.6 miles

Using trigonometry, we have the horizonal distance travelled, 'Δx', in the 2 hours is given as follows;

Δx = d₁ × cos(θ)

∴ Δx = 56.6 × cos(arctan(0.625)) ≈ 48

The increase in the horizontal position of the train, relative to the point (5, 16), Δx ≈ 48 miles

The vertical distance increase in the two hours, Δy is given as follows;

Δy = 56.6 × sin(arctan(0.625)) ≈ 30

The increase in the vertical position of the train, relative to the point (5, 16), Δy ≈ 30 miles miles

Therefore; the location of the train at 5:00 p.m. = ((5 + 48), (16 + 30)) = (53, 46)

The location of the train at 5:00 p.m. = 53 miles east, and 46 miles west

c. The function, 'f', that would give the train's position at time-t is given as follows;

The P = f(28.3·t, θ)

Where;

28.3·t = √(x² + y²)

θ = arctan(y/x)

Parametric equations

y - 5 = 0.625·(x - 16)

∴ y = 0.625·x - 10 + 5

The equation of the train's track is therefore, presented as follows;

y = 0.625·x - 5

d = 28.3·t

The y-component of the velocity, [tex]v_y[/tex] = 3*√89 mph × sin(arctan(0.625)) = 15 mph

Therefore, we have;

y = -10 + 15·t

The x-component of the velocity, vₓ = 3*√89 mph × cos(arctan(0.625)) = 24 mph

Therefore, we have;

x = -8 + 24·t

The location of the train at any given time, 't', f(t) = (-8 + 24·t, -10 + 15·t)

d. The speed of the cyclist next to the observer at 2:00 p.m., v = 10 mph

The distance of the cyclist from the track = The x-intercept = 5/0.625 = 8

The distance of the cyclist from the track = 8 miles

The time it would take the cyclist to react the track, t = 8 miles/10 mph = 0.8 hours

The location of the train in 0.8 hours, is f(0.8) = (-8 + 24×0.8, -10 + 15×0.8)

∴ f(0.8) = (11.2, 2)

At the time the cyclist is at the track along the east-west axis, at the point (8, 0), the train is at the point (11.2, 2) therefore, the train does not collide with the cyclist when the bike goes over the train tracks.

Answer 2

If the cyclist is travelling at 10 mph the train does not collide with the cyclist when the bike goes over the train tracks.

The location south the train is spotted = 10 miles south and 8 miles west

The time the observer spotted the train = 2:00 pm

The location of the train is spotted at 3:00 p.m. = 5 miles north and 16 miles east

Thus, the difference between the two times the train was spotted,

t = 3:00 p.m. - 2:00 p.m. = 1 hour

What is the distance?

The distance is the product of velocity and time.

Distance = Velocity × Time

The initial location of the train = (-10, -8)

The final location of the train = (5, 16)

Therefore the distance the train travelled in the first hour

[tex]d = \sqrt{(x_{2} -x_{1} )^{2} +(y_{2} -y_{1} )^{2} } \\d = \sqrt{(5 -(-10) )^{2} +(16-(-8) )^{2} }[/tex]

d = 3√89

The distance the train travelled in the first hour, d = 28.3 miles

b. The speed of the train, v = (Distance travelled by train)/Time

∴ v ≈ 28.3 miles/(1 hour) = 28.3 miles per hour

The speed of the train in the first hour, v ≈ 28.3 mph

The direction of the train, θ, is given by the arc tangent of the slope, 'm', of the path of the train;

∴ m = tan(θ) = (5 - (-10))/(16 - (-8))

m = 0.625

c. Distance = Velocity × Time

At 5:00 p.m., we have;

The time difference, Δt = 5:00 p.m. - 3:00 p.m. = 2 hours

The distance, d₁ = (28.3 mph × 2 hours = 56.6 miles

Using trigonometry, we have the horizontal distance travelled, 'Δx', in the 2 hours is given as follows;

Δx = d₁ × cos(θ)

∴ Δx = 56.6 × cos(arctan(0.625)) ≈ 48

The increase in the horizontal position of the train, relative to the point (5, 16), Δx ≈ 48 miles

The vertical distance increase in the two hours, Δy is given as follows;

Δy = 56.6 × sin(arctan(0.625)) ≈ 30

The increase in the vertical position of the train, relative to the point (5, 16), Δy ≈ 30 miles miles

Therefore; the location of the train at 5:00 p.m. = ((5 + 48), (16 + 30)) = (53, 46)

