The work done by friction on the roller coaster cart during its motion up the ramp is -813 kJ
Conservation of energyThe total mechanical energy at the bottom of the tall ramp, E equals the total mechanical energy at the top of the tall ramp, E'
E = E'
U + K + W = U' + K' + W' where
U = initial potential energy of block = mgh , K = initial kinetic energy of block = 1/2mv², W = work done by friction at bottom of rampU = final potential energy of block = mgh', K' = final kinetic energy of block = 1/2mv'² and W' = work done by friction at top of rampSo,
mgh + 1/2mv² + W = mgh' + 1/2mv'² + W' where
m = mass of block = 1550 kg, g = acceleration due to gravity = 9.8 m/s², h = initial height of block = 0 m, v = initial velocity of block = 2.3 m/s, W = work done by friction at bottom of ramp = 0 J, h' = height of ramp = 53.5 m, v' = final velocity of block = 2.3 m/s = v (since it moves at constant speed), and W' = work done by friction at top of ramp. Work done by frictionSubstituting the values of h, W and v' into the equation, and making W' subject of the formula, we have
mgh + 1/2mv² + W = mgh' + 1/2mv'² + W'
mg(0) + 1/2mv² + 0 = mgh' + 1/2mv² + W'
0 + 1/2mv² + 0 = mgh' + 1/2mv² + W'
1/2mv² - 1/2mv² - mgh' = W'
W' = -mgh
Substituing the values of the variables into the equation, we have
W = -mgh
W = 1550 kg × 9.8 m/s² × 53.5 m
W = -812665 kgm²/s²
W = -812665 J
W = -812.665 kJ
W ≅ -813 kJ
So, the work done by friction on the roller coaster cart during its motion up the ramp is -813 kJ
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HELP PLEASE Which of the following is a true statement?
All organisms in an ecosystem eat decomposers to survive.
All organisms in an ecosystem eat decomposers to survive.
All organisms rely on photosynthesis, which is done by decomposers.
All organisms rely on photosynthesis, which is done by decomposers.
All organisms generate waste and dead material that is recycled by decomposers.
All organisms generate waste and dead material that is recycled by decomposers.
All organisms are considered decomposers in aquatic ecosystems since all organisms are underwater.
Answer: All organisms generate waste and dead material that is recycled by decomposers.
Explanation: Give me brainiest!
A car starts from rest and reaches a speed of 14/s in 10 s Its acceleration is what?
Answer:
acceleration = change in velocity / change in time
acceleration = 14/10
acceleration = 1.4/s^2
A 0.37 kg rock is thrown vertically upward from the top of a 37 m
cliff. When it hits the ground at the base of the cliff, the rock has a
speed of 33 m/s. Consider that air resistance is negligible. Use
conservation of total mechanical energy principle to find
a. The initial speed of the rock.
b. The greatest height of the rock as measured from the base of the
cliff.
c. Comment on the types of mechanical energy of the rock when
i) it is thrown upward, ii) it reached the maximum height, and
iii) it reached the base of the cliff.
(a) The initial speed of the rock is 19.1 m/s.
(b) The greatest height of the rock as measured from the base of the
cliff is 55.6 m.
(c) i. As the ball is thrown up, its kinetic energy is converted to potential energy.
ii. When then ball reaches the maximum height, its kinetic energy becomes zero and it will have maximum potential energy.
iii. When the rock reaches the base of the cliff, its potential energy becomes zero and it will have maximum kinetic energy.
Conservation of mechanical energyThe initial speed of the rock is determined by applying the principle of conservation of mechanical energy as shown below;
Ui + K.Ei = Uf + K.Ef
mghi + ¹/₂mvi² = mghf + ¹/₂mvf²
(0.37 x 9.8 x 37) + ¹/₂(0.37)vi² = (0.37 x 9.8 x 0) + ¹/₂(0.37 x 33)²
134.16 + 0.185vi² = 0 + 201.47
0.185vi² = 201.47 - 134.16
0.185vi² = 67.31
vi² = 67.31/0.185
vi² = 363.84
vi = √363.84
vi = 19.1 m/s
Height reached by the rock from top cliffvf² = vi² - 2gh
0 = vi² - 2gh
2gh = vi²
h = vi²/2g
h = (19.1)²/(2 x 9.8)
h = 18.6 m
Maximum height reached by rock from the base of the cliffThe maximum height from the base = 37 m + 18.6 m = 55.6 m
When the ball is thrown up, its kinetic energy is converted to potential energy.
