Answer:
The range of initial speeds allowed to make the basket is: [tex]9.954\,\frac{m}{s}\leq v \leq 10.185\,\frac{m}{s}[/tex].
Explanation:
We must notice that basketball depicts a parabolic motion, which consists of combining a constant speed motion in x-direction and free fall motion in the y-direction. The motion is described by the following kinematic formulas:
x-Direction
[tex]x = x_{o} + v_{o}\cdot t \cdot \cos \alpha[/tex]
y-Direction
[tex]y = y_{o} + v_{o}\cdot t\cdot \sin \alpha +\frac{1}{2}\cdot g\cdot t^{2}[/tex]
Where:
[tex]x_{o}[/tex], [tex]y_{o}[/tex] - Initial position of the basketball, measured in meters.
[tex]x[/tex], [tex]y[/tex] - Final position of the basketball, measured in meters.
[tex]v_{o}[/tex] - Initial speed of the basketball, measured in meters per second.
[tex]t[/tex] - Time, measured in seconds.
[tex]\alpha[/tex] - Tilt angle, measured in sexagesimal degrees.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
If we know that [tex]x_{o} = 0\,m[/tex], [tex]y_{o} = 2.20\,m[/tex], [tex]\alpha = 36^{\circ}[/tex], [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], [tex]x = (9.10\pm0.23)\,m[/tex] and [tex]y = 2.70\,m[/tex], the system of equation is reduce to this:
[tex](9.10\pm 0.23)\,m = 0\,m + v_{o}\cdot t \cdot \cos 36^{\circ}[/tex]
[tex]9.10\pm 0.23 = 0.809\cdot v_{o}\cdot t[/tex] (Ec. 1)
[tex]2.70\,m = 2.20\,m + v_{o}\cdot t \cdot \sin 36^{\circ} + \frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right) \cdot t^{2}[/tex]
[tex]0.50 = 0.588\cdot v_{o}\cdot t-4.904\cdot t^{2}[/tex] (Ec. 2)
At first we clear [tex]v_{o}\cdot t[/tex] in (Ec. 1):
[tex]v_{o}\cdot t = \frac{9.10\pm 0.23}{0.809}[/tex]
[tex]v_{o}\cdot t = 11.248\pm 0.284[/tex]
(Ec. 1) in (Ec. 2):
[tex]0.5 = 0.588\cdot (11.248\pm 0.284)-4.904\cdot t^{2}[/tex]
Now we clear the time in the resulting expression:
[tex]4.904\cdot t^{2} = 0.588\cdot (11.248\pm 0.284)-0.5[/tex]
[tex]t = \sqrt{\frac{0.588\cdot (11.248\pm 0.284)-0.5}{4.904} }[/tex]
There are two solutions:
[tex]t_{1} = \sqrt{\frac{0.588\cdot (11.248- 0.284)-0.5}{4.904} }[/tex]
[tex]t_{1} \approx 1.101\,s[/tex]
[tex]t_{2} = \sqrt{\frac{0.588\cdot (11.248+ 0.284)-0.5}{4.904} }[/tex]
[tex]t_{2}\approx 1.131\,s[/tex]
The initial velocity is cleared within (Ec. 2):
[tex]v_{o}=\frac{0.50+4.904\cdot t^{2}}{0.588\cdot t}[/tex]
The bounds of the range of initial speed is determined hereafter:
[tex]t_{1} \approx 1.101\,s[/tex]
[tex]v_{o} = \frac{0.50+4.904\cdot (1.101)^{2}}{0.588\cdot (1.101)}[/tex]
[tex]v_{o} = 9.954\,\frac{m}{s}[/tex]
[tex]t_{2}\approx 1.131\,s[/tex]
[tex]v_{o} = \frac{0.50+4.904\cdot (1.131)^{2}}{0.588\cdot (1.131)}[/tex]
[tex]v_{o} = 10.185\,\frac{m}{s}[/tex]
The range of initial speeds allowed to make the basket is: [tex]9.954\,\frac{m}{s}\leq v \leq 10.185\,\frac{m}{s}[/tex].
