Answer:
Explanation:
There are only two forces causing motion involved. They oppose each other. You know this because there is no acceleration of the sled: you see only a velocity.
The formula when friction is involved is
Fnet = T - mu*Normal
mu is the frictional coefficient
The normal is the downward force caused by the mass of the sled being pulled down by the gravitational constant.
The tension is brought about by the dog pulling in the opposite direction to the frictional force.
The frictional force, oddly, acts in a horizontal direction even though the normal is vertical. It does this because friction always opposes motion.
Since there is no acceleration, the net force = 0
N= m * a_g
m = 1.2 kg
a_g = 9.8
N = 1.2 * 9.8
N = 11.76
The frictional force = mu*Normal Force.
Ff = N * mu
N = 11.76
mu = 0.2
Ff = 0.2 * 11.76
Ff = 2.35
As stated The frictional force and the Tension are equal but in opposite directions
T = 2.35
One ball of mass 0.600kg travelling 9.00m/s to the right collides head on elastically with a second ball of mass 0.300kg travelling 8.00m/s to the left.what are their velocities after collisions?
Let m₁ and v₁ denote the mass and initial velocity of the first ball, and m₂ and v₂ the same quantities for the second ball. Momentum is conserved throughout the collision, so
m₁ v₁ + m₂ v₂ = m₁ v₁' + m₂ v₂'
where v₁' and v₂' are the balls' respective velocities after the collision.
Kinetic energy is also conserved, so
1/2 m₁ v₁² + 1/2 m₂ v₂² = 1/2 m₁ (v₁')² + 1/2 m₂ (v₂')²
or
m₁ v₁² + m₂ v₂² = m₁ (v₁')² + m₂ (v₂')²
From the momentum equation, we have
(0.600 kg) (9.00 m/s) + (0.300 kg) (-8.00 m/s) = (0.600 kg) v₁' + (0.300 kg) v₂'
which simplifies to
10.0 m/s = 2 v₁' + v₂'
so that
v₂' = 10.0 m/s - 2 v₁'
From the energy equation, we have
(0.600 kg) (9.00 m/s)² + (0.300 kg) (-8.00 m/s)² = (0.600 kg) (v₁')² + (0.300 kg) (v₂')²
which simplifies to
67.8 J = (0.600 kg) (v₁')² + (0.300 kg) (v₂')²
or
226 m²/s² = 2 (v₁')² + (v₂')²
Substituting v₂' yields
226 m²/s² = 2 (v₁')² + (10.0 m/s - 2 v₁')²
which simplifies to
3 (v₁')² - (20.0 m/s) v₁' - 63.0 m²/s² = 0
Solving for v₁' using the quadratic formula gives two solutions,
v₁' ≈ -2.33 m/s or v₁' = 9.00 m/s
but the second solution corresponds to the initial conditions, so we omit that one.
Then the second ball has velocity
v₂' = 10.0 m/s - 2 (-2.33 m/s)
v₂' ≈ 14.7 m/s
how much force would be needed to push a box weighing 30 N up a ramp that ahas an ideal mechanical advantage of 3
Answer:
60n would be the needed force
The force needed to push a box weighing 30 N up a ramp that has an ideal mechanical advantage of 3 is equal to 10 N.
What is the mechanical advantage?The mechanical advantage can be described as the ratio of the input force to the output force. The mechanical advantage of any machine can be determined by the ratio of the forces involved to do the work.
The ratio of the resistance force to the effort is called the actual mechanical advantage which will be comparatively less. The efficiency of a machine is always determined by equating the ratio of its output to its input.
The efficiency of the machine is equal to the ratio of the actual mechanical advantage (M.A.) and theoretical mechanical advantage. Mechanical advantage can be defined as the force produced by a machine to the force applied to it.
Given the load = 30 N and the ideal mechanical advantage = 3
Mechanical advantage = Load/ Effort
Input force or effort = Load/ M.A.
Force = 30/3
Input Force = 10 N
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two forces of magnitude 12 n and 24 n act at the same point. which force cannot be the resultant of these forces?
The force that cannot be the resultant of these forces is 10N since it is less than both given forces
Given the forces with a magnitude of 12N and 24N, the resultant of these forces must not be less than any of the two forces.