When then ball reaches the maximum height, its kinetic energy becomes zero and it will have maximum potential energy.
When the rock reaches the base of the cliff, its potential energy becomes zero and it will have maximum kinetic energy.
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write the standard of 1 metere
Let's see
[tex]\\ \rm\Rrightarrow 1metre= 10^2cm[/tex]
[tex]\\ \rm\Rrightarrow 1m=10^3mm[/tex]
[tex]\\ \rm\Rrightarrow 1m=10^6\mu m[/tex]
[tex]\\ \rm\Rrightarrow 1m=10^{-3}km[/tex]
[tex]\\ \rm\Rrightarrow 1m=10^{9}nm[/tex]
the teacher uses the ____ theorem to solve the equation.
A) mass-acceleration
B) work-energy
Answer:
B) work-energy
Explanation:
It is the work-energy theorem as there is no theorem called "mass-acceleration theorem" [unless you consider Newton's Second Law (maybe?) but not really].
Its postulates are :
Work done by all the forces = Change in Kinetic Energy. W g + W N + W f =K f – K i Where W g = work done by gravity W N = work done by a normal forceW f = work done by frictionK f = final kinetic energy.3. Which of the following are true of static electricity charges? *
+
A positively charged object has lost electrons.
A positively charged object has gained protons.
A positively charged object has gained electrons
PLEASE HELP ME !! STUCK ON THIS!
Which choice describes the purpose of the blades in a wind turbine?
A) The blades convert wind energy into rotational energy.
B) The blades include a gearbox and a generator.
C) The blades create charges inside an electromagnet.
D) The blades provide structural support to the turbine.
Answer:
A is the basis for all of the other assumptions.
Everything else supports A.
Answer:
A) The blades convert wind energy into rotational energy.
Explanation:
Wind turbines use blades to collect the wind's kinetic energy. Wind flows over the blades creating lift (similar to the effect on airplane wings), which causes the blades to turn. The blades are connected to a drive shaft that turns an electric generator, which produces (generates) electricity.
The figure is a cross section through three long wires with linear mass density 55.0 g/m. They each carry equal currents in the directions shown. The lower two wires are 4.0 cm apart and are attached to a table. (Figure 1)
The current that will allow the upper wire to float so as to form an equilateral triangle with the lower wires is 328.3 A.
Net force at the center of the equilateral triangleThe current that will allow the upper to float will form zero resultant force due to the current at the left and the current at the right.
Weight effect of the wires acting downwardsW = mg
W = (σL)g
Resultant electric force of the two upward wires[tex]F_1 = F_2 = \frac{\mu_o I^2 l}{2\pi r}[/tex]
The total force due to angle formed by the top wire
[tex]F_t = F_1cos\theta + F_2 cos \theta= 2Fcos\theta = \frac{2\mu_o I^2 l \times cos\theta}{2\pi r} \\\\F_t = \frac{\mu_o I^2 l \times cos\theta}{\pi r}[/tex]
At equilibrium the upward force must equal downward force
[tex]\sigma lg=\frac{\mu_o I^2 l \times cos\theta}{\pi r}\\\\I^2 = \frac{\sigma lg \pi r}{\mu_0 l \times cos\theta} = \frac{\sigma g \pi r}{\mu_0 \times cos\theta} \\\\I^2 = \frac{(0.055)\times 9.8\pi \times 0.04 }{4\pi \times 10^{-7} \times cos60} \\\\I^2 = 107,800\\\\I = \sqrt{ 107,800} \\\\I = 328.3 \ A[/tex]
Thus, the current that will allow the upper wire to float so as to form an equilateral triangle with the lower wires is 328.3 A.
Complete question is below:
The figure is a cross section through three long wires with linear mass density 55.0 g/m. They each carry equal currents in the directions shown. The lower two wires are 4.0 cm apart and are attached to a table. (Figure 1). What current I will allow the upper wire to "float" so as to form an equilateral triangle with the lower wires?
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In Figure 10.13, the author illustrates a book being raised at constant speed. Which of the following statements are true? Select all that apply.