A 6.0-μF air-filled capacitor is connected across a 100-V potential source (a battery). After the battery fully charges the capacitor, it is left connected and the capacitor is immersed in transformer oil, which has a dielectric constant of 4.5. How much additional charge flows from the battery onto the capacitor during this process? Group of answer choices
Answer:
Change in Q = 2.1x 10^-3 C
Explanation:
We are given that
The Initialcapacitance C1 = 6.0μF
Initial charge oncapacitor
Q1 = C1 V
= 6.00 x 10^-6 x 100
= 6.00 x 10^-4 C
So the Final capacitance C2 will be
= K x C1 = 4.5 x 6.00 x 10^-6
= 2.7 x 10^ -5 F
So to get Finalcharge
We use Q2 = C2 x V
= 2.7 x 10^ - 5 x 100
= 27 x 10^ -4 C
So Charge flown in thecapacitor is change in Q
Which is = Q2 - Q1
= 27 x 10^-4 - 6.0 x 10^ -4
Change in Q = 2.1x 10^-3 C
When is the kinetic energy of the ball being transformed into gravitational potential energy?
Answer:
The second option
Explanation:
I am not sure sry
A highway curve with radius R = 274 m is to be banked so that a car traveling v = 25.0 m/s will not skid sideways even in the absence of friction. At what angle should the curve be banked? 2. what is the correct equation for the sum of the forces in the x direction? What is the correct equation for the sum of the forces in the y direction? A. ΣFx:−Nsinθ=mv2/R; ΣFy:Ncosθ−mg=0 B. ΣFx:−Ncosθ=−mv2/R; ΣFy:Nsinθ−mg=0 C. ΣFx:Nsinθ=mv2/R; ΣFy:Ncosθ+mg=0 D. ΣFx:−Nsinθ=mv2/R; ΣFy:Ncosθ=0 E. ΣFx:−Nsinθ=−mv2/R; ΣFy:Ncosθ−mg=0
Answer:
A) θ = 13.1º , B) E
Explanation:
A) For this exercise, let's use Newton's second law, let's set a reference frame where the axis ax is in the radial direction and is horizontal, the axis y is vertical.
In this reference system the only force that we must decompose is the Normal one, let's use trigonometry
sin θ = Nₓ / N
cos θ = [tex]N_{y}[/tex] / N
Nₓ = N sin θ
Ny = N cos θ
x-axis (radial)
Nₓ = m a
where the acceleration is centripetal
a = v² / R
we substitute
-N sin θ = -m v² / R (1)
the negative sign indicates that the force and acceleration towards the center of the circle
y-axis (Vertical)
Ny - W = 0
N cos θ = mg
N = mg / cos θ
we substitute in 1
mg / cos θ sin θ = m v² / R
g tan θ = v² / R
θ = tan⁻¹ (v² / gR)
we calculate
θ = tan⁻¹ (25² / 9.8 274)
θ = 13.1º
B) when comparing the equations the correct one is E
Question 5
Thermal energy can increase even if the average kinetic energy is constant.
O True
O False
The statement "thermal energy can increase even if the average kinetic energy is constant" is definitely true.
What do you mean by Kinetic energy?Kinetic energy may be characterized as a type of energy that an object possesses due to its motion. It is defined as the work that is required to accelerate a body of a given mass from rest to its stated velocity. It measures the work an object can do by the virtue of its motion.
The thermal energy will still enhance even if the average kinetic energy remains constant. This is because it is based on the relationship between kinetic energy and thermal energy. Kinetic energy is defined as the energy possessed by an object or body as a result of its motion.
Therefore, the statement "thermal energy can increase even if the average kinetic energy is constant" is definitely true.
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Three equal point charges, each with charge 1.05 μCμC , are placed at the vertices of an equilateral triangle whose sides are of length 0.500 mm . What is the electric potential energy UUU of the system? (Take as zero the potential energy of the three charges when they are infinitely far apart.)
Answer:
The value is [tex]U = 0.06 \ J [/tex]
Explanation:
From the question we are told that
The value of charge on each three point charge is
[tex]q_1 = q_2 = q_3 =q= 1.05 \mu C = 1.05 *10^{-6} \ C[/tex]
The length of the sides of the equilateral triangle is [tex]r = 0.500 \ [/tex]
Generally the total potential energy is mathematically represented as
[tex]U = k * [ \frac{q_1 * q_2}{r} + \frac{q_2 * q_3}{r} + \frac{q_3 * q_1}{r} ][/tex]
=> [tex]U = k * 3 * \frac{q^2}{r} [/tex]
Here k is coulomb constant with value [tex]k = 9*10^{9}\ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.[/tex]
=> [tex]U = 9*10^9 * 3 * \frac{(1.05 *10^{-6})^2}{0.5 } [/tex]
[tex]U = 0.06 \ J [/tex]
If you go 45 meters at a speed of 16 m/s, how long does the movement take? Exact answer, do NOT round.