From the given options, the only force that is less than both 12N and 24 N is 10N. Hence the force that cannot be the resultant of these forces is 10N since it is less than both given forcesLearn more on resultant force here: https://brainly.com/question/14626208
Mars is 7.83x10^10m [^10 is an exponent] from planet earth. The planet Earth is 5.98x10^24kg [^24 is an exponent] while Mars has a mass of 6.42x10^23kg [^23 is an exponent]. What is the gravitational attraction between the two planets? G=6.67×10^-11 (-11 is an exponent)
Answer:
Approximately [tex]4.18 \times 10^{16}\; \rm N[/tex].
Explanation:
Consider two objects of mass [tex]m_{1}[/tex] and [tex]m_{2}[/tex]. Let [tex]r[/tex] denote the distance between the center of mass of each object. Let [tex]G[/tex] denote the gravitational constant. ([tex]G \approx 6.67 \times 10^{-11}\; {\rm m^{3}\cdot kg^{-1}\cdot s^{-2}}[/tex].)
By Newton's Law of Universal Gravitation, the size of gravitational attraction between these two objects would be:
[tex]\begin{aligned}F &= \frac{G\, m_{1}\, m_{2}}{r^{2}}\end{aligned}[/tex].
In this question, [tex]m_{1} = 5.98\times 10^{24}\; {\rm kg}[/tex] and [tex]m_{2} = 6.24 \times 10^{23}\; {\rm kg}[/tex] are the mass of the two planets. The distance between the two planets is [tex]r = 7.83 \times 10^{10}\; \rm m[/tex] (approximately the same as the distance between the center of mass of planet Earth and the center of mass of Mars.)
Apply Newton's Law of Universal Gravitation to find the size of gravitational attraction between the two planets:
[tex]\begin{aligned}F &= \frac{G\, m_{1}\, m_{2}}{r^{2}} \\ &= \frac{1}{(7.83 \times 10^{10}\; {\rm m})^{2}} \\ &\quad \times (6.67 \times 10^{11}\; {\rm m^{3} \cdot kg^{-1} \cdot s^{-2}}) \\ &\quad \times (5.98 \times 10^{24}\; {\rm kg}) \\ &\quad \times (6.42 \times 10^{23}\; {\rm kg}) \\ &\approx 4.18 \times 10^{16}\; {\rm kg \cdot m \cdot s^{-2}} \end{aligned}[/tex].
Since [tex]1\; {\rm kg \cdot m \cdot s^{-2}} = 1\; {\rm N}[/tex], the size of gravitational attraction between the two planets would be approximately [tex]4.18 \times 10^{16}\; {\rm N}[/tex].
A 2.0 kg block rests on a level surface. The coefficient of static friction is, and the coefficient of kinetic friction is A horizontal force, X, is applied to the block. As X is increased, the block begins moving. Describe how the force of friction varies as X increases from the moment the block is at rest to when it begins moving. Indicate how you could determine the force of friction at each value of X―before the block starts moving, at the point it starts moving, and after it is moving. Show your work.
ps. I had to change F to X because of brainly.
By Newton's second law, the net force acting on the block in the vertical direction is
∑ F [ver] = n - mg = 0
where n = magnitude of normal force and mg = weight of the block. It follows that n = mg.
When the block is at rest, the applied force X will not be enough to move the box until it can overcome the maximum mag. of static friction. If µ[s] is the coefficient of static friction, then the maximum mag. of the frictional force is
f = µ[s] n = µ[s] mg
The net horizontal force would be
∑ F [hor] = X - µ[s] mg = 0
so a minimum force of X = µ[s] mg is required to get the block moving. Any mag. smaller than this and the block stays at rest/in equilibrium.
Once the mag. of X exceeds µ[s] mg, the block will begin to move. At that point, if the coefficient of kinetic friction is µ[k], then the net force on the block is
∑ F [hor] = X - µ[k] mg = 0
so a minimum force of X = µ[k] mg would be needed to keep the block moving at constant speed, or otherwise X = µ[k] mg + ma if the block is accelerating with mag. a.
The principles here are captured in the attached plot.
what voltage is measured across the 15 ohm resistor
in what direction will the seesaw rotate and what will the sign of the angular acceleration be?
Answer:
It can rotate in any direction. The sign of the angular acceleration depends on how you set the reference system, it can be both negative or positive.