There is no change in the kinetic energy of the book.
The potential energy of the book-Earth system decreases.
The potential energy of the book-Earth system increases.
The potential energy of the book increases.
Answer:
There is no change in the kinetic energy of the book and the potential energy of the book-Earth system increases.
Explanation:
This is because velocity is constantly increasing. This supports the idea that the kinetic energy of the book doesn't change and that the potential energy of the book-Earth system increases.
The true statement is that ;there is no change in the kinetic energy of the book and the potential energy of the book-Earth system increases.
We have to note that from the law of conservation of mechanical energy, the sum of the kinetic and potential energy of the book at any point remains constant.
If the book is being raised at constant speed, the the true statement is that ;there is no change in the kinetic energy of the book and the potential energy of the book-Earth system increases.
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Rock candy is made from crystallized sugar. What is crystallization?
Answer: Rock candy is candy made of large sugar crystals. To make rock candy, a supersaturated solution of sugar in water is created and left undisturbed for a few days. The driving force behind crystallization is supersaturation.
effect of earthquake Causes of earthquake and protection against earthquake. final conclusion
Causes of earthquake:
1 Groundwater extraction – decrease in pore pressure
2. Groundwater – increase in pore pressure.
3. Heavy rain.
4. Pore fluid flow.
5. High CO2 pressure.
6. Building dams.
Effects of earthquake:
1. Loss of lives
2. Increase in government expenditure
3. Loss of properties
Protection against earthquake:
We cannot prevent natural earthquakes from occurring but we can significantly mitigate their effects by identifying hazards, building safer structures, and providing education on earthquake safety. By preparing for natural earthquakes we can also reduce the risk from human induced earthquakes.
A 10 g piece of sticky clay moving horizontally with a speed of 12 m/s strikes a pendulum bob and sticks to the bob. The pendulum bob has a mass of 50 g and it is suspended from a 0.7 m string.
a. Find the momentum of the clay before the collision.
b. *Find the momentum of the clay-bob system after the collision.
c.*Find the velocity of the clay-bob system after the collision.
d. *Find the kinetic energy of the clay-bob system after the collision.
e. *Find the maximum height of the clay-bob system that they deflect after the collision.
f. *What velocity should the clay have before the collision in order for the clay-bob system to complete one circle?
Answer:
it is d that my answer to the question
a. The momentum of the clay before the collision is 0.12m/s
b. The momentum of the clay-bob system after the collision is 0.12m/s
c. The velocity of the clay-bob system after the collision is 2m/s
d. The kinetic energy of the clay-bob system after the collision is 0.12m/s
e. The maximum height of the clay-bob system that they deflect after the collision is 0.204m
f. The velocity clay should have before the collision in order for the clay-bob system to complete one circle is 35.13m/s
What is momentum?Momentum is the product of mass and velocity
It is given by ,
p= mv
where, p = momentum
m = mass
v = velocity
What is velocity?velocity is the rate of change of displacement.
To solve , we use Law of conservation of momentum and Law of conservation of mechanical energy
What is Law of conservation of momentum?
Law of conservation of momentum states that in absence of any external forces , the momentum of a system always remains conserved.
i.e,
The momentum of the system before collision = momentum of the system after collision.
[tex]m_{1} u_{1} + m_{2} u_{2} = m_{1} v_{1} + m_{2} v_{2}[/tex]
Where,
m₁ = mass of first body.
m₂ = mass of the second body.
u₁ = velocity of first body before collision,
u₂ = velocity of the second body before collision
v₁ = velocity of first body after collision
v₂ = velocity of first body after collision.
v₂ = velocity of second body after collision.
What is law of conservation of mechanical energyThe Law states that the total mechanical energy of a system remains conserved and energy can be converted from one form to another form.
The sum of kinetic energy an potential energy is equal to total mechanical energy which is a constant.
So, K.E + P.E = constant
a, Here mass of clay m₁ = 10g = 0.01kg,
velocity of the clay = 12m/s.
therefore, momentum p = mv.
p = 0.01 x 12 = 0.12kg m/s.
