a sprinter starting from rest reaches final velocity of 18.0 mi/h. What is her average velocity?

Answers

Answer 1

Answer:

9m/s

Explanation:

Average velovity= (Initial velocity+Final velocity)/2

or A.V=(0+18)/2

or A.V= 9m/s

Answer 2

A sprinter starting from rest reaches final velocity of 18.0 mi/h. The average velocity of the sprinter is 9.0 mi/h.

Given that the sprinter starts from rest and reaches a final velocity of 18.0 mi/h, we can assume that the sprinter accelerates uniformly. Therefore, her average velocity would be the average of her initial velocity (0 mi/h) and her final velocity (18.0 mi/h).

Average velocity = (Initial velocity + Final velocity) / 2

Average velocity = (0 mi/h + 18.0 mi/h) / 2

Average velocity = 18.0 mi/h / 2

Average velocity = 9.0 mi/h

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Related Questions

an immersion heater rated 2.0A,240V is used to boil water from temperature 52°c to hundred°c. if the mass of the water is 2.5kg, determine the time taken to boil water​

Answers

Answer:

1.05 x 103s

Explanation:

The answer to the question is 1.05 x 103s

Describe how to make an electromagnet. Use the following words and phrases:

Power supply, coil of wire, current, iron core

Answers

Required items:

battery a coil of wireiron core

Electromagnet can be created by wrapping a coil of wire on top of the iron core and passing an alternating current through it with the help of power supply.

the magnetic field will be constantly changing.

Answer:

Explanation:

Unlike permanent magnet, electromagnet require a power supply to work.  The power supply drives an electric current through coil of wire wrapped around an iron core.

Compare the gravitational acceleration on the following objects compared to the Sun using:
g(star)/g(Sun) =(M(star)/M(Sun) )/〖(R(star)/R(Sun) )〗^2

Object M(star)/M(Sun) R(star)/R(Sun) g(star)/g(Sun)
White dwarf
Neutron star
Star Betelgeuse

Answers

The gravitational acceleration of White dwarf compared to Sun is 13,675.86.

The gravitational acceleration of Neutron star compared to Sun is 6.79 x 10⁻²⁴.

The gravitational acceleration of Star Betelgeuse compared to Sun is 8.5 x 10¹⁰.

Mass of the planets

Mass of sun = 2 x 10³⁰ kg

Mass of white dwarf = 2.765  x 10³⁰ kg

Mass of Neutron star = 5.5 x 10¹² kg

Mass of star Betelgeuse = 2.188 x 10³¹ kg

Radius of the planets

Radius of sun = 696,340 km

Radius of white dwarf = 7000 km

Radius of Neutron star = 11 km

Radius of star Betelgeuse = 617.1 x 10⁶ km

Gravitational acceleration of White dwarf compared to Sun

[tex]\frac{g(star)}{g(sun)} = \frac{M(star)}{M(sun)} \times [\frac{R(sun)}{R(star)} ]^2\\\\\frac{g(star)}{g(sun)} = \frac{2.765 \times 10^{30}}{2\times 10^{30}} \times [\frac{696,340,000}{7,000,000} ]^2\\\\\frac{g(star)}{g(sun)} = 13,675.86[/tex]

Gravitational acceleration of Neutron star compared to Sun

[tex]\frac{g(star)}{g(sun)} = \frac{M(star)}{M(sun)} \times [\frac{R(sun)}{R(star)} ]^2\\\\\frac{g(star)}{g(sun)} = \frac{5.5 \times 10^{12}}{2\times 10^{30}} \times [\frac{11,000}{7,000,000} ]^2\\\\\frac{g(star)}{g(sun)} = 6.79\times 10^{-24}[/tex]

Gravitational acceleration of Star Betelgeuse compared to Sun

[tex]\frac{g(star)}{g(sun)} = \frac{M(star)}{M(sun)} \times [\frac{R(sun)}{R(star)} ]^2\\\\\frac{g(star)}{g(sun)} = \frac{2.188 \times 10^{31}}{2\times 10^{30}} \times [\frac{617.1 \times 10^9}{7,000,000} ]^2\\\\\frac{g(star)}{g(sun)} = 8.5\times 10 ^{10}[/tex]

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The moon remains in Earth's orbit because of Earth's gravitational pull on the moon. In return, the moon exerts a gravitational pull on Earth. The mass of the moon is 0.07346 x 1024 kg and Earth's mass is 5.9724 x 1024 kg. How does the gravitational pull of Earth on the moon compare to the moon's gravitational pull on Earth?

A. Earth pulls more strongly on the moon.
B. The moon pulls more strongly on Earth.
C. The moon and Earth pull on each other with equal force.
D. There is not enough information to answer this question.

