A man plans on making a large speculative investment in a new company. There is a 20% chance that the company will lose $250,000, a 50% chance of a break even, and a 30% chance of a $150,000 profit. Based ONLY on this information, what should the man do?.

Answer:

[tex]2x = 53 - 3y \\ x = \frac{53 - 3y}{2} \\ y = \frac{53 - 2x}{3} [/tex]

Answer:

the answer for d question is 10

Answer:

Multiply vector c by the scalar -1/2.

Step-by-step explanation:

Look at vector c.

It has an x component of 4 and a y component of 4.

You can write vector c as a sum of its components using unit vectors in the x direction (i) and in the y direction (j).

c = 4i + 4j

Now look at vector d, and write it also as a sum of its x and y components.

d = -2i - 2j

Now ask yourself, what operation do I do to 4 to end up with -2?

One answer is to multiply 4 by -1/2.

d = (-1/2)c = (-1/2)(4i) + (-1/2)(4j) = -2i - 2j

That worked. By multiplying vector c by the scalar -1/2, you end up with vector d.

Solution (1):

Note that:

This means that...

Finding the value of x.

Solution (2):

Note that:

This means that...

Finding the value of x.

Answer:

x²⁰y⁷

____

2

Step-by-step explanation:

multiply

combine exp

cancel terms

combine multiplied terms

combine exp

Answer:

The first one is: -2xy+7x

The second one is: 12x+9y

Number one is a little weird in how you put it, but I hope this helps!

Answer:

ANSWER (A.

Step-by-step explanation:

HOPE IT HELP'S !

Given :

To Find :

Solution :

Area of the outer circle :

[tex]\: \qquad \dashrightarrow \sf{{ \pi \: \times {(490)}^{2} {m}^{2}}} [/tex]

[tex]\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{7} \times \:490 \times 490 \: {m}^{2}}} [/tex]

[tex]\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{ \cancel{7}} \times \cancel{490} \times 490 \: {m}^{2}}} [/tex]

[tex]\: \qquad \dashrightarrow \sf{{ \ {22} \times 70 \times 490 \: {m}^{2}}} [/tex]

[tex]\: \qquad \dashrightarrow \bf{{ \ 754600 \: {m}^{2}}} [/tex]

⠀

Area of the inner circle :

[tex]\: \qquad \dashrightarrow \sf{{ \pi \: \times {(210)}^{2} {m}^{2}}} [/tex]

[tex]\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{7} \times \:210 \times 210 \: {m}^{2}}} [/tex]

[tex]\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{ \cancel{7}} \times \cancel{210} \times 210 \: {m}^{2}}} [/tex]

[tex]\: \qquad \dashrightarrow \sf{{ \ {22} \times 30 \times 210 \: {m}^{2}}} [/tex]

[tex]\: \qquad \dashrightarrow \bf{{ \ 138600 \: {m}^{2}}} [/tex]

⠀

Therefore,

Area of the region inside the circular paths :

[tex]\: \qquad \dashrightarrow \sf{{ \ (754600 - 138600 ) \: {m}^{2}}}[/tex]

[tex]\: \qquad \dashrightarrow \bf{{ \ 616000 \: {m}^{2}}}[/tex]

Answer:

90 In

Step-by-step explanation:

12 x 7 = 84

12 x 1/2 = 6

84 + 6 = 90

2x - 5y = 1

We need to group all the variable terms on one side and all the constant terms on the other side of the equation. Therefore move the term -5y to the other side of equation.

[tex]\rm{2x - 5y = 1 }\\ [/tex]

[tex] \rm{2x - 5y + 5y = 1 + 5y}\\[/tex]

Subtract -5y from both sides of the equation

Simplify 2x - 5y + 5y = 1 + 5y

Cancel -5y with 5y

Reorder 1 + 5y so highest order terms are first

[tex] \rm{x = \frac{5y + 1}{2} } \\ [/tex]

Move factors not having X from the left side of equation 2x = 5y + 1

[tex] \rm{ \frac{2x}{2} = \frac{5y + 1}{2} } \\ [/tex]

Divide both sides of equation 2x = 5y + 1 by 2

Cancel 2 with 2

[tex] \rm{ \frac{\cancel{2}x}{\cancel{2}} = \frac{5y + 1}{2} } \\ [/tex]

[tex] \rm{x = \frac{5y + 1}{2} } \\ [/tex]

Therefore, the x of 2x - 5y = 1 is [tex] \rm{ \frac{5y + 1}{2} } [/tex]

2x - 5y = 1

[tex]\rm{-5y + 2x = 1}\\ [/tex]

Reorder 2x -5y so highest order terms are first

-5y = -2x + 1

We need to group all the variable terms on one side and all the constant terms on the other side of the equation. Therefore move the term 2x to the other side of equation -5y + 2x = 1

[tex]\rm{-5y + 2x - 2x = 1 - 2x}\\[/tex]

Subtract 2x from both sides of the equation

Simply - 5y + 2x -2x = 1 - 2x

Cancel 2x with -2x

Reorder 1 - 2x so highest order terms are first

[tex] \rm{y = - \frac{2x + 1}{5} }\\[/tex]