Hence momentum of clay is 0-12kg m/s.
b. The momentum of clay - bob system after collision is
From law of conservation of momentum ,
final momentum = initial momentum
since initial momentum = 0.12kg m/s
therefore momentum of the clay-bob system after collision is 0.12kg m/s
c. To find the velocity of the body we apply law of conservation of momentum
[tex]m_{1} u_{1} + m_{2} u_{2} = m_{1} v_{1} + m_{2} v_{2}[/tex]
Here m₁u₁ = 0.12kgm/s
m₂u₂ = 0 (since bob is at rest initally)
m₁ = 10g = 0.01kg
m₂ = 50g = 0.05kg
after collision the system moves with a common velocity v
So,
m₁u₁ = (m₁ + m₂)v
0.12 = (0.01 + 0.05 ) v
So, v = 0.12/0.06 = 2m/s
Hence velocity of clay -bob system after collision is = 2m/s.
d. The kinetic energy of the clay-bob system after the collision.
kinetic energy = 1/2 mv²
Here. m = 0.06kg
v = 2m/s
therefore K.E = (1/2)x 0.06 x 2²
K.E = 0.12J
Hence Kinetic energy of the clay-bob system after collision is 0.12J
e. The maximum height of the clay-bob system that they deflect after the collision.
From Law of Conservation of mechanical energy we have,
The kinetic energy = The potential energy
so, 1/2 mv² = mgh
Here, m = 0.06kg
g= 9,8m/s²
h = height.
So, h = 2/9.8 = 0.204m
Hence height to which the clay-bob system will rise after collision is 0.204m
e. To find the velocity that clay should possess before collision in order for the clay- bob system to gain the velocity so that it completes the circle -
The velocity that the particle should have at the bottom of the circle in order to complete the circle is v = [tex]\sqrt{5rg\\}[/tex]
Where, r = radius of the circle
g = acceleration due to gravity
Here,
r = 0.7m
g = 9.8m/s
So, v = [tex]\sqrt{5 X0.7 X 9.8 }[/tex] = 5.85m
So clay-bob system should have a velocity of 5.85m at the bottom of the circle so that it can complete the circle
Now, applying Law of conservation of momentum
m₁u₁ = (m₁ + m₂)v
Here, m₁ = 0.01kg
m₂ = 0.05kg
v = 5.85m/s
So, 0.01u₁ = 0.06 x 5.85
Hence u₁ = 35.13m/s
So velocity that clay should have is 35.13m/s.
Therefore the solution of the question is
. The momentum of the clay before the collision is 0.12m/s
b. The momentum of the clay-bob system after the collision is 0.12m/s
c. The velocity of the clay-bob system after the collision is 2m/s
d. The kinetic energy of the clay-bob system after the collision is 0.12m/s
e. The maximum height of the clay-bob system that they deflect after the collision is 0.204m
f. The velocity clay should have before the collision in order for the clay-bob system to complete one circle is 35.13m/s
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#SPJ2
50 points if you want it
Answer:
Angular momentum increases and gravitational potential energy decreases after the bug lands.
Explanation:
After the bug lands, the rod begins to rotate. As the system was at rest before, when it begins to rotate, its angular momentum increases from zero to positive.
As the rod begins to rotate, the heavier mass of bug and sphere goes down while the lighter mass of sphere goes up. So the system's gravitational potential energy decreases.
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Energy cannot be changed from one variety to another.
True or False
Answer:
False, Hope this helps.
Please answer this question. Thank you and have a fruitful day.
Answer:
top box: upthrust
right box: water resistance
bottom box:gravity / weight
left box: thrust
Explanation:
You too have a fruitful day! Hope I could help!
#Down
The weight of the ship is pulling downwards#Up
Upthrust or buyoant force of water#Left
The force of motor
#Right
Drag force of airWhich of this following value on the absolute scale of temperature is to the point
Answer:
D
Explanation:
because the correct answer is D
A 5.0 kg book is lying on a 0.25 meter high table.
You pick it up and place itn on a bookshelf 1.85 m above the floor.
During this process:
a.) How much work does your hand do on the book? J
(round to the nearest full joule)
Answer:
Below in the picture:-
I hope it helps.