Answer:
2 seconds
Explanation:
The time taken for the movement is 2.81 seconds.
To find the time, the given values are,
Distance = 45 meters
speed = 16 m/s.
What is distance?Distance is the total movement of an object without any regard to direction.Distance can be evaluated how much an object moves from starting point to the end point.The distance completely depends upon the speed and time, i,e., the object covering some area with some particular time interval with the particular speed.Distance will be measured in meter, kilometer, etc..Distance is a Scalar quantity.Formula of distance,
Distance = Speed × Time.
As we have to find the time, Formula can be rearranged as,
Time = Distance / Speed
Substituting the given datas in the formula,
Time = 45 / 16
= 2.81 seconds.
So, the time taken for the movement is 2.81 seconds.
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You walk 20 m north then 30 m west for a total timer four minutes what is the magnitude of your average velocity in (m/s)
Answer:
The average velocity is 0.15 m/s
Explanation:
Use the definition of average velocity as the distance traveled divided the time it took.
Since the movement was on the plane from the origin (0, 0) to the point (-30, 20) corresponding to 30 m west and 20 m north, we calculate the distance using the distance between two points on the plane:
[tex]distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} = \sqrt{(-30)^2+20^2} =\sqrt{1300} \approx 36.06\,\,m[/tex]
Then the magnitude of the average velocity can be estimated via the quotient between distance divided time, but since the units required are meters per second, we first convert the four minute time into seconds: 4 * 60 = 240 seconds.
Then the average velocity becomes:
[tex]v_{ave}=\frac{distance}{time} =\frac{36.06}{240} =0.15\,\,m/s[/tex]
Which kinds of objects emit visible light in the electromagnetic spectrum? A. all objects B. radioactive objects C. relatively cold objects D. relatively hot objects
Answer:
c
Explanation:
Answer:
the answer is c i just did it
Explanation:
a mountain climber lies flat on the surface of a glacier (assumed frictionless), which is inclined at 30 degrees to the horizontal. he remains stationary because he is holding on to a rope that is attached to a spoke in the ice further up the slope. THe slope is parallel to the surface of the ice. if the force of the ice on the climber is 210N, what is the tension in the rope
Answer:
181.87 N
Explanation:
Given that a mountain climber lies flat on the surface of a glacier (assumed frictionless), which is inclined at 30 degrees to the horizontal. he remains stationary because he is holding on to a rope that is attached to a spoke in the ice further up the slope.
Since the he slope is parallel to the surface of the ice.
if the force of the ice on the climber is 210N, the tension T in the rope will be
T = 210 cos 30
T = 181.86 N
Therefore, the tension in the rope is 181.86 N
Describing Forms of Energy
Match each form of energy with its description.
nuclear energy
found when internal energy is
transferred
thermal energy
te
found in the nucleus of an atom
electrical energy
found in the flow of electrical charges
found in the bonds between atoms
chemical energy
Answer:
electrical energy-found in the flow of electrical charges
chemical energy-found in the bonds BTW atoms
thermal energy-found when internal energy is transferred
nuclear energy-found in the nucleus of an atom.
The correct match is: nuclear energy: found in the nucleus of an atom, thermal energy: found when internal energy is transferred, electrical energy: found in the flow of electrical charges, chemical energy: found in the bonds between atoms.
Nuclear energy: This type of energy is obtained from an atom's nucleus. It is released by processes such as nuclear fission or fusion, which utilise the energy held inside atomic nuclei.
Thermal energy is the energy associated with an object's or a system's temperature. When there is a temperature differential, it is a type of internal energy that is exchanged between objects.
Electrical energy is associated with the passage of electric charges, such as electrons, via a conductor.
Chemical energy is contained in the bonds that connect atoms and molecules. When these connections are broken or created, it is released or absorbed during chemical processes.
Thus, this can be the match for the given forms of energy.
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What would the American flag look like under a blue light?
Answer:
The flag will appear to be black.
Explanation:
This is because red is the only brighter color in the American flag, so when a blue light is shined, the red turns dark and then the flag looks just blank and black.
Answer:
As red light falls on a blue surface, it absorbs the red light and no light will be reflected back. Thus, the object appears to be black. When the flag is illuminated by red light, the red and white stripes of the flag will appear solid red, the stars will appear red, and the blue portion will appear black.
