Answer:
[tex] 158.256 \: {cm}^{3} [/tex]
Step-by-step explanation:
For cylindrical jar:
Diameter = 6 cm
Radius (r) = 6/2 = 3 cm
Height (h) = 8 cm
[tex]V_{cylindrical \: jar} = \pi {r}^{2} h \\ \\ = 3.14 \times {(3)}^{2} \times 8 \\ \\ = 3.14 \times 72 \\ \\ = 226.08 \: {cm}^{3} \\ \\ \because \: jar \: is \: filled \: upto \: 70 \% \\ \\ \therefore \: V_{jam} = 70 \% \: of \: V_{cylindrical \: jar} \\ \\ \therefore V_{jam} = 0.70 \times 226.08 \\ \\ \therefore V_{jam} = 158.256 \: {cm}^{3} [/tex]
The graph of quadratic function f is shown on the grid. 5 -3 -12 5 u 6 Which of these best represents the domain of f? А -5.5 < x < 1.5 B All real numbers less than or equal to 3 C All real numbers D y <3
Answer:
C: All real numbers.
Step-by-step explanation:
Domain means the interval of x=values that the function resides in. Since this quadratic function can go to both positive and negative infinity, there are no limits to the x-values so therefore the domain is all real numbers.
7 in
are
9 in
11 in
15 in
Answer: 11 in
Step-by-step explanation: Hope this help :D
Could someone please help with this?
9514 1404 393
Answer:
5. 88.0°
6. 13.0°
7. 52.4°
8. 117.8°
Step-by-step explanation:
For angle A between sides b and c, the law of cosines formula can be solved to find the angle as ...
A = arccos((b² +c² -a²)/(2bc))
When calculations are repetitive, I find a spreadsheet useful. It doesn't mind doing the same thing over and over, and it usually makes fewer mistakes.
Here, the side opposite x° is put in column 'a', so angle A is the value of x. The order of the other two sides is irrelevant.
__
Additional comment
The spreadsheet ACOS function returns the angle in radians. The DEGREES function must be used to convert it to degrees. The formula for the first problem is shown here:
=degrees(ACOS((C3^2+D3^2-B3^2)/(2*C3*D3)))
As you can probably tell from the formula, side 'a' is listed in column B of the spreadsheet.
The spreadsheet rounds the results. This means the angle total is sometimes 179.9 and sometimes 180.1 when we expect the sum of angles to be 180.0.
I need help ASAP. Worth 20 points
Look at picture plz
Find all the values of × for which the statement is true.
[tex] | {x}^{2} + 9| = {x}^{2} + 9[/tex]
Jason has a part-time job. The table below shows the number of hours he worked and how much money he earned on three different days.
Answer:
Pretty sure it's 9.75
Step-by-step explanation:
39.00 divided by 4 = 9.75
HAPPY EARTH DAY GUYS! :)
Answer:
THANK YOU! YOU TOO! :)
Step-by-step explanation:
Have a nice dayyyyyy <3
Answer:
HAPPY EARTH DAY!!!!
:)
Which of the following statements is true?
Answer:
Provide the statements please
Step-by-step explanation:
I NEED HELP ASAP!! THANK YOU
rose can make 5 3/4 bookmarks in one hour . How many bookmarks can she make in 3 1/2 hours
Answer:
I haven't done that type of math in a while but I cam up with 21 bookmarks
which figure can be produced by a rotation and reflection of figure A ?
Answer:
It can produce the shape triangle
What is 4v7^3 in exponential form?
Answer:
7 3/4
Step-by-step explanation:
Please help me fast i need help but please no links
Answer:
dont click that other guys link its an ip grabber
Step-by-step explanation:
What is 3 3/10 + 2 1/10
As a decimal- 5.4
As an exact form- 24/5
As a Mixed number- 5 2/5
Hope this helped :T
what is the place name of 2 in 25
Answer:
no idea
Step-by-step explanation:
bro
Answer:
20
Step-by-step explanation:
Hope this helps
True or False
If you know at least one
angle on the diagram
below you can find the
other three.