Answers

Given what we know, we can confirm that the Earth pulls more strongly on the moon, option A is correct.

Why does the Earth pull more strongly?

This has to do with the relationship between the mass of an object and its gravitational pull. These values are directly proportional, the more massive an object is, the stronger the gravitational pull that object exhibits. The moon does pull on the Earth as well, however, due to its smaller mass, it does not pull as strongly as the Earth on the moon.

Therefore, we can confirm that the Earth pulls more strongly on the moon, which means that option A is the correct choice for this question.

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Please answer this question. Thank you and have a fruitful day.

Answers

#Up

The upward force is caused by floating equipments attached below in ship to make it float.

#Down

Weight or acceleration due to gravity

F=mg

#Right

The drag force or friction from water surface

#Left

Force of motor to go ahead

A plane took from Chicago to Paris 8 h to finish a journey. If the distance of the journey was 6600 km, at what average speed did the plane travel​

Answers

Answer:

825 km/hr

Explanation:

To find the average speed, you simply have to divide the distance by the time taken.

Distance travelled = 6600 km

Time Taken: 8 hours

Average speed = 6600 ÷ 8 or 6600/8 = 825 km/hr

Your final answer would be the plane travelled at an average speed of 825 kilometres per hour.

A spring that can be assumed to be ideal hangs from a stand, as shown above. The spring constant, k, of an ideal spring is defined as the force per unit length and differs from one spring to another. It can be measured in both a static (motionless) and dynamic (in motion) mode A You wish to determine experimentally the spring constant k of the spring in a static (motionless) situation What additional, commonly available equipment would you need? ü What measurements would you make? m. How would k be determined from these measurements? 1 B. You wish to determine experimentally the spring constant k of the spring in a dynamic (moving) situation. What additional, commonly available equipment would you need? What measurements would you make C. Assume that the spring constant is determined to be 500 N/m A 20 kg mass is attached to the lower end of the spring and released from rest. Determine the frequency of oscillation of the mass

Answers

(a) The additional commonly available equipment you would need is stop watch.

(b) The measurement obtained with stop watch is period of oscillation. The period of oscillation can be used to determine angular speed and the angular speed is used to determine the spring constant.

(c) The frequency of oscillation of the mass is 0.8 Hz.

Value of spring constant from experiment

The value of spring constant can be determined experimentally with a mass and stop watch to record the period of oscillation.

How to calculate spring constant

k = ω²m

where;

ω is angular speed = 2πf = 2π/Tm is mass

With a known mass attached to the spring, the period of the oscillation can be determined using stop watch. The period of the oscillation can be used to determine the frequency and angular speed of the oscillation. The angular speed can be used to determine the spring constant, K.

Frequency of the oscillation

ω² = K/m

ω² = 500/20

ω² = 25

ω = √25

ω = 5 rad/s

ω = 2πf

f = ω/2π

f = 5/2π

f = 0.8 Hz

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while flying to Tucson, Mr H's plane experiences mild turbulence, causing the coffee to oscillate back and forth in his cup 4 times each second. if the coffee waves have a wavelength of 0.1m, what is their velocity across the surface?​

Answers

This question involves the concepts of wavelength, frequency, and velocity.

The velocity across the surface is "0.4 m/s".

Wave Speed

The velocity of the wave can be found using the following formula:

[tex]v=f\lambda[/tex]

where,

v = velocity = ?f = frequency = 4 Hzλ = wavelength = 0.1 m

Therefore,

v = (4 Hz)(0.1 m)

v = 0.4 m/s

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Kraig pulls on a rope attached to a box with a mass of 500kg to the right at an angle of 40 degrees to the horizontal with a force of 30 N for 150 seconds. The box does not move from its’ original position, determine the work done by Kraig.

Answers

Answer:

zero

Explanation:

The box does not move from its’ original position, so the displacement is zero, then the work done is zero.

which of these will NOT help reduce c02 levels in the atmosphere?

Answers

Answer:

the answer would be "using more heat" btw

Explanation:

Consider a proton travelling due west at a velocity of 5×10^5m/s. Assuming that the rth magnetic field has a strength of 5x10^-5Tand is directed due south calculate li) the magnitude of the force on the proton (q= 1.6x10^-9C)​

Answers

Answer:

Consider a proton travelling due west at a velocity of 5×10^5m/s. Assuming that the rth magnetic field has a strength of 5x10^-5Tand is directed due south calculate li) the magnitude of the force on the proton (q= 1.6x10^-9C)​

Explanation:

What is the change in the momentum of a 1,600 kg car if its
velocity goes from 20 m/s to O m/s?
a -32,000 kg.m/s
b 32,000 kg-m/s
C 16,000 kg.m/s
d -20 m/s ka.m/s

Answers

Answer:

As Per Provided Information

Mass of car is 1600 Kg Initial velocity 20 m/sFinal velocity 0m/s

we have been asked to determine the change in momentum .

