12(x+3y-6z)
please expand the answer!!!!

Answer:

A) 0

Step-by-step explanation:

x = 3 is a vertical line.

A line perpendicular to x = 3 is a horizontal line.

A horizontal line has slope = 0.

Answer: 0.024

Step-by-step explanation:

percents are out of 100 so 2.4% divided by 100 = the decimal. 2.4/100 = 0.024

Answer:

A recursive sequence is a sequence in which terms are defined using one or more previous terms which are given. If you know the nth term of an arithmetic sequence and you know the common difference , d , you can find the (n+1)th term using the recursive formula an+1=an+d .

Answer:

  (d)  -11

Step-by-step explanation:

The sum of the acute angles of a right triangle is 90°. (That makes the sum of all angles be 180°, as it is for any triangle.)

  65° +(36 +x)° = 90°

  x = 90 -101 . . . . . . . . divide by °, subtract 101

  x = -11

Answer:

can't you do Russian math homework on your own

Step-by-step explanation:

Answer:

you think about it. if you dont do the work yourself u wont ever learn.

Step-by-step explanation:

6x10^6=6,000,000

2.4x10^8=240,000,000

que dijiste buenas noches

Answer:

the answer is so you need takes Away -5

Step-by-step explanation:

it is because they are mentally disabled initially the Psychopaths but the social part and social

Answer It's gonna have to be i think mabey also 12

Step-by-step explanation:

12% of 125

or is ×

12% × 125

12% as a decimal

do you know what 12% is as a decimal comment below

Answer:

15

Step-by-step explanation:

12% of 125 is 15

Answer:

distance: 7.81 miles

Explanation:

simply use distance formula:  [tex]\sf \sqrt{(y_2 -y_1)^2 + (x_2-x_1)^2}[/tex]

using the equation:

[tex]\hookrightarrow \sf \sqrt{(8-3)^2+(10-4)^2}[/tex]

[tex]\hookrightarrow \sf \sqrt{(5)^2+(6)^2}[/tex]

[tex]\hookrightarrow \sf \sqrt{25+36}[/tex]

[tex]\hookrightarrow \sf \sqrt{61}[/tex]

[tex]\hookrightarrow \sf 7.81 \ miles[/tex]

It's a rectangle

Area:-

Four Answers:

====================================================

Explanation:

A rational number is any fraction of two whole numbers.

Examples: 7/9 and -8/12

This can be extended to some numbers like [tex]\sqrt{49}[/tex] because

[tex]\sqrt{49} = \sqrt{7^2} = 7 = \frac{7}{1}[/tex]

As you can see, any whole number is also rational but not the other way around.

So far, these examples help show that choices A, C, D, and J are rational numbers. Choice D might need a bit of rewriting like so:

[tex]\frac{0.5}{8} = 0.5 \div 8\\\\ = \frac{1}{2} \div \frac{1}{8} \\\\= \frac{1}{2} \times \frac{8}{1}\\\\ = \frac{8}{2}\\\\ = 4[/tex]

In short, the expression for choice D simplifies to 4 = 4/1 showing that is rational. Or you can use the shortcut that rational/rational = rational.

------------------

A number like [tex]\sqrt{13}[/tex] is NOT rational because the 13 is not a perfect square. There's no way to rewrite that square root as a ratio or fraction of integers. This allows us to rule out choice B. Choices E, F, and G are eliminated for similar reasoning.

Choice H is ruled out because circle areas involve pi = 3.14159... which is famously an irrational number. The proof of which is very lengthy to go over, but the short version is the decimal digits go on forever without a pattern. This is an informal way to check if we have an irrational number.

Choice I is only eliminated if and only if the side lengths of the square are rational, and also when the side lengths are whole numbers. Its not clear what your teacher's intentions here are, but I'll assume this is the case.

------------------

To summarize, we eliminated B, E, F, G, H, I

We're left with A, C, D, J as the final answers. They either can be written as fractions of integers, or already are fractions of integers.

Answer:

76

its going by 15's so you add 15

>> Question

1, 6, 13, 22, 33, 46, 61 what comes next??

>> Answer :

1, 6, 13, 22, 33, 46, 61, 78, 97, 118, 141, 166

= +5 , +7, +9 , +11, +13, +15, +17, +19, +21, +23, +25

Step-by-step explanation:

I Hope This Helps

square root of 28 is 2√7

√28 = √4 * √7 = 2√7

We are given with an equation and need to find it's solution set also we are given with a condition that m ≠ {0, 1} . So , let's start ;

So we are given with :

[tex]{:\implies \quad \sf \dfrac{6}{m}+2=\dfrac{m+3}{m-1}}[/tex]

First , we will simplify the given Equation and then we will solve it . So , now taking LCM in LHS ;

[tex]{:\implies \quad \sf \dfrac{6+2m}{m}=\dfrac{m+3}{m-1}}[/tex]

Now , Cross Multiplying ;

[tex]{:\implies \quad \sf (m-1)(6+2m)=m(m+3)}[/tex]

[tex]{:\implies \quad \sf m(6+2m)-1(6+2m)=m^{2}+3m}[/tex]