A crate is released from the highest point of a 12 m long ramp inclined at 60° with the horizontal. The motion is frictionless. What is the speed of the crate at the base of the ramp?
law of conservation of mechanical energy
PE1 = Ek2
mgh=1/2mv²
h = 12 sin 60
[tex]\tt v=\sqrt{2gh}=\sqrt{2\times 9.8\times 12\times sin~60}=14.27~m/s[/tex]
you have two positively charged spheres. one sphere has 3 times the charge of the other sphere if they are 0.16m apart and the force between them is 0.28 N, what are the charges of the two spheres?
this is the answer
pls give brainliest
A circular metal disc is heated. Which quantity decreases?
Answer:
Bbbbb. Metal disc.
Explanation:
Sent from my Huawei and I am not a good person and I am not a good person and I am not a good person and I am not a good person
a An electron is placed in a uniform electric field with field strength of 150lavono calculate the duration fort to travel somm from its stationary position. Give an Explanation for your Answer.
Explanation:
Explanation for your Answer.
When studying energy, the main units to consider are the calories. However, many times the needed numbers are not readily available. Often, conversions need to be done in order to calculate the correct values. Knowledge of the metric system is essential to do this successfully.
If a female lion runs a distance of 469.2 meters while chasing an antelope, how many millimeters did she run?
A.
0.0004692 mm
B.
0.4692 mm
C.
46,920 mm
D.
469,200 mm
Answer:
B. O.4692 mm
Explanation:
I hope its help keep safe
Answer:
Its D trust me it is
Explanation:
A Wave with a Frequency of 500 Hz is travelling at Speed of 200 m^-1 . What is its Wavelength ?
Question :-
A Wave with a Frequency of 500 Hz is travelling at Speed of [tex] \bf {200 \: m ^{-1}} [/tex] . What is its Wavelength ?Answer :-
Wavelength of the Wave is 0.4 m .[tex] \rule {180pt} {2pt} [/tex]
Given :-
Frequency = 500 HzSpeed = [tex] \bf {200 \: m ^{-1}} [/tex]To Find :-
Wavelength = ?Solution :-
As per the provided information in the given question, we have been given that the Frequency of the Wave is 500 Hz . Its Speed is given [tex] \bf {200 \: m ^{-1}} [/tex] . And, we have been asked to calculate the Wavelength .
For calculating the Wavelength , we will use the Formula :-
Wavelength = Speed / FrequencyTherefore , by Substituting the given values in the above Formula :-
⇒ Wavelength = 200 / 500
⇒ Wavelength = 2 / 5
⇒ Wavelength = 0.4
Hence :-
Wavelength = 0.4 m[tex] \underline {\rule {180pt} {4pt}} [/tex]
An object, initially at rest, accelerates uniformly with an acceleration of 6 m/s². What is the displacement of the object after 10 s?
a. 300m
b. -300m
c. 600 m
d. -600m
A force of 345 N is applied to a 70 kg scooter. What will the scooter's
acceleration be?
Explanation:
here, force applied (N) = 345 N
or, mass of scooter (m) = 70 kg
now, acceleration (a) = ?
we know, force = mass × acceleration
or, 345 = 70 × acceleration
or, acceleration = 345/70
therefore, acceleration = 4.9 m/s2 (meter/second square)
Express 900 rev/hour (rpm) in rad/s
Answer:
900 Revolution/Minute (rev/min)
=
94.24778 Radian/Second (rad/s)
Explanation:
In astronomy, distances are often expressed in lightyears. One lightyear is the distance that light travels in one Earth year. The distance to Alpha Centauri, the next closest star, is 4.3 lightyears away. How far is this in meters?
Answer is ...
Happy to help ..
The carbon atom has an atomic number of 6 and its atomic mass number is 12.
How many neutrons does the carbon atom have?
Answer:
If it has 12 nucleons and 6 of them are protons the other six must be neutrons (6).
50 points, absurd answers will be reported if there are no answer content
Answer:
Angular momentum increases and gravitational potential energy decreases after the bug lands.
Explanation:
After the bug lands, the rod begins to rotate. As the system was at rest before, when it begins to rotate, its angular momentum increases from zero to positive.
As the rod begins to rotate, the heavier mass of bug and sphere goes down while the lighter mass of sphere goes up. So the system's gravitational potential energy decreases.
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Forest protect the soil from erosion ? True or False
Answer:
TrueForests helps in binding the soil together. Thus, prevent soil from erosion.
Answer:
True
Explanation:
Forest protect the soil from erosion because the trees in the forest hold the soil together not allowing it to erode.