Factorization involves breaking down an expression.
The factorized expression of [tex]8x^3 + 27[/tex] is [tex]8x^3 + 27 =(2x + 3)(4x^2 -8x3 +9)[/tex]The other factor of [tex]2^3 - b^3[/tex] is [tex]4+2b+b^2[/tex]The factorized expression of x^3 - 1 is [tex]x^3 - 1^3=(x-1)(x^2+x+1)[/tex]The sum of cubes is given as:
[tex](a^3 + b^3) = (a + b)(a^2 -ab + b^2)[/tex]
(a) Verify the formula
Expand the expression on the right-hand side
[tex](a^3 + b^3) = a^3 -a^2b + ab^2 +a^2b - ab^2 + b^3[/tex]
Collect like terms
[tex](a^3 + b^3) = a^3 -a^2b +a^2b+ ab^2 - ab^2 + b^3[/tex]
[tex](a^3 + b^3) = a^3 + b^3[/tex]
The formula has been verified
(b) Factorized 8x^3+ 27
We have:
[tex]8x^3 + 27[/tex]
Express 27 as 3^3
[tex]8x^3 + 27 =8x^3 + 3^2[/tex]
Express 8 as 2^3
[tex]8x^3 + 27 =2^3x^3 + 3^3[/tex]
Rewrite as:
[tex]8x^3 + 27 =(2x)^3 + 3^3[/tex]
Given that:
[tex](a^3 + b^3) = (a + b)(a^2 -ab + b^2)[/tex]
The expression becomes
[tex]8x^3 + 27 =(2x + 3)((2x)^2 - (2x)3 +3^2)[/tex]
[tex]8x^3 + 27 =(2x + 3)(4x^2 -8x3 +9)[/tex]
(c)The other factor of 2^3 - b^3
By difference of cubes, we have:
[tex]x^3 - y^3=(x-y)(x^2+xy+y^2)[/tex]
So, the equation becomes
[tex]2^3 - b^3=(2-b)(2^2+2b+b^2)[/tex]
This gives
[tex]2^3 - b^3=(2-b)(4+2b+b^2)[/tex]
Hence, the other factor of [tex]2^3 - b^3[/tex] is [tex]4+2b+b^2[/tex]
(c) Factor x^3 - 1
We have:
[tex]x^3 - y^3=(x-y)(x^2+xy+y^2)[/tex]
Express 1 as 1^3 in x^3 - 1
[tex]x^3 - 1 =x^3 - 1^3[/tex]
[tex]x^3 - y^3=(x-y)(x^2+xy+y^2)[/tex] becomes
[tex]x^3 - 1^3=(x-1)(x^2+x+1^2)[/tex]
[tex]x^3 - 1^3=(x-1)(x^2+x+1)[/tex]
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LAST ATTEMPT IM MARKING AS BRAINLIEST!! (Draw a dilation of the figure using the given scale factor )
Multiply and fill in the blanks
a) 5pq(p2+ q2+pq)
b) -7pr (pq – qr - rq)
c) (4x-3y) (5x-4a)
with explanation pls !
The solution to the simplification of the algebraic expressions are;
A) 5p³q + 5pq³ + 5p²q
B) 14pqr² - 7p²qr
C) 20x² - 15xy - 16ax + 12ay
A) We have the expression;
5pq(p² + q² + pq)
Multiplying out using the concept of distributive property, we have;
(5pq × p²) + (5pq × q²) + (5pq × pq)
>> 5p³q + 5pq³ + 5p²q
B) We have the expression;
-7pr(pq – qr - rq)
Multiplying out using the concept of distributive property, we have;
-7p²qr + 7pqr² + 7pqr²
>> 14pqr² - 7p²qr
C) (4x - 3y)(5x - 4a)
By quadratic expansion, we have;
(4x * 5x) - (3y * 5x) - (4x * 4a) + (4a * 3y)
>> 20x² - 15xy - 16ax + 12ay
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LOOK AT THE PICTURE ATTACHED AND HELP QUICKLLYYYYY PLZZZ!!!!
Answer: √490
Step-by-step explanation:
2 FOR 2.20 UNIT RATE
Answer: (if your asking for the unit rate of that)
the unit rate is 1.10
Answer:
1.10
Step-by-step explanation:
2 /2 = 1
20/ 2 = 10
1.10 is the unit rate
How do you know when to rewrite square trinomials and difference of squares binomials as separate factors? How can sums and differences of cubes be identified for factoring?