The brakes of a car are applied, causing it to slow down at a rate of 10 ft/s2. Knowing that the car stops in 300 ft, determine
(a) how fast the car was traveling immediately before the brakes were applied,
(b) the time required for the car to stop.
Answer:
(a) The velocity of the car before the brakes were applied is 77.46 ft/s
(b) The time required for the car to stop is 7.8 s
Explanation:
Given;
acceleration of the car, a = 10 ft/s²
distance traveled by the car, d = 300 ft
(a) the velocity of the car before the brakes were applied is given;
v² = u² + 2ad
v² = 0 + 2(10 x 300)
v² = 6000
v = √6000
v = 77.46 ft/s
(b) the time required for the car to stop
d = ut + ¹/₂at²
d = 0 + ¹/₂at²
d = ¹/₂at²
t² = 2d / a
t = √ ( 2d / a)
t = √ ( 2 x 300 / 10)
t = 7.8 s
Therefore, the time required for the car to stop is 7.8 s
The speed of the car immediately before the brakes were applied was 77.46 ft/s and it took 7.75 s for the car to stop.
Using the formula:
v² = u² + 2as
Where S is the distance = 300 ft, u is the initial velocity, a is the acceleration = -10 ft/s², v is the final velocity = 0 ft/s (stops)
0² = u² + 2(-10)(300)
0 = u² - 6000
u² = 6000
u = 77.46 ft/s
b)
v = u + at
0 = 77.46 - 10t
t = 7.75 s
The speed of the car immediately before the brakes were applied was 77.46 ft/s and it took 7.75 s for the car to stop.
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Which of the following is not a type of kinetic energy
Enunciado: Una bola se lanza verticalmente de la parte superior de un edificio con una velocidad inicial de 25 m/s. La bola impacta al suelo en la base del edificio 7 segundos después de ser lanzada. (Marque la respuesta correcta)
¿Qué altura subió la bola (medida desde la parte superior del edificio)? a) 19.6 m b) 12.75 m c) 31.88 m d) 40 m e) 20 m
Responder:
Explicación:
Usaremos la ecuación de movimiento para determinar la altura de la bola medida desde la parte superior del edificio.
Usando la ecuación para obtener la altura de caída
S = ut + 1 / 2gt²
u es la velocidad inicial = 25 m / s
g es la aceleración debida a la gravedad = 9,81 m / s²
t es el tiempo = 7 segundos
S es la altura de la caída
S = 25 (7) +1/2 (9,81) × 7²
S = 175 + 4,905 (49)
S = 175 + 240,345
S = 415,35 m
Esto significa que la pelota se elevó a 415,35 m de altura
La altura vertical máxima alcanzada es de 31,88 m.
Tenemos la siguiente información de la pregunta;
Velocidad inicial = 25 m/s
Velocidad final = 0 m/s (a la altura máxima)
tiempo empleado = 3,5 minutos (el tiempo empleado para subir y bajar es igual).
Usando la ecuación;
v^2 = u^2 - 2gh
Dado que v = 0
u^2 = 2gh
h = tu^2/2g
h = (25)^2/2 *9.8
h = 31,88 m
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Calculate the velocity of the bicyclist between 0 and 3 seconds.
Answer:
is there an equasion it gives you?
Explanation:
need a little more info.
A train travels 1000 m south for 100 s. What is the
velocity of the train?
a) 0.1 m/s
b) 0.1 m/s south
c) 10 m/s
d) 10 m/s south
why does person feel weightlessness during freefall
Answer: the only force acting upon your body is the force of gravity
Explanation: a non-contact force. ... The force of gravity is the only force acting upon your body. There are no external objects touching your body and exerting a force. As such, you would experience a weightless sensation.
Explanation:
When in free fall, the only force acting upon your body is the force of gravity - a non-contact force. Since the force of gravity cannot be felt without any other opposing forces, you would have no sensation of it. You would feel weightless when in a state of free fall
why is force required to move an object
Answer:
Force is the push or pull exerted on an object to make it move.
Without force , an object will remain in it's position
Newton's first law of motion proves this. And it states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force.
Explanation:
Newton's second law of motion describes how force is related to mass and acceleration, and this relationship is used to calculate force. In general, the greater the mass of the object, the greater the force needed to move that object.