The location of the train at 5:00 p.m. = 53 miles east, and 46 miles west

c. The function, 'f', that would give the train's position at time-t is given as follows;

The P = f(28.3·t, θ)

28.3·t = √(x² + y²)

θ = arctan(y/x)

Parametric equations

y - 5 = 0.625·(x - 16)

∴ y = 0.625·x - 10 + 5

The equation of the train's track is, therefore, presented as follows;

y = 0.625·x - 5

d = 28.3·t

The y-component of the velocity,

= 3 × √89 mph × sin(arctan(0.625)) = 15 mph

Therefore, we have

y = -10 + 15·t

The x-component of the velocity,

vₓ = 3 × √89 mph × cos(arctan(0.625))

= 24 mph

Therefore, we have;

x = -8 + 24·t

The location of the train at any given time, 't',

f(t) = (-8 + 24·t, -10 + 15·t)

d. The speed of the cyclist next to the observer at 2:00 p.m., v = 10 mph

The distance of the cyclist from the track = The x-intercept

                                                                   = 5/0.625 = 8

The distance of the cyclist from the track = 8 miles

The time it would take the cyclist to reach the track, t = 8 miles/10 mph = 0.8 hours

The location of the train in 0.8 hours, is f(0.8)

= (-8 + 24×0.8, -10 + 15×0.8)

∴ f(0.8) = (11.2, 2)

therefore, If the cyclist is travelling at 10 mph the train does not collide with the cyclist when the bike goes over the train tracks.

Learn more about distance;

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Related Questions

A simple random sample from a population with a normal distribution of 103 body temperatures has x = 98.30°F and s = 0.61°F. Construct a 95​% confidence interval estimate of the standard deviation of body temperature of all healthy humans.

Answers

Answer:

(98.2884 ; 98.3116)

Step-by-step explanation:

Given :

x = 98.30°F and s = 0.61°F

Sample size. n = 103

Zcritical at 95% = 1.96

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x ± margin of error

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Sure! So remember that the Pythagorean theorem is a squared plus b squared = c squared.

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A = 48

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Answers

Answer:

(1+1+1)!*1=6

Step-by-step explanation:

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Answers

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Answer:

Solution given:

square pyramid

each side of base[b]=6cm

height[h]=9cm

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now

length of cube [l]=4cm

volume of cube[v]=l³=4³=64cm³

now

no of wax needed=[tex] \frac{V}{v} [/tex]=[tex] \frac{108cm³}{64cm³} [/tex]=[tex] \frac{27}{16 } =1\frac{11}{16} [/tex]

is needed.

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Step-by-step explanation:

Answer:

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Find the 11th term of the geometric sequence 6, -18, 54, ...

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Step-by-step explanation:

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In your problem [tex]a_{1}[/tex] = 6   r = -3    n = 11

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

Answer:

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Answers

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

9. C, II and III.

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Step-by-step explanation:

9.  If the cylinder is standing upright, the horizontal cut would be a circle or oval, and the vertical cut could be a rectangle

10. First we'll get the volume of the base rectangle. Then we'll calculate the volume of a cylinder, then divide that part in half, because it's 1/2 a cylinder on top of a rectangular prism.

Volume of a rectangular prism:

V = (length)(width)(height)

= 11 x 9 x 6 = 594 cubic mm

Volume of a cylinder:

V = (pi)(radius)^2(height)

The radius = 1/2 the diameter of the circle...the diameter is 9, so the radius is 4.5

= (3.14)(4.5)(4.5)(11)

= 699.435

That would be for a full cylinder with radius 4.5 and height of 11. We have half of one, so 699.435/2 = 349.7175 cubic mm

Add the volume of the 1/2 cylinder to the volume of the rectangular prism:

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Answers

The answer is D. 4.

What problems did Title IX address? Check all that apply.

lack of support for international students

limited opportunities for female athletes

limited resources in scientific courses of study

lack of scholarships and championships for women in sports

limited resources and facilities for women

Answers

Answer:

limited resources and facilities for women

lack of scholarships and championships for women

limited opportunities for female athletes

2,4,5

Statement two, four, and five are correct title IX law mandates institutions to obtain federal assistance to combat gender-based violence and harassment and respond to survivors' needs.

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Title IX is a potent instrument for fighting campus violence because it is a federal (national) legislation. To ensure that all students have equal access to education, the law mandates institutions to obtain federal assistance to combat gender-based violence and harassment and respond to survivors' needs.

As per the Title IX law:

Limited opportunities for female athletes.Lack of scholarships and championships for women in sports.Limited resources and facilities for women.