Answer:
Step-by-step explanation:
You asked: How do you know when to rewrite square trinomials and difference of squares binomials as separate factors? First, and mostly obviously is when the directions say to factor the given expression. Next, if you're given an equation and asked to solve it. You set it equal to 0 and factor the perfect square trinomial or the difference of squares binomial. Set each factor equal zero and solve. This is a little bit oversimplified but, solutions are roots are zeros are x-intercepts, so if you are asked to find any of those things. Set your equation equal to zero, factor and solve. Also, if you have a rational expression (a fraction with a polynomial on top and a polynomial on the bottom) you would need to factor in order to simplify, to sketch a graph without technology. Anytime you need to simplify, factoring is good to try.
You also asked: How can sums and differences of cubes be identified for factoring? The sum or difference of cubes is in the form a^3 + b^3 or a^3 - b^3
You can memorize how to factor these a^3 + b^3 = (a+b)(a^2 - ab + b^2) and
a^3 - b^3 = (a-b)(a^2 + ab + b^2)
If you take the trouble to multiply these two factors back together you will see how four terms drop out and you get a binomial. Also the is an acronym SOAP to help you memorize it. Factoring cubes is used in the same way as you previous question. To factor, to solve, to simply, to graph. This was a really general question. I hope this helps.
suppose Amaya wants to bake cookies that require 4.5 cups of flour for a recipe that makes 4 dozen cookies. how much flour would Amaya need to make 126 cookies?
Answer:
11.8125 cups of flour
Step-by-step explanation:
4 dozen = 48 cookies
126/48=2.625 batches of 48 cookies
2.625 x 4.5 = 11.8125 cups of flour
A squares diagonal is 22. What is the length of each side?
Answer:
[tex]\sqrt{242}[/tex]
what is the slope of (-1,-2) and (-2,2)
[tex]\text{Given that,}\\\\(x_1,y_1) = (-1,-2)~~ \text{and}~~ (x_2,y_2) = (-2,2)\\\\\text{Slope, m =} \dfrac{y_2-y_1}{x_2 -x_1} = \dfrac{2 -(-2)}{-2-(-1)} = \dfrac{2+2}{-2+1} = \dfrac{4}{-1} = -4[/tex]
find the greatest common factor GCF and the least common multiple LCM of these Numbers. 8and 9
Answer:
LCM is [tex]72[/tex]
GCF is [tex]1[/tex]
Step-by-step explanation:
LCM is least common multiplier
LCM of
[tex]8,9=8\times 9\\\\=72[/tex]
GCF is greatest common factor
Factors of [tex]8=1,2,4,8[/tex]
Factors of [tex]9=1,3,9[/tex]
Greatest common factor is [tex]1[/tex]
GCF is [tex]1[/tex]
3.8×102+1.7×103 giving answer in standard form
Answer: 5.15 x 10^2
Step-by-step explanation:
3.8 x 103 + 1.7 x 103 = 5 x 103 = 515 = 5.15 x 10^2
3. Vocabulary Suppose △MNP ∼△RST. How can you identify corresponding parts?
4. Reasoning Suppose △ABC ∼△TUV. Determine whether each pair of measures is equal.
a. the measures of ∠A and ∠T
b. the perimeters of the two triangles
c. the ratios of the sides BC/UV and AC/TV
5. Reasoning e scale of a map is 1 in. : 100 mi. Is the actual distance between two towns 100 times the map distance between the two towns? Explain.
Similar triangles may or may not have congruent sides, but the ratio of the corresponding sides will always be congruent.
(3) Corresponding sides of △MNP and △RST
Given that △MNP ∼△RST.
This means that, the corresponding sides are:
MN and RSMP and RTNP and ST(4) The equal measures
Given that △ABC ∼△TUV
This means that, the corresponding angles are equal, but corresponding sides are not.
So, the equal measures are:
(a). the measures of ∠A and ∠T (c). the ratios of the sides BC/UV and AC/TVThe unequal measure is:
(b). the perimeters of the two triangles(c) Scale mapping
The scale mapping is given as:
[tex]Ratio = 1\ in : 100\ mi[/tex]
The above scale means that 1 inches on the scale represents 100 miles of the actual distance.
Take for instance, 5 inches would represent 500 miles.
500 is 5 times 100
Hence, the actual distance between two towns 100 times the map distance between the two towns
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There are some red and blue balls in a bag of 21 balls and the probability of picking 2 red balls out in a row is 1/14 how many red balls are there?