[tex]{:\implies \quad \sf 6m+2m^{2}-6-2m=m^{2}+3m}[/tex]

Now , transposing whole RHS to LHS and collecting like terms ;

[tex]{:\implies \quad \sf (2m^{2}-m^{2})+(6m-2m-3m)-6=0}[/tex]

[tex]{:\implies \quad \sf m^{2}+m-6=0}[/tex]

Now , we will solve this by splitting the Middle term ;

[tex]{:\implies \quad \sf m^{2}+3m-2m-6=0}[/tex]

[tex]{:\implies \quad \sf m(m+3)-2(m+3)=0}[/tex]

[tex]{:\implies \quad \sf (m+3)(m-2)=0}[/tex]

So , now either , m+3 = 0 or m-2 = 0 . On simplification we will get , m = 2 , -3. So m = {-3, 2}

Hence Option 1) {-3, 2} is correct

Answer:

see below

Step-by-step explanation:

1. x-9=-17-simplifies to a single solution-one solution

2.x+4=4+x-same thing on each side-infinite solutions

3. 0.4x=0.4x+2-same variable coefficient plus a number-no solutions

4. 5x=5x-3-same as above-no solutions

5. 5x=2-variable on one side, constant on another-one solution

6. x-5=x-5-same thing on each side-infinite solutions

7.3x=3x-same thing as above-infinite solutions

8.8x-10=8x-same coefficient for each variable plus a constant-no solutions

Answer:

One solution:

x + 9 = -17

5x = 10

No solution:

0.4x = 0.4x +2

5x = 5x - 3

8x - 10 = 8x

Infinite solutions:

x + 4 = 4 + x

x - 5 = x - 5

3x = 3x

Step-by-step explanation:

x + 9 = -17

  - 9     -9

x = -26 (one solution)

x + 4 = 4 + x

  - 4   - 4

x = x (infinite solutions)

0.4x = 0.4x +2

-0.4x  -0.4x

0 = 2 (no solution)

5x = 5x - 3

-5x  -5x

0 = -3 (no solution)

5x = 10

/5   /5

x = 5 (one solution)

x - 5 = x - 5

 + 5       + 5

x = x (infinite solutions)

3x = 3x (infinite solutions)

8x - 10 = 8x

    + 10  + 10

8x = 8x + 10

-8x   -8x

0 = 10 (no solution)

Hope this helps!

Answer: 8/7

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

Each input value can have only one output value for it to be a function. In other words, there should only be one y value for each x value. The only option that satisfies this is C.

Answer:

$324.33

Step-by-step explanation:

the answer is $324.33

The amount of interest capitalized is greater than the minimum amount that she could pay to prevent interest capitalization by; D: $324.33

We will use the formula: A = P(1 + r/n)^(nt)

Where:

A = final amount

P = initial principal ($9300)

r = interest rate (6.4% or 0.064)

n = number of times interest applied per time period

t = number of time period elapsed.

Thus;

9300(1 + 0.064/12)^(12*4) - 9300 = $2705.13

Also;

9300(0.064/12) * 4 * 12 = $2380.8

Answer = $2705.13 - $2380.8

Answer = $324.33

Read more about Principal amount at; https://brainly.com/question/25545513

Given :

⠀

To Find :

⠀

Solution :

⠀

Then, We know,

[tex] \qquad \sf \dashrightarrow \: 3x + 5x + 7x = 300 \: \: \: \: \: \: \: Perimeter_{(Triangle)}[/tex]

[tex]\qquad \sf \dashrightarrow \: 15x = 300 [/tex]

[tex]\qquad \sf \dashrightarrow \: x = \dfrac{300}{15} [/tex]

[tex]\qquad \bf\dashrightarrow \: x = 20 [/tex]

⠀

So, The sides of the triangle are :

[tex]\qquad \sf \dashrightarrow \: 3 \times 20 \: m = \bf60 \: m [/tex]

[tex]\qquad \sf \dashrightarrow \: 5 \times 20 \: m = \bf 100 \: m [/tex]

[tex]\qquad \sf \dashrightarrow \: 7 \times 20 \: m = \bf140 \: m [/tex]

⠀

Now, Using Heron's formula :

We have,

[tex]\qquad \sf \dashrightarrow \: s = ( {60 + 100 + 140}) \: m = 300 \: m [/tex]

[tex]\qquad \sf \dashrightarrow \: s = \dfrac {60 + 100 + 140}2 \: m = 150 \: m [/tex]

⠀

And the Area will be :

[tex]\qquad \sf \dashrightarrow \: \sqrt{150(150 - 60)(150 - 100)(150 - 140)} \: {m}^{2} [/tex]

[tex]\qquad \sf \dashrightarrow \: \sqrt{150 \times 90 \times 50 \times 10} \: \: {m}^{2} [/tex]

[tex] \qquad \sf \dashrightarrow \: 1500 \sqrt{3} \: {m}^{2} [/tex]

Answer:

2598m²

Step-by-step explanation:

Figure :

