A 6 kilogram block in outer space is moving at -100 m/s (to the left). It suddenly experiences three forces as shown below.

B) What equilibrant force is required to keep the block at rest once it does?


C) If you were to rearrange the three forces as you like, what maximum force could be applied to slow the block?


D) How much time would it take for the block to stop under maximum force conditions?

Answer: This problem may arise when your father never bought a shoe before. A male is bad at buying accesories and guessing the size, so the mother should have bought a pair of shoes. Or it can also be that your father has a short term memory or that he never knew the size of your feets. The feet might also have irregular growth for which it grows more than the normal size but such cases are rare to be seen.

You can prevent this by going with your father and selecting the shoe of your size. Or you can simply send your mother to buy it for you instead. Or another perfect choice could be is that you just dont ever send your father to buy anything for you or just never buy a pair of shoes. Wear the shoes that you always did or buy it yourself since your the one who is supposed to know the size of your feets. Another possible solution could be that you can make use of the money by gifitng them to someone close to you.

Answer:

I believe its A: Sports biomechanics.

Using law of conservation of momentum

[tex]\\ \sf\Rrightarrow m_1v_1-m_2v_2=(m1+m2)v_3[/tex]

[tex]\\ \sf\Rrightarrow 1500(5)-3000(7)=(1500+3000)v_3[/tex]

[tex]\\ \sf\Rrightarrow 7500-21000=4500v_3[/tex]

[tex]\\ \sf\Rrightarrow -13500=4500v_3[/tex]

[tex]\\ \sf\Rrightarrow v_3=-3m/s[/tex]

Answer:

the orbital in which the electron is located relative to the atom's nucleus.

Explanation:

Answer:

the principal energy level of an electron refers to the shell or orbital in which the electron is located relative to the atom's nucleus.

Answer:

Slinky is the correct answer.

Answer:

hottest plant: vensus, close to the sun

coldest plant: Neptune, farthest from the sun

Explanation:

Answer:

1. around 22m

Explanation:

Annie traveled 9 meters during that time. Her average acceleration was -8 m/s².

Annie's initial speed was 12 m/s.

Her final speed was 0 m/s.

The time it took her to stop was 1.5 seconds.

Therefore, the distance she traveled during that time is:

distance = (initial speed + final speed)/2 * time

= (12 m/s + 0 m/s)/2 * 1.5 seconds

= 9 meters

Annie's average acceleration is calculated by dividing her change in velocity by time it took for that change to occur.

In this case, her change in velocity is from 12 m/s to 0 m/s, which is a decrease of 12 m/s.

The time it took for this change to occur is 1.5 seconds.

Therefore, Annie's average acceleration is:

acceleration = change in velocity / time

= -12 m/s / 1.5 seconds

= -8 m/s²

The negative sign indicates that Annie was slowing down.

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So, your science teacher has given your class the classic "mousetrap car" assignment: to make, design, and build a small vehicle powered by the snapping action of a mousetrap to make your car travel as far as possible. If you want to come out ahead of all the other students in your class, you'll need to make your car as efficient as possible so you can squeeze every last inch out of your "car". With the right approach, it's possible to streamline your car's design for maximum distance using only common home materials. You could also buy a mousetrap car kit from any craft store and skip wondering if it will work.

Use large rear wheels. Large wheels have greater rotational inertia than small wheels. In practice, this means that once they start rolling, they're harder to stop rolling. This makes large wheels perfect for distance-based contests — theoretically, they'll accelerate less quickly than smaller wheels, but they'll roll much longer and they'll travel a greater distance overall. So, for maximum distance, make the wheels on the drive axle (the one the mousetrap is tied to, which is usually the rear one) very large. The front wheel is a little less important — it can be large or small. For a classic drag racer look, you'll want big wheels in the back and smaller ones in front.

Use thin, light wheels. Thinner wheels have less friction and may go farther if the distance is what you want or need with your mousetrap racer. It's also important to take the weight of the wheels themselves into account — any unneeded weight will ultimately slow your car down or lead to added friction. In addition, it's worth noting that wide wheels can even have a small negative effect on the car's drag due to air resistance. For these reasons, you'll want to use the thinnest, lightest wheels available for your car.

Old CDs or DVDs work fairly well for this purpose — they're large, thin, and extremely light. In this case, a plumbing washer may be used to reduce the hole size in the middle of the CD (to fit the axle better).

If you have access to old vinyl, these also work extremely well, though they may be too heavy for the smallest mousetraps.