What is the final temperature if it requires 5000 J of heat to warm 2.38892 x10-2 kg of water that starts at 5oC? Remember Cp for water is 4186 J/kgC
The final temperature of water is equal to 50.9999°C
Given the following data:
Mass = [tex]2.38892 \times 10^{-2}\;kg[/tex]Quantity of heat = 5000 J Specific heat capacity of water = 4186 J/kg°CTo determine the final temperature of water:
Mathematically, quantity of heat is given by the formula;
[tex]Q=mc\theta[/tex]
Where:
Q represents the quantity of heat.m represents the mass of an object.c represents the specific heat capacity.∅ represents the change in temperature.Substituting the given parameters into the formula, we have;
[tex]5000=2.38892 \times 10^{-2}\times 4186 \times \theta\\\\5000=100.0001912 \theta\\\\ \theta=\frac{5000}{100.0001912} \\\\ \theta=49.9999^{\circ}C[/tex]
For the final temperature:
[tex]\theta = T_2 - T_1\\\\T_2 = \theta+T_1\\\\T_2 = 49.9999 + 50[/tex]
Final temperature = 50.9999°C
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Suppose that the Sun started shrinking in size, without losing any mass. What would be the effect of the Sun's change on the orbits of the planets
Answer:
F = G M m / R^2 gravitational force on planet of mass m.
None of these quantities change in the given hypothesis so
there will be no change in the orbit of mass m
A single covalent bond is stronger than a single hydrogen bond so why does a group of polar molecules tend to have a higher boiling point than a group of non polar molecules
Answer:
this question makes no sense
Explanation:
like how do you get this question
Answer:They require more energy to break intermolecular forces hence polar molecules have higher melting points and boiling points than non-polar molecules of similar size, shape and number of electrons.
Explanation:
2.
A swimmer swims 1 m/s due north against a current of 3 m/s due south. What is the resultant velocity of
the boat?
The resultant velocity of the boat is equal to 2 m/s due south.
Given the following data:
Swimmer's speed = 1 m/s due northOcean current speed = 3 m/s due south.To determine the resultant velocity of the boat:
Resultant velocity can be defined as the sum (addition) of each of the vector velocity acting on a physical or an object. Thus, it is simply a combination of two or more single vector velocity.
Note: When the velocities are acting in the same direction, you will add them up while you will subtract when the velocities are acting in opposite directions.
In this scenario, the velocities are acting in opposite directions. Thus, we would subtract as follows:
[tex]V = 3 - 1[/tex]
V = 2 m/s due south.
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if a 5kg ball is traveling at 20 m/s and it’s stopped in 4s, what’s the impulse on the ball?
if the speed of a car is increased by 50%, bywhat factor will its minimum braking distance be increased, assuming all else is the same?
When the speed of a car increases by a factor of 50%, the minimum braking distance will also be increased by a factor.
Braking distance will increase by a factor 2.25
Solution
From Newton's equation of motion, we can say that;
v² = u² + 2as
Where initial velocity is zero, we have;
v² = 2as
s = v²/2a
s is the distance and v is the final speed.
50% increase in speed means it has increased by a factor of 1.50
Hence we have
1.50²v² is directly proportional to the 1.50²d
Distance = 1.50²v² = 2.25d
Hence, breaking distance will increase by a factor 3.0625
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What are the three different social perspectives on sport
Answer:
functionalist theory,feminist theory. discipline of sociology
what does and does not impact magnetic force?
Answer:
Image result for what does and does not impact magnetic force?
The magnitude of the magnetic force between them depends on how much charge is in how much motion in each of the two objects and how far apart they are. The direction of the force depends on the relative directions of motion of the charge in each case
Explanation:
The factors that affect magnetic force are magnitude of the charge, speed, magnetic field and inclination of the field.
Magnetic forceThe magnetic force on a charged particle moving in a magnetic field is determined using the following formula;
F = qvBsin(θ)
where;
q is the magnitude of the chargev is the speed of the chargeB is the magnetic fieldθ is the angle between the field and the speed of the chargeThus, the factors that affect magnetic force are magnitude of the charge, speed, magnetic field and inclination of the field.
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Liquid X of volume 0.5m3 and density 900kgm-3 was mixed with liquid Y of volume 0.4m3 and density 800kgm-3. What was the density of the mixture?