Move factors not having y from the left side of equation -5y = -2x + 1

[tex]\rm{ \frac{ - 5y}{ - 5} = \frac{ - 2x + 1}{ - 5} }\\ [/tex]

Divide both sides of equation -5y = -2x +1 by -5

Simplify [tex]\rm{ \frac{ - 5y}{ - 5} = \frac{ - 2x + 1}{ - 5} } [/tex]

Cancel 5 with -5

Resolve sign on fraction [tex] \rm{\frac{ - 2x + 1}{ - 5} }[/tex]

Therefore, the y of 2x-5y = 1 is [tex]\rm{\frac{ - 2x + 1}{ - 5} } [/tex]

3x + 2y = 11

We need to group all the variable terms on one side and all the constant terms on the other side of the equation. Therefore move the term 2:y to the other side of equation 3 x + 2y - 2y = 11 - 2y

Subtract 2y from the both sides of the equation

Simplify 3x + 2y - 2y = 11 - 2y

Cancel 2y with 2y

Reorder 11 - 2y so highest order terms are first

[tex] \rm{x = \frac{2y + 11}{3} } \\ [/tex]

Move the factors not having x from the left side of equation 3x = -2y +11

[tex] \rm{ \frac{3x}{3} = \frac{-2y + 11}{3} } \\ [/tex]

Divide both sides of equation 3x = 2y + 11 by 3

Cancel 3 with 3

[tex] \rm{ \frac{\cancel{3}x}{\cancel{3}} = \frac{-2y + 11}{3} } \\ [/tex]

[tex] \rm{x = \frac{2y + 11}{3} } \\ [/tex]

Therefore, the x for 3x + 2y = 11 is [tex] \rm{ \frac{2y + 11}{3} } [/tex]

2y + 3x = 11

Reorder 3x + 2y so highest order terms are first

[tex]\rm{2y + 3x = 11}\\[/tex]

We need to group all the variable terms on one side and all the constant terms on the other side of the equation. Therefore move the term 2:y to the other side of equation 2y + 3x = 11

[tex]\rm{2y + 3x - 3x = 11 - 3x}[/tex]

Subtract 3y from the both sides of the equation

Simplify 2y + 3x - 3x = 11 - 3x

Cancel 3x with - 3x

Reorder 11 - 3x so highest order terms are first

[tex] \rm{y= - \frac{3x + 11}{3} } \\ [/tex]

Move factors not having y from the left side of equation 2y = -3x + 11

[tex] \rm{ \frac{2y}{2} = \frac{-3x + 11}{3} } \\ [/tex]

Divide both sides of equation 2y = -3x + 11 by 2

Cancel 2 with 2

[tex] \rm{ \frac{\cancel{2}y}{\cancel{2}} = \frac{-3x + 11}{3} } \\ [/tex]

[tex] \rm{y = \frac{-3x + 11}{3} } \\ [/tex]

Therefore, the y for 2y + 3x = 11 is [tex] \rm{ \frac{-3x + 11}{3} } [/tex]

Answer: Parallelogram Opposite Sides Converse

Step-by-step explanation:

There are 2 pairs of opposite congruent sides.

Answer:

true false false true true

Answer:

Approximately 1.6

Step-by-step explanation:

To graph. a function, let use desmos or graphing calculator.

Here the function.

The length of the pendulum as shown here when x=2, is 1.6

Answer:

good luck

Step-by-step explanation:

I do not remember

Answer:

The bottle with 1.25quarts is the better bargain because a quart is the same thing as 2pints

Answer:

HOP IT HELPS

3/8=1.5/4

because when you divide

3÷2 and 8÷2

you get

1.5/ 4

Answer:

1/2

Step-by-step explanation:

3/8 to the nearest 1/2.

The question wants to know if you round 3/8 to the nearest half, what value would that be?  On a number line from 0 to 1, we could mark every 1/8 unit:

0/8==1/8==2/8==3/8==4/8==5/8==6/8==7/8==8/8

Note that 0/8 is 0, 4/8 is 1/4 and 8/8 is 1.

3/8 is one step from 4/8, or 1/2.  So the nearest half would be 1/2.

[tex]\underline{\underline{\large\bf{Solution:-}}}\\[/tex]

[tex]\longrightarrow[/tex]Since angle X and Y have a sum of 159

[tex]\implies \bf Y + X= 159 \_\_\_\_(1) [/tex]

[tex]\longrightarrow[/tex]Since X is 43 degrees smaller than Y , so subtracting X from Y would give 43 , therefore equation will be written as -

[tex]\implies \bf Y - X = 43 \_\_\_\_(2) [/tex]

Adding Equation (1) and (2)

[tex]\begin{gathered}\\\implies\quad \sf Y+X+Y-X = 159+43 \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \sf Y+Y + X-X = 202 \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \sf 2Y = 202 \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \sf Y = \frac{202}{2} \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \boxed{\sf {Y = 101 }} \\\end{gathered} [/tex]

Putting Y in eq (1)

[tex]\begin{gathered}\\\implies\quad \sf X + 101 = 153 \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \sf X = 153-101 \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \boxed{\sf{ X = 52 }}\\\end{gathered} [/tex]

Answer: C 30X

Step-by-step explanation:

Answer:

12

Step-by-step explanation:

Answer:

-x + 5y = 15

Step-by-step explanation:

Hello! This question simply asks us to rearrange the equation.