Use a narrow rear axle. Assuming your car is a rear-wheel-drive car, each time your rear axle turns, the rear wheels turn. If your rear axle is extremely skinny, your mousetrap car will be able to turn it more times for the same length of string than it would if it were wider. This translates to turning your rear wheels more times, meaning greater distance! For this reason, it's a wise idea to make your axle out of the skinniest material available that can still support the weight of the frame and wheels.

Narrow wooden dowel rods are a great, easily-accessible choice here. If you have access to thin metal rods, these are even better — when lubricated, they usually have less friction.

Create traction by giving the edges of the friction of the wheels. If the wheels slip against the ground when the trap is sprung, energy is wasted — the mousetrap works to make the wheels turn, but you don't get any extra distance. If this happens with your car, adding a friction-inducing material to the rear wheels may reduce their slippage. To keep your weight requirements down, use only as much as is necessary to give the tips of the wheels some grip and no extra. Some suitable materials are:[1]

Electrical tape

Rubber bands

Additionally, placing a piece of sandpaper under the rear wheels at the start line can reduce slippage as the car begins to move (when it is most likely)

Answer:

e = k q / r² then,

e = 9×10^9 * 1×10^-6 / 50² = 3.6 N/C

hope this helps ❤.

Answer:

Vertebrate zoology

Explanation:

Have a great day!

Answer:

We are required to analyze the conservation of kinetic energy in a perfectly inelastic collision.

kinetic energy:K=1/2mv²

momentum:p=mv

Explanation:

Using the equations for final velocity in terms of masses and initial velocity for a perfectly inelastic collision, work out the final kinetic energy. Calculate the initial kinetic energy and show that kinetic energy is not conserved. Use variables, no numbers

You need to follow law of conservation of energy

We know

You may use momentum formula mass×velocity

In both you need to form equations then solve for final velocity

Current Forecast is:

Sunny with a temp of 67 deg F, as of rn there is no clouds in the sky

Location, Oklahoma USA in the NE corner

Answer:

1 N

Explanation:

1) You'll just have to sum the force vectors, and since they are opposite, you'll calculate the difference of their magnitudes, in absolute value.

Ftot = |F1 - F2| = 6N - 5N = 1N

2)The direction will be the same as the greater force's direction.

Answer:

Atomic mass

Explanation:

Answer:

atomic mass

Click thanks if thankc if this helped

Answer:

2,500g is the answer yes

The strength of the magnetic field is increased by adding more coils to the wire and placing a metal bar within the coils.

The given problem is based on the concept and fundamentals of the magnetic strength in a current-carrying coil of wire. The current-carrying wire in a coiled form is known as Solenoid.

And the mathematical expression for the magnetic field in a solenoid is,[[tex]B = \dfrac{\mu_{0} \times N \times i}{L}[/tex]

Here,

B is the strength of the magnetic field.

[tex]\mu_{0}[/tex] is the magnetic permeability of free space.

N is the number of coils.

The strength of the magnetic field will increase by increasing the number of coils and placing the metallic slab (it will increase magnetic permeability) within the coils.

Thus, we can conclude that the strength of the magnetic field is increased by adding more coils to the wire and placing a metal bar within the coils.

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Answer:

C

Explanation:

Answer:

5) A 200n

F net=0n

6) B 50n

F net=0n

7) C 200n

F net= 900n, up

8) D 80n

F net=60n,left

9) E 300n

F net=60n,left

10)???

11) G 20n

F net=30n,Right

__________________________________

All the answers is hard

correct me if i'm wrong

Answer:

-8

5.092×10

Explanation:

given,

distance (d) =15m

mass (M1) =350kg

mass(M2) = 492kg

Gravitational constant (G)=6.67×10^-11

we know,

gravitational force=(Gm1m2)÷d^2

=(6.67×10^-11×350×492)÷15^2

= (1.14857×10^-5)÷225

= 5.092×10^-8

Explanation:

What we know:

Sa + Sb = 350 km

Ta + Tb = 4h

S = Vt

With these equations above we can write a system of equations and find Tb, as you see in the picture(s).

After having Tb you can easily find Ta and then Sa and Sb. Hopefully it was clear.

[tex]\large{\underline{\underline{\maltese{\pink{\pmb{\sf{ \; Question \; :- }}}}}}}[/tex]

An automobile with a mass of 1250 kg accelerates at a rate of 4 m/sec² in the forward direction. What is the net force acting on the automobile?

_________________________________________

[tex]\large{\underline{\underline{\maltese{\green{\pmb{\sf{ \; Given\; :- }}}}}}}[/tex]

_________________________________________

[tex]\large{\underline{\underline{\maltese{\orange{\pmb{\sf{ \; To \: Find \; :- }}}}}}}[/tex]

_________________________________________

[tex]\large{\underline{\underline{ \bigstar{{\pmb{\sf{ \; Concept \: and \: Formula \: Used \; :- }}}}}}}[/tex]

➯ Force is defined as the product of the mass of the body and its acceleration.

