A 7.4 A current is set up in a circuit for 7.8 min by a rechargeable battery with a 3.0 V emf. By how much is the chemical energy of the battery reduced?

Answer: IM 95%sure that the answer is B jus took the test got the answer right

Explanation:

Answer:

sorry I forgot I wish I could help

Answer:

10.53m/s²

Explanation:

Centripetal acceleration is the acceleration of an object about a circle. The formula for calculating centripetal acceleration is expressed by:

[tex]a = \frac{v^2}{r}[/tex]

v is the velocity of the car = 24.5m/s

r is the radius of the track = 57.0m

Substitute the given values into the formula:

[tex]a = \frac{24.5^2}{57} \\\\a = \frac{600.25}{57}\\ \\a = 10.53m/s^{2}[/tex]

Hence the centripetal acceleration of the race car is 10.53m/s²

Answer:They have made community members shareholders so they get a share of the profits, which they use for schools and healthcare clinics

Explanation: Edmentum

Answer:

shareholders of the community get profits and that is used for schools and healthcare clinics. cs. 

Explanation:

Answer:

What do you mean ma´am/sir?

Explanation:

Answer:

The force is [tex]F_b =  216 \  N [/tex]

Explanation:

From the question we are told that

   The  mass of the bungee jumper is  m  = 80 kg

    The spring constant is  [tex]k = 20 \ N/ m[/tex]

    The extension of the rubber bungee cords is  x = 50 m

Generally the weight of the jumper is

      [tex]W =  m *  g[/tex]

=>   [tex]W =  80 *  9.8 [/tex]

=>   tex]W =  784  \  N  [/tex]

Generally  the returning force of the rubber bungee cords is mathematically represented as

      [tex]F  =  k  *  x[/tex]

=>     [tex]F  =  20   * 50 [/tex]

=>     [tex]F  =  1000 \  N [/tex]

The force to be applied by the bear is

    [tex]F_b =  F -  W[/tex]

=>    [tex]F_b =  100 -  784[/tex]

=>  [tex]F_b =  216 \  N [/tex]

1) describe the life cycle of a star before it collapses into a black hole.

1) describe the life cycle of a star before it collapses into a black hole.ans: A star's life cycle is determined by its mass. The larger its mass, the shorter its life cycle. A star's mass is determined by the amount of matter that is available in its nebula, the giant cloud of gas and dust from which it was born. Over time, the hydrogen gas in the nebula is pulled together by gravity and it begins to spin. As the gas spins faster, it heats up and becomes as a protostar. Eventually the temperature reaches 15,000,000 degrees and nuclear fusion occurs in the cloud's core. The cloud begins to glow brightly, contracts a little, and becomes stable. It is now a main sequence star and will remain in this stage, shining for millions to billions of years to come. This is the stage our Sun is at right now.

2) describe the life cycle of a star before it becomes a dwarf.

ans: The life cycle of a low mass star (left oval) and a high mass star (right oval). ... As the core collapses, the outer layers of the star are expelled. A planetary nebula is formed by the outer layers. The core remains as a white dwarf and eventually cools to become a black dwarf.

3) what is the likely outcome of our sun?

ans: All stars die, and eventually — in about 5 billion years — our sun will, too. Once its supply of hydrogen is exhausted, the final, dramatic stages of its life will unfold, as our host star expands to become a red giant and then tears its body to pieces to condense into a white dwarf.

Answer:False

Explanation:

Answer:

False

Explanation:

Answer:

Explanation:

Given data

mass m= 1200kg

radius r=92m

coefficient of friction μ=0.65

We know that

F=mv2/r

F=μmg  

mv2/r = μsmg  

v^2/r = μsg  

vmax = √(rμg)

Substituting our data we have

vmax=√(92*0.65*9.81)

vmax=√586.638

vmax=24.22m/s

Answer:

b

Explanation:

Answer:

The spring constant is 3.44x10⁶ kg/s².

Explanation:

We cand find the spring constant by conservation of energy:

[tex] E_{i} = E_{f} [/tex]

[tex] mgh = \frac{1}{2}kx^{2} [/tex]   (1)

Where:

m is the mass =  41700 kg

g is the gravity = 9.81 m/s²

h is the height = 2.65 m

x is the distance of spring compression = 79.4 cm

k is the spring constant =?