So we have this:

y - 2 = 5(x + 5)

Okay, so we need to get an answer with integers for x and y, but no brackets. This means we can start by expanding them:

5y - 10 = x + 5

now, let's put y and x on the same side of the equation, and numbers on the other side:

5y - x = 5 + 10

5y - x = 15

we can put x first, but it's not necessary:

-x + 5y = 15

A = -1

B = 5

C = 15

And that's it!

I hope this makes sense :))

Answer:

5x - y = - 27

Step-by-step explanation:

the equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

given

y - 2 = 5(x + 5) ← distribute parenthesis

y - 2 = 5x + 25 ( add 2 to both sides )

y = 5x + 27 ( subtract 5x from both sides )

- 5x + y = 25 ( multiply through by - 1 )

5x - y = - 27 ← in standard form

Step-by-step explanation:

[tex]V = \frac{ER}{R + a} [/tex]

[tex]V(R+a)=ER[/tex]

[tex]VR + Va=ER[/tex]

[tex]Va= ER-VR[/tex]

[tex]Va=R(E-V)[/tex]

[tex]R = \frac{Va}{E-V} [/tex]

Answer:

9

Step-by-step explanation:

Answer:

9

Step-by-step explanation:

14%= 18

1%= [tex]\frac{18}{14}[/tex]

7%= [tex]\frac{18}{14}[/tex] x 7

    = [tex]\frac{18}{2}[/tex]

    = 9

Answer:

Step-by-step explanation:

Answer:

1.  (3/2)

2. (20)

3. (3)

4. (-9/5)

5. (-8/7)

6. (-2/3), (4)

Step-by-step explanation:

1.                          2.                        3.                          4.

x         3                   12         3               x           1                x + 3        3

/    =    /                     /     =    /                /    =      /                   /     =     /

4         8                   x           5              9           x                   2           5

8x = 12                    60 = 3x                  x² = 9                      5x + 15 = 6

÷8    ÷8                   ÷3    ÷3                   x = √9                          -15     -15

                                                                                                5x = -9

x = (3/2)                   x = 20                  x = 3                           ÷5    ÷5

                                                                                                  x = (-9/5)

5.                             6.

4 - x          3                   1               x - 3

  /       =     /                   /        =        /

 12            7              2x + 1               9

28 - 7x = 36                   9 = 2x^2 - 5x - 3

-28         -28                 + 3                    + 3

                                     12 = 2x^2 - 5x

-7x = 8                          -12                   -12

÷-7   ÷-7

                                       2x^2 - 5x - 12 = 0

x = (-8/7)                      

                                       -b +-√b^2 - 4ac

                                                     /                = -(-5)√-5^2 - 4 (2)(-12)

                                                    2a                                /

                                                                                      2(2)

                                          = 5-+√121        5 - 11        -6

                                                 /         =        /       =    /       = (-2/3)

                                                -4                 4             4

                                                            =     5 + 11          16

                                                                       /      =       /    = (4)

                                                                      4              4

I hope this helps!

Answer:

Step-by-step explanation:

Given : points 4  , 1 ,25  , opposite of 3 ,  -1/2

To Find : draw on Number Line

Solution :

Numbers with a negative sign are less than zero

Right of zero represented by ‘+’ sign and to the left of zero represented by ‘–’ sign.

+ sign numbers can be denoted as simply numbers  

On a number line the number increases as we move to the right and decreases as we move to the left.  

1 : Draw a line and mark some points at equal distance on it as shown in the figure below  Mark a point as zero on it. Points to the right of zero are positive integers and are marked simply 1, 2, 3  and so on , while points to the left of zero are negative integers and are marked – 1, – 2, – 3 and so on

2.  Go 4 unit on right sides from Zero   to show  4

3.  Go 3 units on Left from zero to show opposite of 3

4.  Divide number line between 1 & 2 in 4 Equal parts and go 1 part right of 1

5.  Divide number line between  0 & -1  in 2 Equal parts and go 1 part left of 0

give brainliest.

50 times; 40% A

2/5(50) = A

A = 20

Answer:

50 times; 40% A

2/5(50) = A

A = 20

Step-by-step explanation:

Answer:

64°

.

.........................

Answer:

-6

Step-by-step explanation:

-1 * 2 * 3

= -2 * 3

= -6

Answer:

-1 x 2 = -2

-2 x 3 = -6

Answer:

-6

Answer:

a

Step-by-step explanation:

arc length is calculated as

arc = circumference × fraction of circle

     = 2πr × [tex]\frac{110}{360}[/tex]

     = 2π × 4 × [tex]\frac{11}{36}[/tex] ( cancel 4 and 36 by 4 )

     = 2π × [tex]\frac{11}{9}[/tex]

     = [tex]\frac{22}{9}[/tex] π inches