A football thrown by a professional quarterback goes farther than one thrown by a 10-year old. What Newton Law is this?

Answer:

P since without a host the parasite won't be able to survive they would start decreasing as well but if the hosts were no more then they would go extinct. But since it is just decreasing then it should be P

Answer:

False.

Explanation:

An aurora is a natural electric phenomenon that creates bright and colorful light displays in the sky. These dramatic and colorful lights are created when electrically charged particles from solar winds enter the Earth's atmosphere and interact with gases in the atmosphere.

Answer:

74.88N

Explanation:

From the question,

F = ma................... Equation 1

Where F = force exerted on the ball, m = mass of the ball, a = acceleration

But,

v² = u²+2as.............. Equation 2

Where v = final velocity, u = initial velocity, s = distance.

Given: v = 12 m/s, u = 0 m/s (from rest), s = 5.0 m

Substitute into equation 2 and solve for a

12² = 0²+2×a×5

144 = 10a

10a = 144

a = 144/10

a = 14.4 m/s²

Also Given: m = 5.2 kg,

Substitute into equation 1

F = 5.2×14.4

F = 74.88 N

Hence the force exerted on the ball is 74.88 N

Solution :

Given :

Force, F = 500 N

Let [tex]$ \vec F = F_x\ \hat i + F_y\ \hat j$[/tex]

      [tex]$|\vec F|=\sqrt{F_x^2+F_y^2}$[/tex]

∴ [tex]$F_x=F \cos 60^\circ = 500 \ \cos 60^\circ = 250 \ N$[/tex]

  [tex]$F_y=-F \cos 30^\circ = -500 \ \cos 30^\circ = -433.01 \ N$[/tex]   (since [tex]$F_y$[/tex] direction is in negative y-axis)

[tex]$F=250 \ \hat i - 433.01 \ \hat j$[/tex]

So scalar components are : 250 N and 433.01 N

     vector components are : [tex]$250 \ \hat i$[/tex] and [tex]$-433.01\ \hat j$[/tex]

1.  Scalar components along :

 x' axis = 500 N, since the force is in this direction.

 [tex]$F_{x'}= F \ \cos \theta = 500\ \cos \theta$[/tex]

  Here, θ = 0° , since force and axis in the same direction.

So, cos θ = cos 0° = 1

∴ [tex]$F_{x'}=500 \times 1=500\ N$[/tex]

[tex]$F_{y'}= F \ \sin \theta = 500\ \sin 0^\circ=500 \times 0=0$[/tex]

[tex]$F_{y'}=F\ cos \theta$[/tex] but here θ is 90°. So the force ad axis are perpendicular to each other.

[tex]$F_{y'}=F\ \cos 90^\circ= 500 \ \cos 90^\circ = 500 \times 0=0$[/tex]

∴ [tex]$F_{x'}= 500\ N \text{ and}\ F_{y'}=0\ N$[/tex]

2. Scalar components of F along:

x-axis :

[tex]$F_x=F\ \cos \theta$[/tex],   here θ is the angle between x-axis and F = 60°.

[tex]$F_x=500 \times \cos60^\circ=250\ N$[/tex]

y'-axis :

[tex]$F_{y'}=F\ \cos \theta$[/tex],   here θ is the angle between y'-axis and F = 90°.

[tex]$F_{y'}=500 \times \cos90^\circ=500\times 0=0\ N$[/tex]

∴ [tex]$F_{x}= 250\ N \text{ and}\ F_{y'}=0\ N$[/tex]

Explanation:

transfer to babes are always at your advice by a particular motion being a particular wave motion along didn't wave is a wave which particular is a medium move a direction parallel to the direction of the wave moves something that is similar in the surveys on the medium moves of the same direction and bathe an accident to one or two Dimensions do in London killing babe attacks in one dimension and transverse waves attacks in two Dimensions the Waze cannot be paralyzed or organized

Answer:

Valence electrons are outer shell electrons with an atom and can participate in the formation of chemical bonds. In single covalent bonds, typically both atoms in the bond contribute one valence electron in order to form a shared pair. The ground state of an atom is the lowest energy state of the atom.

Answer:

ij

Explanation:

Answer:

The SI unit of time is second (s) and temperature is Kelvin (K)

Explanation:

hope it is helpful to you

Answer:

 α = 2.13 10⁻⁵ C⁻¹    ,  the closest material is ALUMINUM

Explanation:

The expression for thermal expansion is

          ΔL = α L₀ ΔT

temperatures are

         ΔT = 85 - 10 = 75 ° C

the length of the rod is L₀ = 125 m and L_f = 125.20 m

        ΔL = 125.20 - 125 = 0.20 m

        α = [tex]\frac{1}{L_o} \frac{\Delta L }{\Delta T}[/tex]

        α = [tex]\frac{ 1}{125} \ \frac{0.20 }{75}[/tex]

        α = 2.13 10⁻⁵ C⁻¹

When reviewing the table, the closest material is ALUMINUM

Answer:

  I = 1.8 N s,  it is directed towards the right  

Explanation:

