A dragster starts from rest and travels 1/4 mi in 6. 70 s with constant acceleration. What is its speed in mi/h when it crosses the finish line?

Answers

Answer 1

The dragster crosses the finish line at 120.1 m/s as its final speed.

The definition of constant acceleration?

A velocity change that does not change over time is referred to as constant acceleration.

The average acceleration of an automobile remains constant at 20 mph per minute even if it increases its speed by 20 mph in one minute and then by another 20 mph the next.

The dragster was initially at rest, therefore,

Initial speed, journey distance, time spent, and final speed;

Our first step is to calculate the dragster's acceleration using the second equation of motion:

In order to change the equation to reflect our ideals,

The first equation of motion is now applied to determine the dragster's ultimate speed as it approaches the finish line:

In order to change the equation to reflect our ideals,

When a result, the dragster travels at a final speed of 120.1 m/s as it crosses the finish line.

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Related Questions

What is the distance δymax−max between the first maxima (on the same side of the central maximum) of the two patterns?

Answers

The distance between consecutive identical points on a wave, such as the space between two succeeding maxima, at a specific point in time is known as the wavelength.

Which laser's first maximum is located more near the center of the beam?The first order maximum generated by laser 1 is therefore closer to the central maximum than the first order maximum generated by laser 2. As can be seen, the distance between two successive interference maxima is constant and regardless of the observed order.The distance between consecutive identical points on a wave, such as the space between two succeeding maxima, at a specific point in time is known as the wavelength.The first order maximum generated by laser 1 is therefore closer to the central maximum than the first order maximum generated by laser 2. As can be seen, the distance between two successive interference maxima is constant and regardless of the observed order.                      

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What was the average weight of a 5’0/4’11 twelve-year-old female in 1977?

please no out out of context or absurd answers! any random answers will be deleted!!

Answers

Answer: The CDC also reports that a 12-year-old girl's weight is usually between 68 and 135 pounds, and the 50th percentile weight for girls is 92 pounds.

Explanation:

Hope its not absurd

The average weight of a 5’0/4’11 twelve-year-old female in 1977 is between 68 and 135 pounds

What is weight?

The force exerted on an object by gravity is known as the weight of the object in science and engineering. The gravitational force acting on the object is referred to as weight in some common textbooks. Some people refer to weight as a scalar quantity that measures the gravitational force's strength.

It gauges how much gravity is pulling on a body. Weight is calculated using the formula w = mg. Since weight is a force, it has the same SI unit as a force, which is the Newton (N). In this case, the weight is about 68 and 135 pounds.

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A monkey has filled in a 3 × 3 grid with the numbers 1, 2,. . . , 9. A cat writes down the three numbers obtained by multiplying the numbers in each horizontal row. A dog writes down the three numbers obtained by multiplying the numbers in each vertical column. Can the monkey fill in the grid in such a way that the cat and dog obtain the same lists of three numbers? what if the monkey writes the numbers 1, 2,. . . , 25 in a 5 × 5 grid? or 1, 2,. . . , 121 in a 11 × 11 grid? can you find any conditions on n that guarantee that it is possible or any conditions that guarantee that it is impossible for the monkey to write the numbers 1, 2,. . . , n2 in an n × n grid so that the cat and the dog obtain the same lists of numbers?

Answers

Yes, it is possible for the monkey to fill in the 3 x 3 grid in such a way that the cat and dog obtain the same lists of three numbers.

What if the monkey writes the numbers 1, 2,. . . , 25 in a 5 × 5 grid? or 1, 2,. . . , 121 in a 11 × 11 grid?For example, the monkey could fill the 3x3 grid with the numbers 1, 4, 7; 2, 5, 8; and 3, 6, 9.Yes, it is possible for the monkey to fill in the 5 x 5 grid with the numbers 1, 2, ... , 25 in such a way that the cat and dog obtain the same lists of three numbers. For example, the monkey could fill the 5x5 grid with the numbers 1, 8, 15, 22, 25; 2, 7, 16, 21, 24; 3, 6, 17, 20, 23; 4, 5, 18, 19, 12; and 9, 10, 11, 14, 13.Yes, it is possible for the monkey to fill in the 11 x 11 grid with the numbers 1, 2, ... , 121 in such a way that the cat and dog obtain the same lists of three numbers. For example, the monkey could fill the 11x11 grid with the numbers 1, 10, 19, 28, 37, 46, 55, 64, 73, 82, 121; 2, 9, 20, 27, 38, 45, 56, 63, 74, 81, 120; 3, 8, 21, 26, 39, 44, 57, 62, 75, 80, 119; 4, 7, 22, 25, 40, 43, 58, 61, 76, 79, 118; 5, 6, 23, 24, 41, 42, 59, 60, 77, 78, 117; 11, 12, 13, 14, 15, 16, 17, 18, 33, 34, 115; 10, 13, 22, 25, 34, 37, 46, 49, 68, 71, 114; 9, 14, 21, 26, 33, 38, 45, 50, 67, 72, 113; 8, 15, 20, 27, 32, 39, 44, 51, 66, 73, 112; and so on.In general, it is possible for the monkey to fill in an n x n grid with the numbers 1, 2, ... , n2 in such a way that the cat and dog obtain the same lists of numbers, provided that n is an even number. For odd numbers (n = 3, 5, 7, etc.), it is impossible for the monkey to fill in the grid in such a way that the cat and dog obtain the same lists of numbers.

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A triangle has sides with lengths of 7 meters, 14 meters, and 17 meters. Is it a right triangle?

Answers

No, it is not a right angled  triangle.

For a right angled triangle, Acc. to Pythagoras theorem:-

Hypotenuse²= Base² + Perpendicular²

Hypotenuse is the longest side of the triangle.

For the given triangle, Hypotenuse= 17

17² ≠ 14² + 7²

289 ≠245.

Hence, it is not a right angled triangle.

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