1) Suppose you place an object in front of a concave mirror. Which of the following statements must be true? (There could be more than one correct choice.) A) The image of the object will always be smaller than the object. B) No matter where you place the object, a real image of the object will be formed. C) The image of the object will always be inverted. D) If you position the object between the mirror and the focal point of the mirror, its image must be upright and virtual. E) No matter where you place the object, the image of the object will always be virtual and upright.

Answers

Answer 1

Answer:

C

Explanation:

because the concave mirror is always inverted

Answer 2

d )  when object is between focus and mirror , image formed is always virtual and erect

What is a Concave mirror ?

A concave mirror has a reflective surface that is curved inward and away from the light source .

a) Incorrect because image can be equal to , smaller then , and bigger then the object

b) and c)  Incorrect when object is between focus and mirror , image formed is virtual and erect

d ) Correct option  when object is between focus and mirror , image formed is always virtual and erect

e) Incorrect except one case in all other cases nature is real and inverted

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Related Questions

What is the low end of the range of surface temperature for blue white stars

Answers

B 10,000 - 30,000 K Blue-white stars

A 7,500 - 10,000 K White stars

F 6,000 - 7,500 K Yellow-white stars

G 5,000 - 6,000 K Yellow stars (like the Sun)

The lowest temperature stars are red while the hottest stars are blue. Astronomers are able to measure the temperatures of the surfaces of stars by comparing their spectra to the spectrum of a black body.

Assume ideal behavior. How many moles of are needed to fill a 2000L weather balloon at 210K and 1atm pressure? Round your answer to the nearest mole (use R = 0.082057 L atm mol-1K-1)

Answers

Considering the ideal gas law, 116.06 moles of are needed to fill a 2000 L weather balloon at 210 K and 1 atm pressure.

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P×V = n×R×T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas. The universal constant of ideal gases R has the same value for all gaseous substances.

In this case, you know:

P= 1 atmV=2000 Ln= ?R= 0.082057 [tex]\frac{atmL}{molK}[/tex]T= 210 K

Replacing in the ideal gas law:

1 atm× 2000 L = n× 0.082057 [tex]\frac{atmL}{molK}[/tex]× 210 K

Solving:

[tex]n=\frac{1 atmx 2000 L}{0.082057 \frac{atmL}{molK}x 210 K}[/tex]

n=116.06 moles

Finally, 116.06 moles of are needed to fill a 2000 L weather balloon at 210 K and 1 atm pressure.

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What are the rest of the blanks?

Answers

Not quite, just wanted the points lol

what equation do you use to calculate force from work to distance

Answers

Answer:

Work can be calculated with this equation: Work = Force x Distance. The SI unit for work is the Newton meter (N m). One joule equals the amount of work that is done when 1 N of force moves an object over a distance of 1 m.

Explanation:

tree sloths are the slowest mammals on earth an typical tree sloth moves with maximum speed of 0.075 m/s. how long would it take a sloth moving at this speed to travel 2.0m

Answers

The time taken for the tree sloths to travel the given distance is 26.31 s.

The given parameters:Maximum speed of the tree sloths, v = 0.075 m/sDistance traveled by the tree sloths, d = 2.0 m

The time taken for the tree sloths to travel the given distance is calculated as follows;

distance = speed x time

[tex]time = \frac{distance }{speed} \\\\time = \frac{2.0}{0.075} \\\\time = 26.31 \ s[/tex]

Thus, the time taken for the tree sloths to travel the given distance is 26.31 s.

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Stacey runs around a 400 meter track 2 times in 5 minutes. How does her displacement differ from her distance? *

Answers

Answer:

Distance is 800 m and Displacement is 0 m

Explanation:

Total Distance

= 400(2)

= 800 m

Total Displacement

= 0 m since she returns to the same spot

what's the difference between a lunar eclipse and a solar eclipse?

Answers

Answer:

passes

Explanation:

Traditionally, eclipses are divided into two major types: solar and lunar. Solar eclipses occur when the Moon passes between Earth and the Sun, leaving a moving region of shadow on Earth's surface. Lunar eclipses occur when Earth passes between the Sun and the Moon, casting a shadow on the Moon.

The instant before a batter hits a 0.14-kilogram baseball, the velocity of the ball is 45 meters per second west. The instant after the batter hits the ball, the ball's velocity is 35 meters per second east. The bat and ball are in contact for 1.0 x 10-2 second.
1. find the magnitude and direction of the average acceleration of the baseball while it is in contact with the bat.
2. calculate the magnitude of the average force the Bat exerts on the ball while they are in contact. ​

Answers

(1) The magnitude and direction of the average acceleration of the baseball while it is in contact with the bat is 8,000 m/s² east.