Answer:
Density of the mixture = 855.56kgm-3
Explanation:
Density = Mass / Volume
Volume of Liquid X = 0.5m³
Density of Liquid X = 900kgm-3
Mass of Liquid X = Density × Volume
= 900kgm-3 × 0.5m³ = 450kg
Volume of Liquid Y = 0.4m³
Density of Liquid Y = 800kgm-3
Mass of Liquid Y = Density × Volume
= 800kgm-3 × 0.4m³= 320kg
As X and Y are mixed, we add their masses and volumes together:
Mass = 770kg
Volume = 0.9m³
Now we can find the density of the mixture:
Density = 770kg / 0.9m³ = 855.56kgm-3 (rounded to the 2nd decimal)
A ball falling from a height of 5 m was caught at some height after being reflected off the floor. Find the magnitude of the movement of the ball. If the distance traveled is equal to 7 meters.
Answer:
3m
Explanation:
I can't make a drawing right know, but it's all around vectors. First of all the ball travels down 5 meters, so we have a vector pointing down, then it is reflected and travels 2 meters up. You have to sum the vectors so you obtain that the distance traveled is: 5-2 meters = 3m
The magnetic field 0. 02 m from a wire is 0. 1 T. What is the magnitude of the magnetic field 0. 01 m from the same wire? 0. 01 T 0. 05 T 0. 1 T 0. 2 T.
The magnitude of the magnetic field 0.01 m from the same wire is 0.2 T.
Given to us:
Magnetic field, [tex]B_1 = 0.1\ T[/tex]
Radius of wire, [tex]R_1 = 0.02\ m[/tex]
To find out the magnitude of the magnetic field 0. 01 m from the same wire, we need to find out current first. we will use the formula,
[tex]B = \dfrac{\mu_oI }{2\pi R},\\\rn\\where,\\B= magnetic\ field\\\mu_o = 4\pi\times 10^{-7} m\cdot kg\cdot s^{-2} A^{-2}\ is\ the\ magnetic\ constant\\I= current\\R= radius\ of\ the\ wire[/tex]
Putting the values,
[tex]B_1 = \dfrac{\mu_oI }{2\pi R_1},\\\rn\\\\0.1= \dfrac{4\times \pi \times 10^{-7}\times I}{2\times \pi\times0.02}\\\\I=10,000\ A[/tex]
Now, for [tex]B_2[/tex]
[tex]B_2 = \dfrac{\mu_oI }{2\pi R_2},\\\rn\\\\B_2= \dfrac{4\times \pi \times 10^{-7}\times 10,000}{2\times \pi\times0.01}\\\\B_2= 0.2\ T[/tex]
Hence, the magnitude of the magnetic field 0. 01 m from the same wire is 0.2 T.
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A 2-column table with 5 rows. The first column has entries empty, time of trial number 1 (seconds), time of trial number 2 (seconds), time of trial number 3 (seconds), average time (seconds). The second column labeled one quarter checkpoint has entries 2. 15, 2. 05, 02. 02, 02. 7. Use the table to answer the questions. What is the fastest time trial for the first quarter checkpoint? seconds What is the slowest time trial for the first quarter checkpoint? seconds What is the range of times measured for this checkpoint? seconds.
The fastest time trial for the first quarter checkpoint is 2.02 s.
The slowest time trial for the first quarter checkpoint is 2.7 s.
The range of the times measured for the checkpoint is 0.68 s.
The given parameters;
Time for quarter checkpoint, = 2.15, 2.05, 2.02, 2.7The fastest time trial for the first quarter checkpoint is the least measured time value.
fastest time trial = least time measured
fastest time trial = 2.02 s
The slowest time trial for the first quarter checkpoint is the highest measured time value.
slowest time trial = 2.7 s
The range of the times measured for the checkpoint is difference between the fastest time and slowest time.
Range = fastest time - slowest time
Range = 2.7 - 2.02
Range = 0.68 s
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Answer:
2.02, 2.15, 0.13
Explanation:
A 2-column table with 5 rows. The first column has entries empty, time of trial number 1 (seconds), time of trial number 2 (seconds), time of trial number 3 (seconds), average time (seconds). The second column labeled one quarter checkpoint has entries 2.15, 2.05, 2.02, 2.07.
Use the table to answer the questions.
What is the fastest time trial for the first quarter checkpoint?
2.02
seconds
What is the slowest time trial for the first quarter checkpoint?
2.15 seconds
What is the range of times measured for this checkpoint?