Solving equation (1) for k:

[tex]k = \frac{2mgh}{x^{2}} = \frac{2*41700 kg*9.81 m/s^{2}*2.65 m}{(0.794 m)^{2}} = 3.44 \cdot 10^{6} kg/s^{2}[/tex]              

Therefore, the spring constant is 3.44x10⁶ kg/s².

I hope it helps you!

Answer:

The correct answer is A. A government that wants to increase its GDP would most likely increase the money supply to make it easier to borrow money.

Explanation:

If the government wanted to increase its GDP, the most appropriate way to do so would be to increase the money supply both through issuance and through a reduction in bank reserve requirements, thereby increasing the circulating money in the hands of society.

This, in turn, would make citizens reinvest that money, increasing economic production and, therefore, the national GDP.

Answer: A. Increase the money supply to make it easier to borrow money

Explanation: I just took the test on Ap ex

Answer:

25.  Approximately 8.1 meters

26. North 1.31 km, and East 2.81 km

Explanation:

25.

Notice that the displacements: 6 meters east and 5.4 south create the legs of a right angle triangle. The hypotenuse of that triangle will be the distance (d) needed to cover in order to get the ball in the hole in one putt. That is:

[tex]d=\sqrt{6^2+5.4^2} =\sqrt{65.16} \approx 8.072\,\,\,m[/tex]

which can be rounded to 8.1 m.

26.

Notice that the 3.1 km at an angle of 25 degrees north of east, is the hypotenuse of a right angle triangle that has for legs the east and north components of that distance.

We can find the leg corresponding to the east displacement using the cosine function (that relates adjacent side with hypotenuse):

[tex]east\,\, comp=3.1 * cos(25^o)\approx 2.809\,\,km[/tex]

and we can calculate the north component using the sine function that relates the opposite side to the angle with the hypotenuse.

[tex]north\,\,component = 3.1 * sin(25^o) \approx 1.31 \,\,km[/tex]

Answer:

[tex]200.38^0[/tex]

Explanation:

Given the forces:

F1 = 8.92 i + 17.37 j

F2 = 8.31 i - 10.97 j

If a third vector is added to them such that they add up to to the null vector as F1 + F2 + F3 = 0

then to get F3:

F3 = -F2-F1

F3 = -(8.31 i - 10.97 j)-(8.92 i + 17.37 j )

F3 = -8.31 i + 10.97 j-8.92 i - 17.37 j

F3 = -8.31i-8.92i+10.97j-17.37j

F3 = -17.23i-6.4j

from the vector:

x = -17.23 and y = -6.4

angle of the third vector with respect to the +x-axis is expressed as:

[tex]\theta = tan^{-1}\frac{y}{x}\\ \theta = tan^{-1}\frac{-6.4}{-17.23}\\\theta = tan^{-1}0.3715\\\theta = 20.38^0[/tex]

Hence the angle the vector makes with the x axis will be [tex]\theta = 180+20.38 = 200.38^0[/tex]

Answer:acbd

Explanation:

ans: 4m/s²

and 2m/s²

step:

f=m.a

in first condition

f=12N , M=3kg

so,

12=3.a

a=12/3

a=4m/s².

similarly

in second condition

f=12N ,M=6Kg

so,

12=a.6

a=12/6

a=2m/s²

Answer:

noun. a person who is connected with another or others by blood or marriage. something having, or standing in, some relation or connection to something else. something dependent upon external conditions for its specific nature, size, etc. (opposed to absolute).

Answer:

La aceleración necesaria para detener el avión es - 10.42 m/s².

Explanation:

Un movimiento uniformemente acelerado (M.U.A) es aquél cuya aceleración es constante y la velocidad de un objeto cambia a medida que el movimiento evoluciona.

Siendo la aceleración "a" el cambio de velocidad al tiempo transcurrido en un punto A a B, la velocidad inicial la velocidad que tiene un cuerpo al iniciar su movimiento en un período de tiempo y la velocidad final la velocidad que tiene un cuerpo al finalizar su movimiento en un período de tiempo, entonces en  M.U.A se cumple:

Vf² - Vo² = 2*a*d

donde:

En este  caso:

Reemplazando:

(0 m/s)² - (50 m/s)² = 2*a*120 m

Resolviendo:

[tex]a=\frac{(0 m/s)^{2} -(50 m/s)^{2} }{2*120 m}[/tex]

a= - 10.42 m/s²

La aceleración necesaria para detener el avión es - 10.42 m/s².