(2) The magnitude of the average force the Bat exerts on the ball while they are in contact is 1,120 N.

The given parameters:

Mass of the baseball, m = 0.14 kgInitial velocity of the baseball, u = 45 m/s west (negative direction)Final velocity of the baseball, v = 35 m/s east (positive direction)Time of contact, t = 0.01 s

The magnitude and direction of the average acceleration of the baseball while it is in contact with the bat is calculated as follows:

[tex]a = \frac{v- u}{t} \\\\a = \frac{35 - (-45)}{0.01} \\\\a = \frac{80}{0.01} \\\\a = 8,000 \ m/s^2[/tex]

The magnitude of the average force the Bat exerts on the ball while they are in contact is calculated as follows;

[tex]F = ma\\\\F = 0.14 \times 8,000\\\\F = 1,120 \ N[/tex]

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stella is driving down a steep hill. she should keep her car __________ to help _________.

Answers

Answer:

Stella is driving down a steep hill. She should keep her car in a lower gear to help slow her vehicle.

Explanation:

Which of the following industries is the largest producer of primary air pollutants in the United States?

Answers

The largest producer of primary air pollution in the United States is what? electricity producing plants.

Answer:

electricity production

Explanation:

. a. Calculate the work done while lifting 300 kg of wate through a vertical height of 6 m. (Assume g = 10 m a =​

Answers

Answer:

potential energy = mgh = 300 × 10 × 6m = 18000 joule or 18 kilo joule.

Explanation:

a 10 mh inductor is connected in series with a 10 ohm resistor, a switch and a 6 v battery. what is the time constant of the circuit

Answers

Answer:

The inductive time  constant is just T = L / R

T = 10E-3 henry/ 10 ohm = 10E-2 sec = .1 sec  

(.01 / 10 = .1)

Liquids and solids are:
a- compressible and expandable.
b- incompressible and non-expandable.
c- incompressible and expandable.

Answers

Answer:

incompressible and expandable

The answer is b incompressible and expandable

which of the following are features of the nucleus of an atom
finding evidence to support or dispove is how science advanes

Answers

We r made of atom so v can’t touch anything hehe I just joking

General kinematics problem.

"Anna is returning from vacation driving down the Sunshine Highway. She travels for a stretch (SA) at a speed of 110 km/h. Then, due to an increase in traffic, Anna is forced to reduce her speed by travelling the second part of the journey (SB) at 60 km/h. The total distance and duration of the trip are 350 km and 4.0 hours respectively.
-> Calculate the time intervals needed to travel SA and SB
-> Calculate the distances covered in the two sections SA and SB".

The results I should get by doing the exercise are in the attached picture.

If you could explain the various steps in the problem you would be doing me a huge favor. Thanks!​

Answers

Explanation:

What we know:

Sa + Sb = 350 km

Ta + Tb = 4h

S = Vt

With these equations above we can write a system of equations and find Tb, as you see in the picture(s).

After having Tb you can easily find Ta and then Sa and Sb. Hopefully it was clear.

A wave has a frequency of 2700 Hz and λ of 6m. Calculate the speed of the wave.pls help

Answers

Answer:

16,200 m/s

Explanation:

The speed of the wave given only it's frequency and wavelength can be found by using the formula

[tex]c = f \times \lambda[/tex]

where

c is the velocity of the wave in m/s

[tex] \lambda[/tex] is the wavelength in m

f is the frequency in Hz

From the question

c = 2700 × 6 = 16,200

We have the final answer as

16,200 m/s

Hope this helps you

the impulse-momentum relationship is a direct result of

Answers

Newton's second law.

__________________

o0o0o0o0o0o0o0o0o0

The impulse-momentum relationship is a direct result of Newton's second law of motion.

What is the impulse-momentum?

The impulse-momentum theorem states that the impulse applied to an object is equal to the change in its momentum. It proves that the change in momentum of an object depends not only on the amount of force applied but also on the duration of force applied.

Newton's second law states that the force acting on an object is equal to the rate of change of its momentum.

This means that a force applied to an object will cause a change in its momentum. The impulse-momentum relationship describes the relationship between the force applied to an object and the resulting change in its momentum.

The impulse-momentum relationship states that the impulse acting on an object is equal to the change in its momentum.

Impulse is defined as the force applied to an object over a period of time, while momentum is the product of an object's mass and velocity. Therefore, the impulse-momentum relationship can be expressed as:

Impulse = Change in momentum

This relationship is important in understanding the behavior of objects in motion, particularly in collisions or other situations where forces act over a period of time.