The relatively high resistivity of dry skin, about 1 × 106 O·m, can safely limit the flow of current into deeper tissues of the body. Suppose an electrical worker places his palm on an instrument whose metal case is accidentally connected to a high voltage. The skin of the palm is about 1.5 mm thick. Estimate the area of skin on the worker’s palm that would contact a flat panel, then calculate the approximate resistance of the skin of the palm.
Answer:
The area is [tex]A = 0.015 \ m^2 [/tex]
The resistance is [tex]R = 1.0 *10^{5} \ \Omega [/tex]
Explanation:
From the question we are told that
The relativity of dry skin is [tex]\rho = 1 * 10^6\ \Omega\cdot m[/tex]
The thickness of the skin is [tex]d = 1.5 \ mm = 1.5 *10^{-3} \ m[/tex]
Generally the area of a flat palm with length = 0.10 m and breath b = 0.15 m is mathematically represented as
[tex]A = d * L[/tex]
[tex]A = 0.10 * 0.15 [/tex]
[tex]A = 0.015 \ m^2 [/tex]
Generally the resistance is mathematically represented as
[tex]R = \frac{\rho * d}{ A }[/tex]
=> [tex]R = \frac{ 1.0 *10^{6} * 1.5*10^{-3}}{ 0.015 }[/tex]
=> [tex]R = 1.0 *10^{5} \ \Omega [/tex]
It takes you 9.5 min to walk with an average velocity of 1.2 m/s to the north
from the bus stop to the museum entrance. What is your displacement?
The direction of movement of the body or item is defined by velocity. Your total displacement will be 684 meters.
What is Velocity?The direction of movement of the body or item is defined by velocity. Speed is fundamentally a scalar number. Velocity is, in essence, a vector quantity. It is the pace at which distance changes. It is the displacement rate of change.
Given that It takes you 9.5 min to walk with an average velocity of 1.2 m/s to the north from the bus stop to the museum entrance.
Time = 9.5 minutes = 9.5 × 60 seconds = 570 seconds
Average Velocity = 1.2 m/s
Now, the displacement made by you can be written as,
Velocity = Displacement / Time
1.2 m/sec = Displacement / 570 seconds
Displacement = 1.2 m/sec × 570 seconds
Displacement = 684 meter
Hence, your total displacement will be 684 meters.
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Willie swift drives a hockey puck into the goal at a speed of 34.8 m/s. From a distance of 60.0 m, how long will it take to reach the net?
Explanation:
distance = rate*time
time = distance divided by rate
now just substitute
time = distance (60 m) divided by rate (34.8 m/sec)
a steel ball bearing will sink in water but a large ship floats because
Answer:
water displacement.
the bigger the item means more water displacement meaning bouyance
The fastest crossing of the Atlantic Ocean by an ocean liner was made on July 7,
1952. The ship, the S.S. United States, traveled 4727 km east by northeast in 3 days,
10 hours, and 40 minutes. Assume that the ship had traveled the same speed, but
directly east. What would the velocity of the S.S. United States be in kilometers per
hour?
Answer:
The speed would be about 80.8 km/h
Explanation:
Notice that the ship really traveled northeast (at 45 degrees north from East) covering eastwards 4727 km.
That means (by using the East projection in a right angle triangle) that the total distance was (the hypotenuse of the right angle) :
[tex]Distance= \frac{4727}{cos(45^o)} \approx 6685\,\,km[/tex]
Then the velocity of the ship was the quotient between this distance divided the time it took. Now,notice that the time is given in days, hours, and minutes, but we need the final velocity answer in km per hour. Then we reduce the given time to hours:
3 days + 10 hours + 40 min = 3 (24) h + 10 h + (40/60) h = 248/3 hours which is approximately 82.7 hours.
Then this record speed is the quotient:
6685 km / 82.7 h = 80.8 km/h
Velocity is the speed and direction of an object. true of false
Answer:
true
Explanation:
Because if u have seen many velocity videos or got taught it then u should know
Help me please! You will get the brainliest!
Answer:
0.5 m.
Explanation:
From the question given above, the following data were obtained:
Force (F) applied = 5 N
Work done (W) = 2.5 J
Distance (s) travalled by the book =?
We can obtain the distance travelled by the book by applying the formula of work done. This is illustrated below:
Work done (W) = Force (F) × Distance (s)
W = F × s
Force (F) applied = 5 N
Work done (W) = 2.5 J
Distance (s) travalled by the book =?