find the product -2X²×4X²y²
Answer:
-8X^4y^2
Step-by-step explanation:
-2X² × 4X²y² = -8X^4y^2
edit to add:
first: multiply the coefficients together:
-2 x 4 = -8
second: add the exponents of X together (when you multiply exponents, you just add them together):
² & ² = ^4
and you have the answer:
-8X^4y^2
Step-by-step explanation:
-2X²×4X²-y²
= -4X × 16X - y
= 64X -y
Round 69781 to the nearest thousand
Answer:
70000 :) :) :)
Answer:
70,000
Step-by-step explanation:
69781 = 69700
So now you need to round 700 to 1,000 or 0
If you said 1,000 your correct, this makes the number 60,000 + 10,000 making 70,000
Need Help plzzzzzzxxxz
Answer:
[tex]VW = 50[/tex]
Step-by-step explanation:
Given
The attached triangle
Required
Find VW
To find VW, we make use of the following equivalent ratios.
[tex]YX : XW = ZX : XV[/tex]
Where:
[tex]YX = ZX - ZY = 42 - 28 = 14[/tex]
[tex]XV = XW + VW = 25 + VW[/tex]
So, we have:
[tex]14 : 25 = 42 : 25 + VW[/tex]
Express as fraction
[tex]\frac{14 }{ 25 }= \frac{42 }{ 25 + VW}[/tex]
Divide both sides by 14
[tex]\frac{1}{ 25 }= \frac{3}{ 25 + VW}[/tex]
Cross multiply
[tex](25 + VW) * 1 = 3 * 25[/tex]
[tex]25 + VW = 75[/tex]
Solve for VW
[tex]VW = 75 -25[/tex]
[tex]VW = 50[/tex]
The PTO is selling raffle tickets to raise money for classroom supplies. A raffle ticket costs $3. There is 1 winning ticket out of the 140 tickets sold. The winner gets a prize worth $84. Round your answers to the nearest cent.
What is the expected value (to you) of one raffle ticket?
Calculate the expected value (to you) if you purchase 8 raffle tickets?
What is the expected value (to the PTO) of one raffle ticket?
If the PTO sells all 140 raffle tickets, how much money can they expect to raise for the classroom supplies?
Answer:
A) 0.54
B) 4.32
C) 2.4
D) 336
Step-by-step explanation:
A)Expected value (you) = (84 × 3) × [tex]\frac{1}{140}[/tex] × (0.3)× [tex]\frac{139}{140}[/tex]
= 0.54
B) Expected value (you) 8 tickets = 0.54 × 8
= 4.32
C) Expected value ( for PTO) = ( 3 - 84) × [tex]\frac{1}{140}[/tex] + ( 3 - 0 ) × [tex]\frac{139}{140}[/tex]
= 2.4
D) For 140 raffle tickets = 2.4 × 140
= 336
what is the answer to this (235-(-30) /5-100
Answer:
265/ -95 = -2.789
Step-by-step explanation:
235 - - 30 /5 - 100
two negatives equal a positive +
265/5 - 100
265/-95
-2.789
Julio has started his very own floral business. He sells centerpieces for $19.50 each. His fixed costs are $500 per
month, and each centerpiece cost $8 to produce.
Determine your break-even point. Suppose you wish to break even by selling only 25 centerpieces. At what price
would you need to sell each centerpiece?
a. Julio must sell 25 centerpieces at $35 each to break even.
b Julio must sell 25 centerpieces at $25 each to break even.
C. Julio must sell 25 centerpieces at $40 each to break even.
d. Julio must sell 25 centerpieces at $28 each to break even.
The answer to that question was 43.93 not 43.98
Answer: Ok, but can you tell me what you want me to help you with you just put “ The answer to that question was 43.93 not 43.98” and I don’t understand.
Step-by-step explanation:
Help plsssss no links plss
20 Here is a list of five numbers.
98^53
98^64
98^73
98^88
98^91
Find the lowest common multiple of these five numbers.
We want to five the lowest common multiple of these 5 numbers. We will see that the lowest common multiple is:
[tex]98^{91}[/tex]
A multiple of a number N is any product between N and a positive integer. Here we want to get the smallest common multiple of the 5 numbers in the given set.
Here, the set is:
[tex]{98^{53}, 98^{64}, 98^{73}, 98^{88}, 98^{91}[/tex]
Remember the rule:
[tex]a^n*a^m = a^{n + m}[/tex]
Then we can see that:
[tex]98^{91} = 98^{91}*1 = 98^{88}*98^{3} = 98^{73}*98^{18} = 98^{64}*98^{27} = 98^{53}*98^{38}[/tex]
So:
[tex]98^{91}[/tex]
Is a common multiple of all the numbers in the set, and is the smallest common multiple because is equal to the largest number in the set.