Answer:
6 red balls
Step-by-step explanation:
The probability in the first pick
6/21
The probability in the second pick (without replacement)
5/20
the requested probability
(6/21)(5/20) = 30/420
simplification
30/420 = 3/42 = 1/14
Hope this helps
Answer:
6 red balls.
Step-by-step explanation:
If there are x red balls then
probability of 2 red balls
= x/21 * (x - 1)/20 = 1/14
x^2 - x / 420 = 1/14
x^2 - x = 30
x^2 - x - 30 = 0
(x - 6)(x + 5) = 0
x = 6.
19z+12=20z–8
help i dont really understanddd!!!
Answer:
z = 20
Step-by-step explanation:
subtract 19z from 20z, and add 8 to 12. you will be left with 20 = 1z. Divide 1 by 20 and you will have Xz =20.
I hope this helps!
I NEED HELP PLEASE 15 POINTS
13) Given that m∠EFJ = 70°, find m∠KFG. A) 10° B) 20° C) 30° D) 40°
Answer:
20°
Step-by-step explanation:
∡EFJ = 70°
∡JFK = 90°
So, ∡KFG = 180 - ∡JFK - ∡EFJ = 180 - 90 - 70 = 20°
Answer:
60
Step-by-step explanation:
i put 30 then it said the answer was 60
£ 23 PER WEEK TRAVEL HOW MUCH FOR 2 YEARS
Answer: the cost would be 2398.19
Step-by-step explanation: hope this helps:)
Help me to solve this
Step-by-step explanation:
first we use Pythagoras to get t :
c² = a² + b²
with c being the Hypotenuse.
so,
t² = r² + s² = 10² + 31² = 100 + 961 = 1061
t = sqrt(1061)
and then we use the law of sine :
a/sin(A) = b/sin(B) = c/sin(C)
with the angles being opposite of their related sides.
so, r/sin(R) = t/sin(T) = t/sin(90) = t/1 = t
sin(R) = r/t = 10/sqrt(1061) = 0.30700278...
R = 17.8786966... ≈ 17.9°
evaluate:
16÷(2+12)2
A. 2 14/25
B. 4 1/4
C. 6 2/5
D. 8 1/4
The result of the given expression in simplest form is [tex]\frac{4}{7}[/tex].
The given parameters:
16÷(2+12)2
The given expression can be evaluated in the following order as shown below;
add the numbers in the bracket;
2 + 12 = 14
multiply the numbers in the bracket by 2;
14 x 2 = 28
divide the 16 by your result after the multiplication;
[tex]= \frac{16}{28} \\\\[/tex]
divide the numerator and denominator by their common factor which is 4;
[tex]\frac{16}{(2+ 12) 2} = \frac{16}{28} = \frac{4}{7}[/tex]
Thus, the result of the given expression in simplest form is [tex]\frac{4}{7}[/tex].
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Can someone help Pleasaseee
Answer:
i think it's 1.8.
Step-by-step explanation:
why? bc if u add 6/20 + 1.5 = 1.8
i think it's 1.8, im not sure, hopefully it's correct!!
Answer:
1.8
Step-by-step explanation:
you just simplify -6/20 into a decimal and you get .3 then you add it to 1.5.
Help me please ill mark as the brainiest if correct. I don't know how so please tell me
Answer:
:)))))
Step-by-step explanation:
<3
Y=x+3 please helppppppppppol
Answer:
(-1, 2), (0,3), (1,4)
slope= 1
y-intercept= (0,3)
Step-by-step explanation:
Resuelve la siguiente ecuación lineal: 13-4(5x+1)=3(7-5x)-15
.........................
An angle measures 157.2° more than the measure of its supplementary angle. What is the measure of each angle?
Two supplementary angles equal 180 degrees
Subtract the difference from 180:
180-157.2 = 22.8
Divide by 2:
22.8 /2 = 11.4
One angle is 11.4
Now add the difference to 11.4
11.4 + 157.2 = 168.6
The second angle is 168.6
Answer: 11.4 and 168.6
In the rectangular trapezoid ABCD AC is driven by a CD (see figure).
Find the area of the trapezoid if AC = 3, AD = 5.
Answer:
10.5
Step-by-step explanation:
A=a+b
2h=2+5
2·3=10.5
Answer:
solution given:
let's see only in a right-angled triangle Δ ACD.