Answer:

The rate the wheel will process about the vertical is 2.86 RPM

Explanation:

Given;

radius of the bicycle wheel, R = 0.36 m

mass of the wheel, m = 3.2 kg

angular velocity, ω = 4 rev/s

The rate at which the wheel will process about the vertical is given by;

Ф = τ/L

Where;

τ is the torque

L is the angular momentum

τ = Fr

τ = mgr = 3.2 x 9.8 x 0.1 = 3.126 N.m

L = Iω =  MR²ω

L = 3.2 x (0.36)² x (4 x 2π)

L = 10.4244 kg.m²/s

Ф = τ/L

Ф = (3.126) / (10.4244)

Ф = 0.29987 rad/s

Ф = 0.29987 rad/s  x (60 / 2π)

Ф = 2.86 RPM

Therefore, the rate the wheel will process about the vertical is 2.86 RPM

Answer:

Biology

Physics

Chemistry

Explanation:

Biology (life like cells, human reproduction, etc.)

Physics (Studies forces, like gravity.)

Chemistry (studies the atoms, the elements, etc.)

Answer:

t = 5.77 s

Explanation:

This exercise will use Newton's second law for rotational motion

            τ = I α

             α = τ / I

             α = 66/175

             α = 0.3771   rad/s²

now we can use the rotational kinematics relations, remember that all angles must be in radians

            θ = 1 rev = 2π radians

            θ = w₀ t + ½ α t²

as the wheel starts from rest w₀ = 0

             t = √ (2θ/α)

let's calculate

             t = √ (2 2π / 0.3771)

             t = 5.77 s

Answer:

y(i) = h

v(y.i) = 0

Explanation:

See attachment for elaboration

Answer:

m₁ = 70 lb

Explanation:

Here we will use the law of conservation of momentum:

m₁u₁ + m₂u₂ + m₃u₃ = m₁v₁ + m₂v₂ + m₃v₃

where,

m₁ = mass of first suitcase = ?

m₂ = mass of second suitcase = 30 lb

m₃ = mass of baggage carrier = 50 lb

u₁ = initial speed of first suitcase = 7.2 ft/s

u₂ = initial speed of second suitcase = 7.2 ft/s

u₃ = initial speed of baggage carrier = 0 ft/s

v₁ = Final speed of first suitcase = 4.8 ft/s

v₂ = Final speed of second suitcase = 4.8 ft/s

v₃ = Final speed of baggage carrier = 4.8 ft/s

because after collision all three will have same speed

Therefore,

(m₁)(7.2 ft/s) + (30 lb)(7.2 ft/s) + (50 lb)(0 ft/s) = (m₁)(4.8 ft/s) + (30 lb)(4.8 ft/s) + (50 lb)(4.8 ft/s)

(m₁)(7.2 ft/s) + (216 lb ft/s) + (0 lb ft/s) = (m₁)(4.8 ft/s) + (144 lb ft/s) + (240 lb ft/s)

(m₁)(7.2 ft/s) - (m₁)(4.8 ft/s) = 168 lb ft/s

m₁ = (168 lb ft/s)/(2.4 ft/s)

m₁ = 70 lb

Answer:

The value is [tex]n=  9.375 *10^{15} \  electrons [/tex]

Explanation:

From the question we are told that

  The average current is  [tex]I  =  25.0 \mu A = 25.0 *10^{-6} \  A[/tex]

Generally the quantity of charge (electron )  is mathematically represented as

       [tex]Q =  ne[/tex]

Here e is the charge on a single electron with value [tex]e = 1.60  *10^{-19} \  C[/tex]

   Generally current is mathematically represented as

     [tex]I  = \frac{Q}{t}[/tex]

=>   [tex]I  = \frac{ne}{t}[/tex]

Here t is time which is given as 1 minutes =  60  seconds

  and  n is the number of electrons

So

      [tex]25.0 *10^{-6}  = \frac{ n* 1.60  *10^{-19}}{60}[/tex]