[tex]\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\qbezier(1, 0)(1,0)(3,3)\qbezier(5,0)(5,0)(3,3)\qbezier(5,0)(1,0)(1,0)\put(2.85,3.2){$\bf A$}\put(0.5,-0.3){$\bf C$}\put(5.2,-0.3){$\bf B$}\put(5,1){$\bf 3x $}\put(2.5, - .5){$\bf 7x $}\put(.5,1){$\bf 5x $}\put(4.5,4){$\bf not \: to \: scale \: $}\end{picture} [/tex]

Here we are given that the ratio of sides of a triangular plot is 3:5:7 and its perimeter is 300m . We are interested in finding the area of the rectangle . Firstly , let us take the given ratio's HCF be x , then we may write the ratio as ,

[tex]\longrightarrow 3x : 5x : 7x [/tex]

According to the question ,

[tex]\longrightarrow 3x + 5x + 7x = 300m \\ [/tex]

[tex]\longrightarrow 15x = 300m\\ [/tex]

[tex]\longrightarrow x =\dfrac{300m}{15}\\ [/tex]

[tex]\longrightarrow x = 20m [/tex]

Therefore , the sides will be ,

[tex]\longrightarrow 3x = 3(20m) = \red{60m}\\ [/tex]

[tex]\longrightarrow 5x =5(20m)= \red{100m}\\ [/tex]

[tex]\longrightarrow 7x =7(20m)=\red{140m}[/tex]

Now we may use Heron's Formula to find out the area of triangle as ,

Heron's Formula :-

Here ,

[tex]\longrightarrow s =\dfrac{300m}{2}=150m [/tex]

Therefore ,

[tex]\longrightarrow Area =\sqrt{ 150(150-60)(150-100)(150-140)}m^2\\ [/tex]

[tex]\longrightarrow Area =\sqrt{ 150 \times 90 \times 50 \times 10}m^2\\ [/tex]

[tex]\longrightarrow Area = \sqrt{ 50^2 \times 30^2\times 3}m^2\\[/tex]

[tex]\longrightarrow Area = 50\times 30 \times 1.732 m^2\\[/tex]

[tex]\longrightarrow\underline{\underline{ Area = 2598m^2}} [/tex]

And we are done !

=====================================================

Explanation:

The x coordinate of (-2,4) is -2

The y coordinate of (3,-2) is -2

Joining those two up gets us (-2,-2) as one of the answers

--------------

The x coordinate of (3,-2) is 3

The y coordinate of (-2,4) is 4

This leads to the other answer (3,4)

Check out the diagram below.

The answer points are marked in red.

Answer:

C. (–2, –2) and E. (3, 4)

Step-by-step explanation:

Answer:

a) Pythagoras' Theorem: a² + b² = c²

(where a and b are the legs, and c is the hypotenuse, of a right triangle)

b) Given:

Substituting these values into the equation and rearranging:

⇒ (x - 3)² + x² = 15²

⇒ x² - 6x + 9 + x² = 225

⇒ 2x² - 6x - 216 = 0

c) Solve  2x² - 6x - 216 = 0  by factorizing:

2x² - 6x - 216 = 0

⇒ x² - 3x - 108 = 0

⇒ x² - 12x + 9x - 108 = 0

⇒ x(x - 12) + 9(x - 12) = 0

⇒ (x - 12)(x + 9) = 0

⇒ x - 12 = 0 ⇒ x = 12

⇒ x + 9 = 0 ⇒ x = -9

As distance is positive, x = 12 only.

Therefore, the height of the pole is 12 ft.

So the distance from the hook to the base = 12 - 3 = 9 ft

We need x

Apply Pythagorean theorem

[tex]\\ \rm\Rrightarrow 15^2-x^2=(x-3)^2[/tex]

[tex]\\ \rm\Rrightarrow 225-x^2=x^2-6x+9[/tex]

[tex]\\ \rm\Rrightarrow 2x^2-6x-216=0[/tex]

[tex]\\ \rm\Rrightarrow x^2-3x-108=0[/tex]

[tex]\\ \rm\Rrightarrow (x+9)(x-12)=0[/tex]

[tex]\\ \rm\Rrightarrow x=-9,12[/tex]

Answer:

x^2-x^2=BC4

oh yeaa u know im right

Answer:

y - 10 = 110 ( x - 5)

explanation :

i)

[tex]\sf point \ slope \ form : \bold{y-y_{1}=m\left(x-x_{1}\right)}[/tex]

ii)

Answer:

[tex]y=110x-540[/tex]

Step-by-step explanation:

Point-slope form of a linear equation:  [tex]y-y_1=m(x-x_1)[/tex]

(where [tex]m[/tex] is the slope and [tex](x_1,y_1)[/tex] is a point on the line)

Given:

Substitute these values into the equation:

[tex]y-y_1=m(x-x_1)[/tex]

[tex]y-10=110(x-5)[/tex]

[tex]y-10=110x-550[/tex]

[tex]y=110x-540[/tex]

Answer:

12624 packets

Step-by-step explanation:

To solve this let the unknown number of packets be x.

        1 box ⇒ 48 packets

263 boxes ⇒ x

Now let us use cross multiplication to find the value of x.

1 × x = 48 × 263

1x     = 12624

Divide both sides by 1.

x = 12624