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The following data were collected during a short race between two friends. Velocity (m/s) 0 0.5 1 1.5 2 2 4 6 2 0 Time (s) 0 2 4 6 8 10 12 14 16 18 a) Describe the different sections of the graph. b) Determine the acceleration over the first eight seconds. c) Determine the maximum acceleration. d) Using the graph calculate the displacement: i) over the first eight seconds ii) the total race. e) Find the maximum velocity reached by the runner.

Answers

The characteristics of the kinematics allow to find the results for the questions about the movement of the body are:

a)  we have four sections;

0 to 8 s The body is accelerating. 8 to 10 s The body goes at a constant speed, the acceleration is zero. 10 to 14 Body accelerating. 14 to 18 Body slowing down.

b)  The acceleration is the first 8 s is:  a = 0.25 m / s²

c) The maximum acceleration is:    a = 1 m / s²

d) The displacement   is:  i) d₁ =  8m,     ii)  [tex]d_{total}[/tex]= 16 m

e) maximum speed  is:      v = 6 m / s

Kinematics studies the movement of bodies by finding relationships between the position, speed and acceleration of bodies.

        v = v₀ + a t

        y = v₀ t + ½ a t²

where v and v₀ is the current and initial velocity, respectively, a is the acceleration and t is time.

In many circumstances graphs are made for their analysis, in a graph of speed versus time when we have a horizontal line the speed is constant, the acceleration is zero and in the case of a slope there is an acceleration, we have two cases:

Positive slope the body is accelerating and the speed is increasing. Negative slope the body is stopping, the speed decreases.

Let's answer the different questions about the system.

a) in the attached we have a graph of the velocity versus time, each section corresponds to a change in the slope of the graph, we have four sections;

0 to 8 s The body is accelerating. 8 to 10 s The body goes at a constant speed, the acceleration is zero. 10 to 14 Body accelerating. 14 to 18 Body slowing down.

b) The acceleration is the first 8 s

          v = v₀ + a t

          [tex]a = \frac{v-v_o}{\Delta t}[/tex]  

          [tex]a = \frac{2-0}{8-0}[/tex]  

          a = 0.25 m / s²

c) The maximum acceleration is when the slope is maximum.

          [tex]a = \frac{6-2}{ 14-10}[/tex]  

          a = 1 m / s²

Therefore the acceleration is maximum in the section between 10 and 14 s

d) The total displacement is the sum of the displacements of each section.

         [tex]d_{total } = d_1 +d_2 + d_3 +d_4[/tex]  

We look for every displacement.

       d₁ = v₀ + ½ a₁ Δt²

       d₁ = 0 + ½ 0.25 8²

       d₁ = 8 m

In the second section the velocity is constant

         d₂ = v₂ Δt₂

         d₂ = 2 (10-8)

         d₂ = 4 m

The third section.

    d₃ = v₀ + ½ a t²

    d₃ = 2 + ½ 1 (14-10) ²

    d₃ = 10 m

The distance of the fourth section.

       

we look for acceleration

          a₄ = [tex]\frac{v-v_o}{\Delta t}[/tex]  

          a₄ = [tex]\frac{0-6}{18-14}[/tex]  

          a₄ = -1.5 m / s²

     

          d₄ = 6 + ½ (-1.5) (1814) ²

          d₄ = -6 m

The total displacement is;

          [tex]d_{total}[/tex] = 8 + 4 + 10 -6

          [tex]d_{total}[/tex] = 16 m

e) The maximum speed is the highest point in the graph of speed versus time that in the attachment we can see corresponds to

          v = 6 m / s

In conclusion using the characteristics of kinematics we can find the results for the questions about the motion of bodies are:

  a)  we have four sections;

0 to 8 s The body is accelerating. 8 to 10 s The body goes at a constant speed, the acceleration is zero. 10 to 14 Body accelerating. 14 to 18 Body slowing down.

b)  The acceleration is the first 8 s is:  a = 0.25 m / s²

c) The maximum acceleration is:    a = 1 m / s²

d) The displacement   is:  i) d₁ =  8m,     ii)  [tex]d_{total}[/tex]= 16 m

e) maximum speed  is:      v = 6 m / s

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A 600g toy train completes 10 laps of its circular track in 1 min 20s. If the radius of the track is 1.2 m, Find the speed of the train in m/s.

Answers

Answer:

0.236  m/s² (rounded)

Explanation:

according to newton's third law, of a sledgehammer hits a wall with a force of 1000 n, how much force does the wall hit the sledgehammer? a - 1000 n b 1000 n c 0 n d 500 n

Answers

The correct option is A: the force exerted on the wall by the sledgehammer is  - 1000 N

Newton's third law

Newton's third law of motion states that for every action or force, there is an equal but oppositely directed force.