0.13 seconds
Which electromagnetic wave has a lowest frequency?
Group of answer choices
A) x-rays
B) ultraviolet light
C) microwaves
D) infrared light
E) visible light
Answer:
E.visible lights
Explanation:
hope its attachments
please help quickly,the picture and choices are above.
Answer:
C because it make sens
C the light wave traveled through ice and then through a Dimond.
what role does gravity have in the motion of planets around the sun?
Answer:
The gravity helps the planets stay together near the Sun, without it Earth would be floating away with the planet eventually becoming frozen up, thus the role gravity have in the motion of planets around the sun is by keeping them together.
Explanation:
Hope this helps!
Which statement accurately describes how the acceleration of an object in free fall changes?
O A. It accelerates downward at a constant rate.
O
B. It accelerates downward at an increasing rate.
C. It accelerates downward at an irregular rate.
D. It accelerates downward at a decreasing rate.
Answer: A
Explanation: An object in free fall only is affected by gravity, so the acceleration is 9.8 m/s²
The slope of position-time graph represents
Answer:
The speed.
Explanation:
The slope of a line is that line's rate of change. If a car is travelling at 20 km/hr and we plot distance vs time graph, the slope of that line will be 20.
why does polishing the surface of a metal extend fatigue life
Answer:
they are machined with shape characteristics which maximize the fatigue life of a metal.
Explanation:
they are highly polished to provide the surface characteristics which enable the best fatigue life.
What does it mean when a wave’s amplitude increases?
The wave’s wavelength gets longer.
The wave is moving through a denser medium.
The wave is carrying more energy.
The wave’s frequency also increases.
Answer:
the wave is carrying more energy
Explanation:
trust me broski
Answer:
a
Explanation:
How much energy has 4x 1010 m³ of water collected in a reservoir at a 2. 3. height of 100 m from the power house? What kind of energy is that? (Given, mass of 1 m³ of water = 1000 kg)
Explanation:
[tex] \rule{999pt}{66646pt}[/tex]
Physics Practice Help just need an explanation really not looking for an answer
What variables would be required for a computational model that predicts change in the energy of a falling object?(1 point)
A.)Momentum, speed, mass
B.)Height, speed, mass
C.)Acceleration, speed, mass
D,) x, y, z
This question involves the concepts of the law of conservation of energy and kinetic energy.
The variables required for a computational model that predicts change in the energy of a falling object are "B.)Height, speed, mass".
According to the law of conservation of energy the change in energy can be given in the following form for a falling object:
Loss in Potential Energy = Gain in Kinetic Energy
[tex]mgh = \frac{1}{2}mv^2[/tex]
It is clear from the formula that the variables involved in the computational model are mass, height, and velocity.
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Answer:
b) height, speed, mass
Explanation:
just took the test
Which best describes how plant and animal cells carry out the basic functions of life?
A.
Plant and animal cells do not need food molecules for growth.
B.
Plant and animal cells do not make molecules for their own growth and repair.
C.
Plant and animal cells break down food for growth and repair.
D.
Plant and animal cells perform life functions such as making food molecules for growth.
29) A cheetah can accelerate from rest to 25
m/s in 6 s. Assuming that the cheetah moves
with constant acceleration, what distance does
it cover in the first 3 s
Answer:
[tex]\huge\boxed{\sf S = 18.75 \ meters}[/tex]
Explanation:
Given Data:
Initial Velocity = Vi = 0 m/s (rest)
Final Velocity for 6 seconds = Vf = 25 m/s
Time (1) = T1 = 6 seconds
Time (2) = T2 = 3 seconds
Required:
Distance for 3 seconds = S = ?
Solution:
For 6 seconds, the acceleration will be:
[tex]\displaystyle a = \frac{Vf-Vi}{t} \\\\a = \frac{25 - 0}{6} \\\\a = 25 / 6\\\\\boxed{a = 4.167 \ m/s^2}[/tex]
Since, acceleration is constant, it will be the same at 3 seconds as well.
Using second equation of motion to find Distance (S) with time being 3 seconds:
[tex]\displaystyle S= Vit+\frac{1}{2} at^2\\\\S = (0)(3)+ \frac{1}{2} (4.167)(3)^2\\\\S = \frac{1}{2} (4.167)(9)\\\\S = \frac{37.5}{2} \\\\\boxed{S = 18.75 \ meters}\\\\\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807