For this exercise we use the relationship between momentum and moment

         I = Δp

         F t = p_f - p₀

in this case the initial velocity is v₀ = - 2,0 m / s and final velocity v_f = 10,0 m / s, we assume the positive right direction

          I = m (v_f - v₀)

let's calculate

         I = 0.150 (10.0 - (-2.0))

         I = 0.150 (10 + 2)

         I = 1.8 N s

as the impulse is positive it is directed towards the right

Answer:

1.63 A and in clockwise direction

Explanation:

The magnetic field due to the rectangular loop is :

[tex]$B=\frac{2 \mu_0 I}{\pi}\left(\frac{\sqrt{L^2+W^2}}{LW}\right)$[/tex]

Given : W = 4.20 cm

                [tex]$=4.20 \times 10^{-2} \ m$[/tex]

            L = 9.50 cm

               [tex]$= 9.50 \times 10^{-2} \ m$[/tex]

            [tex]$B = 3.40 \times 10^{-5} \ T $[/tex]

   Rearranging the above equation, we get

[tex]$I=\frac{B \pi LW}{2 \mu_0\sqrt{L^2+W^2}}$[/tex]

[tex]$I=\frac{(3.40 \times 10^{-5}) \pi(9.50 \times 10^{-2})(4.20 \times 10^{-2})}{2(4 \pi \times 10^{-7})\sqrt{(9.50 \times 10^{-2})^2+(4.20 \times 10^{-2})^2}}$[/tex]

I = 1.63 A

So the magnitude of the current in the rectangular loop is 1.63 A.

And the direction of current is clockwise.

Answer:

It’s the product of 7 x 7. The square root of 49 is 7

Explanation:

It’s the product of 7 x 7. The square root of 49 is 7

The distance - time graph of the humming bird is missing, so i have attached it.

Answer:

Instantaneous velocity = 0.5 m/s

Explanation:

From the attached graph, at time t = 1 s, the corresponding distance is 0.5 m.

Instantaneous velocity is the velocity at that point.

Thus;

Instantaneous velocity = 0.5/1

Instantaneous velocity = 0.5 m/s

Answer:

2

Explanation:

wave length is the distance between corresponding points of two consecutive waves

3. hertz

Answer:

2.5 m/s²

Explanation:

Given,

Initial speed ( u ) = 10 m/s

Final speed ( v ) = 20 m/s

Time ( t ) = 4 seconds

To find : Acceleration ( a ) = ?

Formula : -

a = ( v - u ) / t

a = ( 20 - 10 ) / 4

= 10 / 4

= 5 / 2

a = 2.5 m/s²

Therefore,

The acceleration of the scooter is 2.5 m/s²

Answer:

they all need a source of oxygen

Answer:

B

Explanation:

Answer:

The torque is approximately 3.82 N·m

Explanation:

The relationship between work done, 'W', and the applied torque, 'τ' can be presented as follows;

W = τ × Δθ

Where;

W = The work done by the torque

τ = The magnitude of the torque

Δθ = The angle through which the object is turned

The parameters for 'W' and 'Δθ' are;

W = 3j

Δθ = 1/4 × π

From W = τ × Δθ, we have;

τ = W/Δθ

∴ τ = 3j/(1/4 × π) ≈ 3.81971863421 N·m

The torque, τ ≈ 3.82 N·m

Answer:

7.35..kg

Explanation:

Hope this will help you

Please,Mark me as Brainllist .

Answer:

im still in elementry so you got to do it yo self

Explanation:

so me confused

Answer:

Perpendicular ; Parallel

Answer:

D. Newton's first law

Explanation:

Newton's first law of inertia says that an object will remain how it is, unless affected by an outside force. In this case, the plates want to remain stationary(not moving). Therefore, if you pull the table cloth fast enough, the force of friction produced will be small enough so that the Inertia of the plates will overcome the force of friction.

Answer: 4276.2 calories

Explanation:

Given

mass of steam is 6 gm at [tex]100^{\circ}C[/tex]

Conversion of steam to ice involves

Calories released during the conversion of steam to water at [tex]100^{\circ}C[/tex]

[tex]E_1=mL_v\quad [L_v=\text{latent heat of vaporisation}]\\E_1=6\times 533=3198\ cal.[/tex]

Calories released during the conversion of water at [tex]100^{\circ}C[/tex] to water at [tex]0^{\circ}C[/tex]

[tex]E_2=mc(\Delta T)\quad [c=\text{specific heat of water,}1\ cal./gm.^{\circ}C]\\E_2=6\times 1\times 100=600\ cal.[/tex]

Calories released during the conversion of water to the ice at [tex]0^{\circ}C[/tex]

[tex]E_3=mL_f\quad [L_f=\text{latent heat of fusion}]\\E_3=6\times 79.7=478.2\ cal.[/tex]

The total energy released is

[tex]E=E_1+E_2+E_3\\E=3198+600+478.2=4276.2\ cal.[/tex]

300

could i get brainiest

Answer:

46.67 miles/s

Explanation:

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