Application of the newton's third law

Force with which the sledgehammer hits the wall = 1000 N

From the Newton's third law, an equal but oppositely directed force is exerted on the sledgehammer by the wall.

Thus, the force exerted by the sledgehammer on the wall = -1000 N

The negative sign indicates that the force acts in a direction opposite to that of the sledgehammer.

Thus, the correct option is A: the force exerted on the wall by the sledgehammer is  - 1000 N

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nitrogen dioxide is a major component of smog which type of chemical reaction creates this product?
a. synthesis reaction
b. replacement reactions
c. combustion reactions
d. decomposition reaction

Answers

Answer:

A.synrhesis reaction

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How is the independent variable affected by the dependent variable

Answers

Answer:

A dependent variable is a variable that is tested in an experiment. An independent variable is that can be modified. Depending on what you are testing, the dependent variable will change accordingly to the dependent variable.

- I'm reading this back and it doesn't make much sense, if you want me to reword this I can

Connor rode an inner tube down a river. For 4.6 minutes, he moved downriver at 15 meters per minute. During this time, how far did he move?

Answers

Answer:

2 miles

Explanation:

Stewart (70 Kg) is attracted to Ms. Little (60 Kg) who sits 2 m away. What is the gravitational attraction between them? G=6.67×10^-11 (-11 is an exponent)​

Answers

Happy Holidays!

We can use the following equation to solve for the gravitational force:

[tex]\large\boxed{F_g = G\frac{m_1m_2}{r^2}}[/tex]

Fg = force due to gravity (N)

G = Gravitational constant

m1,m2 = masses of the objects (kg)

r = distance between the objects (m)

Plug in the given values into the equation:

[tex]F_g = (6.67*10^{-11})\frac{(70)(60)}{(2)^2}} = \boxed{7.0 * 10^{-8}N}[/tex]

A 4000kg truck has a head-on inelastic collision with a 2500kg truck.

A. calculate the total momentum of the trucks before they collide.


B. Calculate their speed just after they collide.

Answers

Answer:it could be B

Explanation:

im not sure

2. A nutty professor leaves a history classroom and walks 10. meters north to a drinking fountain. Then, in a daze, she turns and walks 30. meters south to an art classroom. (draw vectors to scale to show your work)
(a) What is the professor’s total displacement from the classroom to the art classroom?
(b) What was the total distance she traveled?

Answers

[tex]\vec{N}=10m[/tex][tex]\vec{S}=30m[/tex]

Total displacement:-

[tex]\\ \sf\Rrightarrow 10-30=20m[/tex]

Total distance

[tex]\\ \sf\Rrightarrow 10+30=40m[/tex]

The distance-time graph for a vehicle standing on a road side will be

Answers

Answer:

hi

Explanation:

could you please upload ur image

What do you feel when you receive your homework? ​

Answers

Very bad, it’s extremely draining I dread it a lot maybe it’s just cause I have a lot

The feeling can either be positive or negative.

How one feels depends on number of factors

A positive feeling can occur when one performs very well in the given home. Also, a positive feeling can come from a high level of satisfaction in the homework. When you complete your homework on time using the recommended steps, you will be sure to do well on the homework.

In other hand, a negative feeling may result from poor performance in the homework. In ability to complete the homework or missing some steps in the homework can increase your level of trepidation even before seeing your score.

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Annie comes to a sudden stop to avoid hitting a deer crossing the road at night. As she hits the breaks, her speed drops from 12 m/s to zero in 1.5 seconds.(p1) How far did she travel during that time? (p2)What was her average acceleration?

Distance(p1)
9 m
8 m
10 m
13.5 m

Acceleration(p2)
6 m/s2
8 m/s2
12 m/s2
16 m/s2

Answers

Answer:

1. around 22m

Explanation:

Annie traveled 9 meters during that time. Her average acceleration was -8 m/s².

Annie's initial speed was 12 m/s.

Her final speed was 0 m/s.

The time it took her to stop was 1.5 seconds.

Therefore, the distance she traveled during that time is:

distance = (initial speed + final speed)/2 * time

= (12 m/s + 0 m/s)/2 * 1.5 seconds

= 9 meters

Annie's average acceleration is calculated by dividing her change in velocity by time it took for that change to occur.

In this case, her change in velocity is from 12 m/s to 0 m/s, which is a decrease of 12 m/s.

The time it took for this change to occur is 1.5 seconds.

Therefore, Annie's average acceleration is:

acceleration = change in velocity / time

= -12 m/s / 1.5 seconds

= -8 m/s²

The negative sign indicates that Annie was slowing down.

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please help me with this​

Answers

Answer:

>400N is needed to balance that lever

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