2.5 = 5 × s
Divide both side by 5
s = 2.5/5
s = 0.5 m
From the above calculation, the book will travel 0.5 m when a force of 5 N is applied.
ou are walking down a straight path in a park and notice there is another person walking some distance ahead of you. The distance between the two of you remains the same, so you deduce that you are walking at the same speed of 1.05 m/s. Suddenly, you notice a wallet on the ground. You pick it up and realize it belongs to the person in front of you. To catch up, you start running at a speed of 2.75 m/s. It takes you 18.5 s to catch up and deliver the lost wallet. How far ahead of you was this person when you started running
Answer:
The value is [tex]d = 31.45 \ m [/tex]
Explanation:
Generally the relative speed at which you are moving with respect to the person ahead of you is mathematically represented as
[tex]v_r = v_s - v_c[/tex]
substituting 1.05 m/s for [tex] v_c [/tex] and 2.75 m/s for [tex]v_s[/tex]
So
[tex]v_r = 2.75 - 1.05[/tex]
=> [tex]v_r = 1.7 \ m/s [/tex]
Generally the distance by which the person is ahead of you is mathematically represented as
[tex]d = v_r * t[/tex]
substituting 18.5 s for [tex] t [/tex]
[tex]d = 1.7 * 18.5[/tex]
=> [tex]d = 31.45 \ m [/tex]
Determine the distance S to which the 90kg painter can climb without causing the 4m ladder to slip at it's lower end A. The top of the 15kg ladder has a small roller, and at the ground the coefficient of static friction is 0.25. The mass center of the painter is directly above her feet.
Explanation:
...................,..........
Newton's first law states that at rest the sum of the forces acting on a body is zero
The distance S to which the painter can climb is approximately 2.55 meters
The reason the above value for the distance is correct is as follows:
The given parameter are;
The mass of the painter, m₁ = 90 kg
Length of the ladder, l = 4 m
The mass of the ladder, m₂ = 15 kg
The coefficient pf static friction, μ = 0.25
Friction force, [tex]\mathbf{F_f}[/tex] = Normal reaction, N × μ
Normal reaction (flat surface), N = Weight of painter + Weight of ladder
N = m₁·g + m₂·g
Where;
g = The acceleration due to gravity, g = 9.81 m/s²
N = 90 kg × 9.81 m/s² + 15 kg × 9.81 m/s² = 1,030.05 N
∴ [tex]\mathbf{F_f}[/tex] = 1,030.05 N × 0.25 = 257.5125 N
Friction force, [tex]\mathbf{F_f}[/tex] = 257.5125 N (Horizontal force)
At equilibrium, the sum of the horizontal forces = 0
∴ Fₓ + [tex]\mathbf{F_f}[/tex] = 0
Fₓ = [tex]-F_f[/tex] = -257.5125 N (Acting opposite to the direction of the friction force)
The height of the top of the ladder from the ground, h = √(4²-1.5²) = √(13.75)
Taking moment about point A gives;
Clockwise moment = Anticlockwise moment
Fₓ × h = m₁·g·s·cos(θ) + m₂·g·(l/2)·cos(θ)
Therefore;
Fₓ × √(13.75) m = 90 kg × 9.81 m/s² × s × (1.5/4) + 15 kg × 9.81 m × 2 m × (1.5/4)
Fₓ × √(13.75) m = 331.0875 N × s + 110.3625 J
257.5125 N × √(13.75) m = 331.0875 N × s + 110.3625 J
s = (257.5125 N × √(13.75) m - 110.3625 J)/(331.0875 N) ≈ 2.55 m
The distance to which the 90 kg painter can climb without causing the 4 m ladder to slip at its lower end, A, distance S ≈ 2.55 meters
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Meter #1 can measure voltage to within 0.1 volts. Meter #2 can measure voltage to within 0.01 volts.
A.) Which meter has the greatest precision?
B.) Which meter is more accurate? Why?
Meter #2 is more precise.
There's no information here that tells us which meter is more accurate.
What is the velocity of a plane to travel 3000 miles from New York to California in 5.0 hours
Answer:
10 miles per minute.
Which statement supports Newton’s first law of motion?
Answer:
Newton's first law of motion is that an object at rest will stay at rest, unless acted upon by an external force.
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The "external force" can be anything, from a gust of wind, to a person moving the object. His first law also corresponds with the definition of inertia.
Hope this helps!