If you want to learn more, you can read:
https://brainly.com/question/1055068
One angle of a right triangle measures 51°. What is the measure of the other acute angle, in degrees?
Answer:
39 degree
Step-by-step explanation:
180-90-51=39
One year there was a total of 59 commercial and noncommercial orbital launches worldwide. In addition, the number of noncommercial orbital launches was two more
than twice the number of commercial orbital launches. Determine the number of commercial and noncommercial orbital launches.
Answer:
The number of commercial orbital launches is equal to 19 and the number of noncommercial orbital launches is equal to 40.
Step-by-step explanation:
IMPORTANT INFORMATION: The number of noncommercial orbital launches was two more than twice the number of commercial orbital launches.
Let's say that the number of commercial orbital launches is equal to x. Now, the number of noncommercial orbital launches is equal to 2x+2.
We are told that if we add the number of commercial and noncommercial orbital launches together we will get 59.
Therefore, if we add 2x+2 with x we should get 59:
2x+2+x=59
3x+2=59
3x=57
x=19
This is how we can come to the answer that the number of commercial orbital launches is equal to 19 and the number of noncommercial orbital launches is equal to 40 (2x+2=2*19+2=38+2=40).
Hope this helps!
At many college bookstores, students can decide whether to purchase or to rent a textbook for a class. A study was conducted to investigate whether the percent of rented textbooks for all science classes in the state was greater than the percent of rented textbooks for all literature classes in the state. The following hypothesis test was done at the significance level of α=0.05α=0.05.
H0:pS=pLHa:pS>pLH0:pS=pLHa:pS>pL
In the hypotheses, pSpS represents the proportion of all science textbooks that are rented, and pLpL represents the proportion of all literature textbooks that are rented.
All conditions for inference were met, and the resulting pp-value was 0.035. Which of the following is the correct decision for the test?
The pp-value is less than αα. Since 0.035<0.050.035<0.05, the null hypothesis is rejected, and the claim is supported. There is convincing statistical evidence that the proportion of all science textbooks that are rented is greater than the proportion of all literature textbooks that are rented.
A The pp-value is less than αα, and the null hypothesis is rejected. There is not convincing evidence to support the claim that the proportion of all science textbooks that are rented is greater than the proportion of all literature textbooks that are rented.
B The pp-value is less than αα, and the null hypothesis is not rejected. There is not convincing evidence to support the claim that the proportion of all science textbooks that are rented is greater than the proportion of all literature textbooks that are rented.
C The pp-value is greater than αα, and the null hypothesis is rejected. There is convincing evidence to support the claim that the proportion of all science textbooks that are rented is greater than the proportion of all literature textbooks that are rented.
D The pp-value is greater than αα, and the null hypothesis is not rejected. There is not convincing evidence to support the claim that the proportion of all science textbooks that are rented is greater than the proportion of all literature textbooks that are rented.
Answer:
A The p-value is less than α, and the null hypothesis is rejected. There is convincing evidence to support the claim that the proportion of all science textbooks that are rented is greater than the proportion of all literature textbooks that are rented.
Step-by-step explanation:
Given :
Percentage rented science textbooks = pS
Percentage rented Literature textbooks = pL
To test if percentage Science textbooks in the state was greater than percentage Literature textbooks :
H0: pS = pL
Ha: pS > pL
Pvalue = 0.035 ; α = 0.05
Decision Region :
If Pvalue < α ; We reject H0
In the scenario above,
Pvalue < α ; 0.035 < 0.05 ; Hence, we reject the Null ;
We conclude that There is convincing evidence to support the claim that the proportion of all science textbooks that are rented is greater than the proportion of all literature textbooks that are rented.
7/12 x 4/6 simplest form
In 1960, the average cost of a gallon of milk was $0.49. In 1985, the average cost of a gallon of milk was $2.26. Which of the following represents how to calculate the percent increase in the average cost of a gallon of milk from 1960 to 1985.
A
2.26−0.490.49
B
2.26+0.490.49
C
2.26−0.492.26
D
2.26+0.492.26
Answer:
A
Step-by-step explanation:
$ 2.26- $0.49
=$1.77 increase from 1960 to 1985