Formula Used

[tex] \bf\Delta \: p = m \: \times \Delta \:v[/tex]

Put the given value we obtain

[tex] \rm \qquad \dashrightarrow \Delta \: p \: = 1600 \times (0 - 20) \\ \\ \\ \rm \qquad \dashrightarrow \Delta \: p \: = 1600 \times ( - 20) \\ \\ \\ \rm \qquad \dashrightarrow \Delta \: p \: = - 32000 \: kgm {s}^{ - 1} [/tex]

Hence,

Change in momentum is -32000Kgm/s .

So, correct option is (a) -32000 Kgm/s.

The change in the momentum of a 1,600 kg car if its velocity goes from 20 m/s to O m/s  is -32000 Kg-m/s.

What is Momentum?

The meaning of MOMENTUM is a property of a moving body that the body has by virtue of its mass and motion and that is equal to the product of the body's mass and velocity. Momentum is vector quantity.

Given in the question

Mass of car is 1600 Kg

Initial velocity 20 m/s

Final velocity 0 m/s

we have been asked to determine the change in momentum

Momentum = mass*(change in velocity)

                   = 1600(0 - 20)

                   =  -32000 Kg-m/s

The change in the momentum of a 1,600 kg car if its velocity goes from 20 m/s to O m/s is  -32000 Kg-m/s.

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You want to build a generator to light a bulb. You have a fairly large permanent magnet, some wire, and a lightbulb. You may build it as follows. Wind the wire for about 200 turns into a coil of 15 cm radius. Tape up the coil and place it in the region between the poles of the magnet that produces a 0.10 T magnetic field. Connect a hand crank to the coil and rotate it at a rotational speed ω.

What is the required rotational speed ω to generate a peak voltage of 6 V?

Answers

The required rotational speed ω to generate a peak voltage of 6 V is 4.24 rad/s

The induced peak voltage

The induced peak voltage in the generator is given by ε = NABω where

N = number of turns of coil = 200, A = area of coil = πr² where r = radius of coil = 15 cm = 0.15 m, B = magnetic field strength = 0.10 T and ω = rotational speed of coil

Rotational speed

Making ω subject of the formula, we have

ω = ε/NAB

ω = ε/Nπr²B

Substituting the values of the variables into the equation, we have, given that ε = 6 V

ω = ε/Nπr²B

ω = 6 V/(200 turns × π(0.15 m)² × 0.10 T)

ω = 6 V/(200 turns × 0.0225π m² × 0.10 T)

ω = 6 V/(200 turns × 0.0225π m² × 0.10 T)

ω = 6 V/0.45π turns-m²T

ω = 6 V/1.4137 turns-m²T

ω = 4.244 rad/s

ω ≅ 4.24 rad/s

The required rotational speed ω to generate a peak voltage of 6 V is 4.24 rad/s

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When light is incident through the focal point, and then strikes a mirror, ___ the light will reflect parallel to the principal axis the light will reflect back through the focal point the light will not reflect at all

Answers

When light is incident through the focal point and allow to strike a mirror, the light will be reflected back parallel to the principal axis.

What is reflection of light?

The reflection of light occurs when all the incident light falls back when it hit a plane surface like mirror. In this process the light will be thrown back by the mirror without absorbing it.

Reflection of light when it strikes a mirror

When light is incident through the focal point and allow to strike a mirror, the light will be reflected back parallel to the principal axis.

Thus, the incident light will reflect parallel to the principal axis.

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A ballon is rubbed against a sweater. Which of the following describes the result of this interaction?

Answers

A balloon is rubbed against a sweater. Which of the following describes the result of this interaction? Answer: The fibers of the sweater lose electrons.

Answer:

static could form and The balloon becomes positively charged

Explanation:

Science

_________________ usually have larger amplitudes and longer wavelengths.

A. Surface waves

B. Transverse waves

C. Compression waves

D. Longitudinal waves

Answers

Answer:

longitudinal wave

i guess

sry if its wrong

An undersea research chamber is spherical with an external diameter of 6.20 m. The mass of the chamber, when occupied, is 60400 kg. It is anchored to the sea bottom by a cable. The density of sea water is 1025 kg/m3. Calculate the following: (express your answers using appropriate mks units.)

(a) the buoyant force on the chamber

(b) the tension in the cable

Answers

I think the answer is b

A 6.0 x10^-2 kg tennis ball moves at a velocity of 12 m/s. The ball is struck by a racket, causing it to rebound in the opposite direction at a speed of 18 m/s. What is the change in the ball’s momentum?