=>    [tex] 60  * 25.0 *10^{-6} =  n* 1.60  *10^{-19}  [/tex]

=>    [tex]n=  \frac{60  * 25.0 *10^{-6} }{ 1.60  *10^{-19} }[/tex]

=>    [tex]n=  9.375 *10^{15} \  electrons [/tex]

The number of electrons that strike the screen every minute is; n = 9.375 × 10¹⁵ electrons

We are given;

Average Current; I = 25 μA = 25 × 10⁻⁶ A

Formula for the current is;

I = Q/t = ne/t

where;

n is number of electrons

e is electron charge = 1.6 * 10⁻¹⁹ C

t is time = 1 minute = 60 seconds

Thus making n the subject gives;

n = It/e

n = (25 × 10⁻⁶ * 60)/(1.6 * 10⁻¹⁹)

n = 9.375 × 10¹⁵ electrons

Read more about number of electrons at; https://brainly.com/question/11406294

The answer is A I Hope this answer helps you (i got the question right)

Answer:

A. As speed increases, kinetic energy increases exponentially.

Explanation:

The amount of kinetic energy an object has depends on the speed. Kinetic energy is also known as "motion energy." This being said, if speed is increasing, decreasing, or staying constant, the kinetic energy of the object will too.

Answer:

1030.3504 units

Explanation:

Disk radius = 7 inches

Density at distance x = p(x) = [tex]\sqrt{10x}[/tex]

Calculate the mass of the two-dimensional object

M = 2[tex]\pi[/tex][tex]\sqrt{10} * (\frac{2}{5} ) *(7)^{\frac{5}{2} }[/tex] = 1030.3504 units

Answer:

3.2

Explanation:

I hope that this helps! Have a good day!!

Answer:

Both cars convert more kinetic energy to thermal energy.

Explanation:

Given that,

Two cars come to a stop from the same initial speed, one braking gently and the other braking hard.

We know that,

The conservation of energy :  

The energy of the system is always constant.

The energy can be change one form to another form.

So, we can say that when both cars come to a stop from the same speed, one braking softly and the other braking strongly then both cars convert more kinetic energy to thermal energy.

Hence, Both cars convert more kinetic energy to thermal energy.

Based on the law of consevation of energy, the car that brakes hard will convert more kinetic energy to thermal energy.

According to the law of conservation of energy, the total energy is conserved in any closed system.

Since the cars have the same mass and had the same initial speed, their kinetic energies are the same.

However, the car braking hard comes to rest in a shorter time and in a shorter distance.

Using the formula for calculating power:

The car that braked hard will have greater power due to shorter time of action.

This power is seen as greater thermal energy, whereas some of the energy of the other car will still be used in travelling some distance before stopping.

Therefore, the car that brakes hard will convert more kinetic energy to thermal energy.

Learn more about kinetic energy and thermal energy at: https://brainly.com/question/3064483

Answer:

40

Explanation:

Answer:

The value of q is [tex]\dfrac{Q}{8}[/tex]

Explanation:

Given that,

Each charge = -Q

Distance between charges = L

Reduced force = [tex]\dfrac{F}{2}[/tex]

Suppose, Two particles each with a charge -Q are fixed a distance L apart as shown above. Each particle experiences a net electric force F. A particle with a charge +q is now fixed midway between the original two particles.

We know that,

The force on each end is

[tex]F=\dfrac{kQ^2}{L^2}[/tex]...(I)

If the charge q is placed at mid point then

The  force on each end charge is

[tex]\dfrac{F}{2}=F+F'[/tex]....(II)

We need to calculate the value of q

Using equation (II)

[tex]\dfrac{F}{2}=F+F'[/tex]

Put the value of F into the formula

[tex]\dfrac{\dfrac{kQ^2}{L^2}}{2}=k\dfrac{Q^2}{L^2}+k\dfrac{q\times(-Q)}{(\dfrac{L}{2})^2}[/tex]

[tex]\dfrac{kq(-Q)}{(\dfrac{L}{2})^2}=-\dfrac{kQ^2}{2L^2}[/tex]

[tex]\dfrac{q}{\dfrac{1}{4}}=\dfrac{Q}{2}[/tex]

[tex]q=\dfrac{Q}{8}[/tex]

Hence, The value of q is [tex]\dfrac{Q}{8}[/tex]