Engineering College

4. Oil system cleaning products should not use solvents because:
A) O Solvents smell bad
B) Solvents are completely removed during the service
CO Solvents have no impact on dirt and debris
DO Solvents can damage certain plastics and rubbers found in the engine
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Answers

Answer 1

Answer:

Solvents can damage certain plastics and rubbers found in the engine

Explanation:

Related Questions

If a nurse does not agree to the discipline set due to a complaint made against this nurse, after reviewing the proposed agreed order, they can request a

Answers

Ans: If the nurse doesn't agree with the proposed order, the conference provides the nurse with an opportunity to respond to the allegations and dispute the evidence or proposed disciplinary action and to provide additional information for the board's consideration.

What distinguishes the research, investigation, and analysis phase from later phases of the historical preservation process?


It involves careful attention to the history of the structure.

It is the only phase that does not involve construction.

It is primarily involved with fact finding.

It is the only phase that does not involve design.

Answers

Answer:

c

Explanation:

A piece of corroded steel plate was found in a submerged ocean vessel. It was estimated that the original area of the plate was 5 in.2 and that approximately 2.3 kg had corroded away during the submersion. Assuming a corrosion penetration rate of 200 mpy for this alloy in seawater, estimate the time of submersion in years. The density of steel is 7.9 g/cm3.

Answers

Answer:

the estimated time of submersion is 17.7 years

Explanation:

Given the data in the question;

estimate the time of submersion in years.

we write down the relation between time of submersion and corrosion penetration as follows;

CPR(mpy) = K × W(mg) / [ A(in²) × p(g/cm³) × t(hr) ]

we solve for t

t = (K × W) / ( AP × CPR )

given that;  

Area A = 5 in²

W = 2.3 kg = 2.3 × 10⁶ mg

density of steel p = 7.9 g/cm³

CPR = 200

we know that K is 534

so we substitute

t = (534 × 2.3 × 10⁶ mg) / ( 5 in² × 7.9 g/cm³ × 200 mpy )

t = 1,228,200,000 / 7900

t = 155468.3544 hr

t = 155468.3544 hr × ( 1 yrs / ( 365 × 24 hrs )

t = 17.7 years

Therefore, the  estimated time of submersion is 17.7 years

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