Answers

Δp = m(v₂-v₁)

v₁ = 12 m/s

v₂ opposite direction = - (negative sign) = -18 m/s

Δp = 6.10⁻² (-18-12)

Δp = -1.8 Ns

Which of the following is correct when convection occurs in the atmosphere?
A


Cool air rises and warm air sinks.

B


Cool air sinks and warm air rises.

C


Cool and warm air sink.

D


Cool and warm air rise.

Answers

Answer:

Cool air sinks and warm air rises.

Explanation:

Cool air sinks and warm air rises

What are the first three harmonics of a note produced on a 0.31 m long violin string if the waves on this string have a speed of 274.4 M/s. what is the length of the pipe

Answers

Is that what you are looking for?

N2O is the chemical formula of a covalent compound used in the production of whipping cream. The elements that
make up this compound are nitrogen and oxygen.

What is the name of the second element in the chemical name of this compound?

Answers

N₂O: Nitrous oxide

oxygen

build three straight ramps on the stage one ramp should be nearly flat and another should be extremely steep the last ramp should have a steepness somewhere in between

Answers

Answer:

hope this helps

Explanation:

The ramps to be constructed are straight ramps. So, their lengths must be straight.

What is meant by an incline ?

An incline or inclined plane is defined as a plane or flat surface that is tilted at a particular angle and the incline have one end higher than other.

Here,

The inclined plane or a ramp can be considered as a simple machine used for raising heavy objects through its steeper surface.

Three ramps are to be constructed that are having the configurations of straight run such that one of them should be constructed nearly flat.

The other one is to be constructed in a way that its slopping surface must be extremely steeper.

The last one is constructed such that the sloping surface have a steepness somewhere in between the other two.

Since the ramps to be constructed are straight ramps, their lengths must be straight.

Hence,

The ramps to be constructed are straight ramps. So, their lengths must be straight.

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Attaching the image here

What will happen to this force if the distance between the charges is doubled and the -4μC is cut in half ? Use proportional reasoning to find the answer and then check by changing and moving the charges.

Answers

Answer: MIS huevos

Explanation:

my sources

6. How much heat is absorbed by a persons hand if 100 grams of liquid water at 100°C is poured on his hand? (Assume the final temperature of the water will be normal body temperature of 37°C)

Answers

The heat absorbed by a persons hand is 26,359.2 J.

Heat absorbed

The quantity of heat absorbed by the persons hand is heat gained or transferred from the hot water to cold hand. This is based on the principle of conservation of energy.

The quantity of heat absorbed is calculated as follows;

Q = mcΔθ

where;

Q is the quantity of heat absorbedm is mass of the liquidΔθ is change in temperature

Q = 100 x 4.184 x (100 - 37)

Q = 26,359.2 J

Thus, the heat absorbed by a persons hand is 26,359.2 J.

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Use this sentence: A large tray is filled with flour and a fan is turned on so that it blows wind across the top.

Which natural process is this modeling?

(1 point)


physical weathering (i picked this)

chemical weathering


erosion


deposition

Answers

Answer: Physical weathering

Explanation:

1) If the red motorcycle and the blue motorcycle have the same speed but the red one has more mass, which one has more momentum? explain

Answers

Answer:

The blue motorcycle.

Explanation:

The red one, since it has more mass, meaning it is denser, would drag on less. Less mass equals more momentum, since there is less holding it down.

why a drop of spirit on the hand feels colder than a drop of water at the same temperature​

Answers

Answer:

This is because spirit has a lower boiling point when compared to water

Explanation:

spirit has a lower boiling point when compared to water which means it has the capacity to pull more heat from your hand and also it can do this very fast. This is why our hand feels colder.

Following extinction , when the conditioned response (cr) gains strength again , we say it has been
A. Generalized
B. Discriminated
C. Spontaneously recovered
D. Initially inhibited

Answers

Answer:

C. Spontaneously covered

Explanation:

what is the force in kN of work done is 1.2 ms moves through 120m​

Answers

Answer:

work done = force x distance

1.2 = f x 120

1.2 = 120f

f = 0.01N

hope its helps!

Write a script that depicts an employer meeting expectation and failing meeting expectations

Answers

Answer: On Monday, XX/XX, the XXXX you presented in our weekly review were not accurate and I’m worried that this reflected poorly on our team’s credibility. This could negatively impact senior leadership’s confidence in our team’s effectiveness at a time when headcount is already being scrutinized and potentially eliminated. Next time you present XXXX, my expectation is that everything will have been double or triple-checked in advance of the meeting so that all figures are reported accurately.

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