AC=3 units
AD=5 units
since Δ ACD is a right-angled triangle. It satisfies Pythagoras law
[tex]AD^{2}=AC^{2}+CD^{2}[/tex]
25=9+[tex]CD^2[/tex]
[tex]CD^2[/tex]=25-9=16
[tex]CD=\sqrt{16} =4 units[/tex]
Now
Area of rectangle Δ ACD=[tex]\frac{1}{2} CD*AC=\frac{1}{2}*4*3=6\: square \:units[/tex]
similarly,
[tex]\frac{1}{2} AD*CE=6\: square \:units\\ 5*CE=6*2\\CE=\frac{12}{5}=2.4 units[/tex]
since AB=CE=2.4 units
Δ ACE is a right-angled triangle. It satisfies Pythagoras law.
[tex]AC^{2}=AE^{2}+CE^{2}\\3^2=AE^2+2.4^2\\9-5.76=AE^2\\AE and BC=\sqrt{1.24} =1.11 units[/tex]
now
area of trapezoid=area ofΔACD+Area of ΔABC
=6+[tex]\frac{1}{2}AB*BC=6+\frac{1}{2}*2.4*1.11=6+1.33 =7.33\: square \:units[/tex]
Step-by-step explanation:
A graph, a table and equation are shown below. Please help!
Answer:
A) slope is 1
B) Slope is 3
C) slope is 0.5
Step-by-step explanation:
Using Rise over run method and mx+b
The large rectangle below represents one whole. What percent is represented by the shaded area? %
Answer:
Step-by-step explanation:
would help a lot if you show the picture or describe it very well.
Don’t know where to start
Step-by-step explanation:
C = 2πr = 2 x π x 6 = 37.69911
What is the probability of randomly selecting a month pf year and not getting a month that ends in y?
Answer:
2/3
Step-by-step explanation:
The months whose names end in 'y' include Jan, Feb, May, Jul. The probability of randomly selecting a month whose name ends in 'y' is 4/12 (remember that there are 12 months in a year), or 1/3.
Thus, the probability of selecting a month whose name does NOT end in 'y' is 8/12, or 2/3. Note that this event is the 'complement' of the first event:
P(name does not end in 'y') = 1 - P(name does not end in 'y') = 1 - 1/3 = 2/3
In order to solve the following system of equations by elimination, which process creates opposite coefficients to eliminate the y variable?
2x + y = 5
x + 4y = -7
A. Multiply the first equation by 4
B. Multiply the second equation by 2
C. Multiply the first equation by -4
D. Multiply the second equation by -2
Answer:
C. Multiply the first equation by -4
Step-by-step explanation:
Hi there!
In order to eliminate the y values, we would have to find a number in which the sum of the top y value and the bottom y value would equal 0. In this case, the bottom y value is equal to +4 (the +4y), so we would have to find the number that would add to make that 0, which is -4. Since the y value for the top equation is 1, all we have to do is multiply the equation by -4 so that our y value is equal to -4y and the y can be eliminated.
I hope this helps!!
Use green’s theorem to evaluate
By Green's theorem (all the conditions are met), we have
[tex]\displaystyle \int_C \sqrt y \, dx + \sqrt x \, dy = \iint_D \frac{\partial(\sqrt x)}{\partial x} - \frac{\partial(\sqrt y)}{\partial y} \, dx \, dy[/tex]
where D is the interior of the path C, or the set
[tex]D = \left\{ (x, y) : 0 \le y \le \dfrac{x^2}2 \text{ and } 0 \le x \le 2 \right\}[/tex]
So, the line integral reduces to the double integral,
[tex]\displaystyle \frac12 \int_0^2 \int_0^{\frac{x^2}2} x^{-\frac12} - y^{-\frac12} \, dy \, dx[/tex]
[tex]\displaystyle = \frac12 \int_0^2 x^{-\frac12}\left(\frac{x^2}2\right) - 2\left(\frac{x^2}2\right)^{\frac12} \, dx[/tex]
[tex]\displaystyle = \frac12 \int_0^2 \frac12 x^{\frac32} - \sqrt 2 \, x \, dx[/tex]
[tex]\displaystyle = \frac14 \int_0^2 x^{\frac32} - 2\sqrt 2 \, x \, dx[/tex]
[tex]\displaystyle = \frac14 \left(\frac25\cdot2^{\frac52} - \sqrt2\cdot2^2\right) = \boxed{-\frac{3\sqrt2}5}[/tex]
16 #5) Describe the error in finding the value of x.