Thus, statement two, four, and five are correct title IX law mandates institutions to obtain federal assistance to combat gender-based violence and harassment and respond to survivors' needs.

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Simplify this expression
(√2+√3)(√5 -√7)

Answers

Answer:

Step-by-step explanation:

Answer:

pretty sure its the second one

Step-by-step explanation:

7. The answer is letter A or letter D
Find the next two terms in the sequence.

40, 10, –20, –50, . . .

A.
60, 80

B.
–80, –110

C.
–70, –100

D.
–70, –90

Answers

Answer:

B.

–80, –110

Step-by-step explanation:

-80 and -110

It is an arithmetic sequence. The difference = -30. It is the difference between each number in the sequence: 10-40=-30

-50-30=-80

-80-30 =-110

-80

First Identify the sequence being made here.

10-40 = -30

-20-10 = -30

-50-(-20) = -30

Therefor this pattern is decreasing by a rate of 30 so to continue this, just subtract 30 from -50.

-50-30 = -80

The next term is -80.

Hope I helped!

It should be B because all of them subtract 30...

What is the value of x?
a . 75
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Answers

Answer:

d. 4.5

Step-by-step explanation:

10x-5=16x+22

    -22      -22

10x-27=16x

-10x      -10x

-27=6x

x=4.5

The answer is d 4.5

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Answer:

106

Step-by-step explanation:

all 3 of the angles add up to 360

you already know one is 164 and one is a right angle so

164 + 90 = 254

360 - 254 = 106

The equation of the scatter plot trend line is y = -1700x + 32000 where y is the value of the car in dollars and x is the age of cars in years. Use the trend line equation to predict the value of a car after 7 years.

Answers

Answer:

20100

Step-by-step explanation:

According to the scenario, computation of the given data are as follows,

Given equation

y = -1700x + 32000

Where x is the age of car and y is the value of the car.

Then value after 7 years can be calculated as follows,

y = -1700 (7) + 32000

y = -11900 + 32000

y = 20,100

So, the value of car after 7 years will be 20100.

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Answers

Answer:

Step-by-step explanation:

10 times 10 times 60 = 6000

6000 - (1600 + 2000) = 2,400

Answer:

7200 [tex]in^3[/tex]

Step-by-step explanation:

volume of the bottom + volume of the middle part + volume of the top part (I'm sorry this is so vague T-T)

[tex](8*60*10)+(2*40*10)+(8*20*10)= 4800+800+1600=7200[/tex]

A man travels 2 miles, turn left and travels 3 miles, turn left again and travel 6 miles. How far is he from the starting point?​

Answers

Answer: 5 miles

Step-by-step explanation:

this creates a polygon which can be shortened to be a triangle with side lengths 3 and 4 and the hypotenuse unknown. to find the side length you use the formula a^2 + b^2 = c^2

3^2 + 4^2 = c^2

9 + 16 = c^2

25 = c^2

sqrt(25) = c

c = 5

what is the sale price of $149 sneakers with 15% off?

Answers

Answer:  $ 126.65

Step-by-step explanation:

149/100)*15 =

(149*15)/100 =

2235/100 = 22.35

15% of $149 is 22.35

so ,

   real price-15% of real price= sale preice

  $149-$22.35=$126.65

Answer:

$ 126.65

Step-by-step explanation:

$ 149 multiply 15 % which is 0.15

Which is $ 22.35

Take $ 149 - $22.35 = $126.65

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Answers

Answer:

isosceles triangle

Step-by-step explanation:

the first one is isosceles triangle

Please help me so i don't fail :(

Answers

Answer:

y = 2x + 6

Step-by-step explanation:

slope-intercept form => y = mx + b

substitute two of the (x, y) into the equations: y = mx + b  to solve for m and b

=> 0 = -3m + b, 6 = 0m + b

6 = 0m + b => b = 6

substitute b = 6 into 0 = -3m + b to solve for m:

=> 0 = -3m + 6 => -3m = -6 => m = 2

plug in b = 6 and m = 2 into the equation y = mx + b:

=> y = 2x + 6

Answer is y= 2x+6 hope it helps:)

Please someone help I need to turn this in soon !!

Answers

Answer:

6

Step-by-step explanation:

18/3=6

Match the equivalent expressions.



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Answer:

1/9 = 3^-2

1/8 = 2^-3

9 = 3²

8 = 2³

2x-2y>6 in y=Mx+b form

Answers

Answer:

y=−x+3

Step-by-step explanation:

The slope-intercept form is y=mx+b, where m is the slope and b

is the y-intercept.

y=mx+b

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