[tex] \bigstar \: \small{ \fbox {\textsf {\textbf{F = ma}}}}[/tex]

Where :

[tex]\large{\underline{\underline{ \bigstar{{\pmb{\sf{ \; Substituting \: the\: Given\: Values :- }}}}}}}[/tex]

[tex]⇝ \: \: \small \textsf {\textbf{ F = (1250 × 4) N }}[/tex]

[tex]⇝ \: \: \small \textsf {\textbf{ F = 5000 N }}[/tex]

[tex]\large{\underline{\underline{ \bigstar{{\pmb{\sf{ \; Therefore \; :- }}}}}}}[/tex]

❝ The net force acting on the automobile is 5000 N. ❞

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Answer:

So correct sentence is:

So correct sentence is:

So correct sentence is:

So correct sentence is:

Answer:

Homogenous Mixture

Explanation:

The composition in paint is uniform so every part of it looks the same throughout the paint.

When NaOH is added to water, it separates into Na+ and OH-. The hydroxyls make it more basic.

A basic solution is an aqueous solution containing more OH⁻ ions than H⁺ ions.

When NaOH as a solute is mixed into the solvent like water, it separates NaOH into Na+ and OH-. The sodium ions Na⁺ have little effect on the solution, but the hydroxyls OH⁻ ions makes the solution more basic.

Thus, NaOH form a basic solution by the presence of OH⁻ ions  into it.

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Hi there!

[tex]\large\boxed{\text{Angular acceleration.}}[/tex]

For a rigid body rotating about a fixed axis, its angular characteristics ⇒ angular acceleration and velocity are constant throughout.

However, its LINEAR velocities/accelerations differ because of the following relationships:

v = ωr

a = αr

Thus, a point closer to the axis of rotation has a smaller linear velocity or acceleration compared to a point along the edge.

The process of charging an object without touching it is called induction charging.

The process of charging a sphere by touching it with a charged rod is called charging by conduction..

When an uncharged object brings into the contact of the charged object but not touching the object directly, the uncharged object gets charged. This process of charging is called Induction Charging.

When an uncharged object brings in to the contact of the charged object by touching it directly, the uncharged object gets charged, This process of charging is called Conduction Charging.

When a charged rod touches the metal sphere, sphere gets same charged as the rod. The process of charging a sphere by touching it with a charged rod. is called conduction charging.

For more details about the conduction and induction charging, follow the link given below.

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Answer:

induction and conduction or 3,2 or c and b

Explanation:

edge 2022

Answer:

This above a triangle that models our situation.

Explanation:

We have a two componens., since we have a western componet and southern component. One travel in a southern direction. and the other travel in the west.

Let the component that travel in the south be the length of a.

According to the problem, the westard component is half of that so let that length be a/2.

Now we must find the angle of the wind in the South.

This means that what is angle that is opposite of the western componet because that angle is the most southward angle. So know we apply the tan property.

[tex] \tan(x) = \frac{opp}{adj} [/tex]

Our side opposite of the angle we trying to find is the western component and the side adjacent to it is the southern component. Also remeber since western and Southern negative displacements, we have

[tex] \tan(x) = \frac{ - \frac{a}{2} }{ - a} [/tex]

[tex] \tan(x) = - \frac{a}{2} \times - \frac{1}{a} = \frac{1}{2} [/tex]

Now we take the arctan or inverse tan of 1/2.

[tex] \tan {}^{ - 1} ( \frac{1}{2} ) = 26.57[/tex]

Based on the information about vector components and graph provided, the angle of the wind with the south is 26.57°.

The western and southern component have a negative displacement as shown in the graph.

Let the southern component be -x

The western component is half of -x = -x/2

Since the angle is with the south, the trigonometric ratio to be used to find the angle is:

Tan θ = -×/2 /-x

Tan θ = 1/2

θ = tan^-1(0.5)

θ = 26.6°

Therefore, angle of the wind with the south is 26.57°.

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Answer:

Doubling the large mass

Explanation:

By doubling the mass you will get more gravational force

Answer:

There are many forces involved in the game of football. These are: Force of Gravity, Normal Force, Force of Friction, and Applied Force. Force of Gravity applies to football when the football is thrown or kicked, when a player jumps in the air to avoid a tackle or catch a ball, and is constantly being applied.

Explanation:

How physics is used in football?

When you throw a football across the yard to your friend, you are using physics. You make adjustments for all the factors, such as distance, wind and the weight of the ball. The farther away your friend is, the harder you have to throw the ball, or the steeper the angle of your throw.